Answer: 0.15
Step-by-step explanation:
As per given , the probability that customers who bought a new vehicle bought an SUV : P(SUV) = 0.20
The probability that customer bought a vehicle that was an SUV and in black color : P(SUV and black) =0.03
Now by suing conditional probability formula,
If we have given that a customer bought an SUV, then the probability that it was black will be :
Hence, the required probability is 0.15.
The probability that a customer who bought an SUV also bought a black SUV is 0.006, or 0.6% (expressed as a percentage).
To find the probability that a customer who bought an SUV also bought a black SUV, you can use conditional probability.
Let's define the following events:
A: A customer bought an SUV.
B: A customer bought a black SUV.
You are given that P(B|A) is the probability that a customer who bought an SUV also bought a black SUV, which is 3% or 0.03.
You want to find P(B|A), the probability that a customer who bought an SUV also bought a black SUV. You can use the following formula for conditional probability:
P(B|A) = (P(A and B)) / P(A)
Here, P(A and B) is the probability that a customer bought both an SUV and a black SUV, and P(A) is the probability that a customer bought an SUV.
You know that P(B|A) = 0.03 and P(A) = 0.20.
Now, you need to find P(A and B), the probability that a customer bought both an SUV and a black SUV. You can rearrange the formula:
P(A and B) = P(B|A) * P(A)
P(A and B) = 0.03 * 0.20
P(A and B) = 0.006
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The probability that the sample mean would differ from the population mean by more than 1.8 millimeters is approximately 0.0668.
A standard deviation (σ) is a measure of the distribution of the data in reference to the mean.
The standard deviation of the population is millimeters. The standard error of the sample mean is then
millimeters.
The probability that the sample mean would differ from the population mean by more than 1.8 millimeters is the probability that it falls outside of the interval . We can use the standard normal distribution to approximate this probability.
First, we need to convert the difference between the sample mean and the population means to standard units.
The difference of 1.8 millimeters is :
standard units.
Then, we can use the standard normal distribution to find the probability that the sample mean falls outside of this interval.
This probability is equal to ,
where is the standard normal cumulative distribution function.
Therefore, the required probability is approximately 0.0668.
Learn more about the standard deviation here:
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9x – 6y = 15,
3x – 2y = 5
This system of equation has an infinite number of solutions.
You can tell this because multiplying one equation by a constant gives you exactly the other equation. You can multiply the second equation by 3.
9x - 6y = 15
5(3x - 2y = 5) = 9x - 6y = 15
When this happens, you can assume that there are an infinite number of solutions.
Answer:
1) The equations in the system are equivalent equations.
2) There is no solution to the system of equations.
3) The system of equations has one solution at (3, 2).
4) The system of equations has one solution at (5, 5).
Answer = 1
Step-by-step explanation:
I just did the assignment
Answer:
−2x^2+6x
Explanation:
You just have to distribute meaning you have to multiply -2x to the equation.
fiction 12
nonfiction 18
thriller 24
romance 6
Which genre of book does Danielle likely have the most of?
Answer:
Thriller, 24
Step-by-step explanation:
It has the most books shown.
Answer:
iM nOT toO suRE BUT I THINK ITS THRILLER BECAUSE IT HAS 24 AND 60/24=2.5
Step-by-step explanation:
Here, we need to write the length of the insect in scientific notation.
The given length of the insect is 0.0052 meter
Now, to write 0.0052 meter in scientific notation we need to follow this:
Scientific notation always start with non-zero digit followed by a decimal point.
Since in our number the decimal is needed to be moved three places to the right to get the first non-zero digit.
The exponent of the 10 is .
Therefore, our number 0.0052 can be written as:
Hence, the require scientific notation is .