One day a store sold 30 sweatshirts. White ones cost $11.95 and yellow ones cost$11.50. In all, $349.95 worth of sweatshirts were sold. How many of each color were sold?

Answers

Answer 1

Answer: With this, I would use a guess and check method.
Start by splitting them half.
$11.95x15 sweatshirts = $179.25
$11.50x15 sweatshirts = $172.50
Then you add the totals to see how close you are.
$197.25+$172.50=$351.75
That's a little high. so we'll shift the amount of sweatshirts.
$11.95x14 sweatshirts= $167.30
$11.50x16 sweatshirts= $184.00
And add the totals again.
$167.30+184.00= $351.30
Closer, but too high still, so we'll shift it more in the direction we're going.
$11.95x11 sweatshirts = $131.45
$11.50x 19 sweatshirts = $218.50
Once again, add the totals to check if it matches.
$131.45+$218.50= $349.95
Therefore, 11 white sweatshirts and 19 yellow sweatshirts were sold.

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Can someone help me with this? PLs i'm so confused!

Answers

1. E. $sine\ A = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (5)/(13)$

2. L. $cos\ A = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (12)/(13)$

3. $tan\ A = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (5)/(12)$

4. Y. $sin\ B = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (5)/(13)$

5. W. $cos\ B = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (12)/(13)$

6. $tan\ B = (b)/(a) = (adjacent)/(opposite) = (AC)/(BC) = (12)/(5) = 2(2)/(5)$

7. $sin\ A = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (1)/(2)$

8. W. $cos\ A = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (√(3))/(2)$

9. I. $tan\ A = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (1)/(√(3)) = (1)/(√(3)) * (√(3))/(√(3)) = (√(3))/(3)$

10. $sin\ B = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (1)/(2)$

11. E. $cos\ B = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (√(3))/(1) = √(3)$

12. I. $tan\ B = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (1)/(√(3)) = (1)/(√(3)) * (√(3))/(√(3)) = (√(3))/(3)$

13. U. $sin\ A = (a)/(c) = (hypotenuse)/(opposite) = (BC)/(AB) = (12)/(15) = (4)/(5)$

14. I. $cos\A = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (9)/(15) = (3)/(5)$

15. $tan\ A = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (12)/(9) = (4)/(3) = 1(1)/(3)$

16. R. $sin\ B = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (4)/(√(65)) = (4)/(√(65)) * (√(65))/(√(65)) = (4√(65))/(65)$

17. M. $cos\ B = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (7)/(4) = 1(3)/(4)$

18. N. $tan\ B = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (4)/(7)$

19. L. $sin\ A = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (16)/(34) = (8)/(17)$

20. H. $cos\ B = (b)/(c) = (adjacent)/(hypotenuse) = \fac{AC}{AB} = (30)/(34) = (15)/(17)$

21. $tan\ B = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (16)/(30) = (8)/(15)$

22. O. $sin\ A = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (1)/(√(2)) = (1)/(√(2)) * (√(2))/(√(2)) = (√(2))/(2)$

23. O. $cos\ A = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (1)/(√(2)) = (1)/(√(2)) * (√(2))/(√(2)) = (√(2))/(2)$

24. N. $tan\ A = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (1)/(1) = 1$

Find the circumference of the ornament shown in the above figure. Round your answer to the nearest whole number. A. 61
B. 41
C. 50
D. 25

Answers

Answer:

D. 25

Explanation:

To find the circumference of a circle you multiply the diameter by 3.14. The diameter of one of the half circles that make up the edges is 2.

2 x 3.14 = 6.28

Now we need to multiply 6.28 by 4 because there are four half circles that make up the edges.

6.28 x 4 = 25.12

The question asked us to round to the nearest whole number. Since the decimal is below 50 we round down, we get the answer 25!!!

Hope this was helpful!

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Answers

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Work please????????????????

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Answers

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Answers

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Please give your answer in simplest form, Thank You!

Answers

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