Answer:
Option: A(0.585)
Step-by-step explanation:
After arranging our data in ascending order we get that:
5.16 5.16 5.25 5.33 5.33 5.5 5.66 5.66 5.75 5.75 6 6 6.25
Quartiles divide a rank-ordered data set into four equal parts. The values that divide each part are called the first, second, and third quartiles; and they are denoted by Q1, Q2, and Q3, respectively.
The interquartile range is equal to Q3-Q1.
So, the Median()of data is given by: 5.66
also the lower half is:
5.16 5.16 5.25 5.33 5.33 5.5
Hence, the middle value or median of this lower half of this data lie between 5.25 and 5.33 which is 5.29.
Hence, =5.29
Similarly the upper half is:
5.66 5.75 5.75 6 6 6.25
Hence, the middle value or median of this upper half of this data lie between 5.75 and 6 which is 5.875
Hence, =5.875
Hence, the interquartile range=
Hence, option A is correct.
Answer: Option: A(0.585)
Step-by-step explanation:
The total suitcases in all three cargo bins, when added up (94 + 214 + 103), equals 411. Consequently, there will be 411 suitcases in the cargo area of the 747 airplane.
Total suitcase calculation involves simply adding up the numbers from all three cargo bins. The first bin contains
94 suitcases, the second bin 214 suitcases, and the third contains 103 suitcases. Adding all these up gives a total suitcase number as follows: 94 + 214 + 103 = 411. Therefore, if all these cargo bins are loaded onto the 747 airplane, here will be 411 suitcases in the cargo area.
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2. (x +4) • 9
3. y + 7 + 8 – 7(x -8)
4. (4 – 5) + x(6 – 8)
5. y(4 – 8) – 3y
6. x + 8y – 16x(1- 3)
7. 82 – x(4 – 8) + √25
8. 53 – 4(y – 7y) - √81
9. x2 – 4 – 5y - √36 • √144 + 23(x – 5x)
Directions: For problems 10-14 solve the following expressions by substituting these values: x = 2, y = 3.
10. y(4 – 8) – 3y
11. x + 8y – 16x(1- 3)
12. 82 – x(4 – 8) + √25
13. 53 – 4(y – 7y) - √81
14. x2 – 4 – 5y - √36 • √144 + 23(x –5x)
Answer:
Step-by-step explanation:hutcryketkdrfyhgjbnm