The table of values shows the number of touchdown passes that a quarterback threw in each of his first five football games of the season.Game vs. Touchdown Passes
Game
Touchdown passes
1
3
2
1
3
3
4
2
5
3

Which would be a point on the scatterplot that represents touchdown passes based on these games played?
(1, 2)
(2, 4)
(3, 1)
(5, 3)

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

If x is the game number, and y is the amount of touchdown passes for that specific game number, then (5,3) represents the idea that the quarter back threw y = 3 touchdown passes for game number x = 5

So the answer is choice D. This is the only ordered pair that comes from the given table. Something like (2,4) isn't true because the quarterback threw 1 touchdown pass (not 4) in game two.

Answer 2

Answer:

Answer:D

Step-by-step explanation:

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Answers

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Find the average of 72,95,100,85,and 88

Answers

Answer:

Step-by-step explanation:

72 + 95 + 100 + 85 + 88=440

440/5=88

M(8, 7) is the midpoint of RS. The coordinates of S are (9, 5). What are the coordinates of R?

Answers

Answer:

M(Mx, My), R(Rx, Ry), S(Sx, Sy)

M is midpoint of RS

=> Rx + Sx = 2Mx => Rx = 2Mx - Sx = 2 x 8 - 9 = 7

=> Ry + Sy = 2My => Ry = 2My - Sy = 2 x 7 - 5 = 9

=> R(7, 9)

Hope this helps!

Answer:

(7,9)

Step-by-step explanation:

Let R:(x,y)

(x+9)/2, (y+5)/2 = 8 ,7

x + 9 = 16

x = 7

y + 5 = 14

y = 9

R: (7,9)

I need help please help me

Answers

Is there anwer choices

Suppose you have 18 objects (10 of type A, 5 of type B, and 3 of type C). Objects of type A are indistinguishable from each other; objects of type B are indistinguishable from each other; and objects of type C are indistinguishable from each other. In how many ways can you Pick 5 of the 18 objects (order does not matter)

Answers

Answer:

$\binom{18}{5}= 8568$

Step-by-step explanation:

Note that we have in total 18 items. Even though we are given information regarding the amounts of items per type, the general question asks the total number of ways in which you can pick 5 out of the 18 objects, without any restriction on the type of chosen items. Therefore, the information regarding the type is unnecessary to solve the problem.

Recall that given n elements, the different ways of choosing k elements out of n is given by the binomial coefficient $\binom{n}{k})$ .

Therefore, in this case the total number of ways is just $\binom{18}{5}=8568$

Answer:

Given:

Number of objects: n = 18

Type A objects: 10

Type B objects: 5

Type C objects: 3

To find:

In how many ways can you Pick 5 of the 18 objects (order does not matter)

Step-by-step explanation:

When the order does not matter we use Combination.

Formula to calculate combination:

C(n,r) = n! / r! ( n - r )!

n = 18

r = 5

Putting the values:

C(n,r)

= C(18,5)

= 18! / 5! ( 18 - 5 )!

= 18! / 5! ( 13 )!

= ( 18 * 17 * 16 * 15 * 14 * 13 * 12 * 11 * 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 ) / ( 5 * 4 * 3 * 2 * 1 ) * (13 * 12 * 11 * 10 *9* 8 * 7 *6 * 5 * 4 * 3 * 2 *1 )

Cancel 13!

= (18 * 17 * 16 * 15 * 14 ) / ( 5 * 4 * 3 * 2 * 1 )

= 1028160 / 120

= 8568

So you can pick 5 of the 18 objects in 8568 ways.

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