MATHEMATICS COLLEGE

Mass and weight math

Answers

Answer 1

Answer:

Answer: There is 1,000 milligrams in 1 gram.

Answer 2

Answer:

Answer:

1000mg

Step-by-step explanation:

to be honest that's the obvious answer

and in advance

1kg=1000000mg

1kg=1000g

1g=1000g

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Use the steps to determine the exact value of sin(−135)°.

Identify the reference angle, θ.

θ =
°

Answers

To solve for sin(-135), the reference angle will be obtained as follow:
sin(-135)
=-sin(135)
=-sin(180-135)
=-sin 45
hence
the reference angle θ=45°

Answer:

The reference angle will be ${\theta}=45^(\circ)$

Step-by-step explanation:

To solve for $sin(-135)$ , the reference angle can be obtained as follows:

= $sin(-135)$

= $- sin(135)$ (Because $sin(-{\theta})=-sin{\theta}$ )

Thus, the above equation can be written as:

= $-sin(180-135)$

= $-sin45$

Hence, the reference angle will be ${\theta}=45^(\circ)$

What is the solution of the system

Answers

$x - 2y = 4 \n x = 2y + 4 \n 3(2y + 4) + y = 5 \n 6y + 12 + y = 5 \n 7y = - 7 \n y = - 1$
x = 2(-1) + 4
x = 2

From a group of 12 students, we want to select a random sample of 4 students to serve on a university committee. How many different random samples of 4 students can be selected?

Answers

Answer:

Step-by-step explanation:

Each side of a square is increasing at a rate of 4 cm/s. At what rate (in cm2/s) is the area of the square increasing when the area of the square is 25 cm2

Answers

Answer:

The area of the square is increasing at a rate of 40 square centimeters per second.

Step-by-step explanation:

The area of the square ( $A$ ), in square centimeters, is represented by the following function:

$A = l^(2)$ (1)

Where $l$ is the side length, in centimeters.

Then, we derive (1) in time to calculate the rate of change of the area of the square ( $(dA)/(dt)$ ), in square centimeters per second:

$(dA)/(dt) = 2\cdot l \cdot (dl)/(dt)$

$(dA)/(dt) = 2\cdot √(A)\cdot (dl)/(dt)$ (2)

Where $(dl)/(dt)$ is the rate of change of the side length, in centimeters per second.

If we know that $A = 25\,cm^(2)$ and $(dl)/(dt) = 4\,(cm)/(s)$ , then the rate of change of the area of the square is:

$(dA)/(dt) = 2\cdot \sqrt{25\,cm^(2)}\cdot \left(4\,(cm)/(s) \right)$

$(dA)/(dt) = 40\,(cm^(2))/(s)$

The area of the square is increasing at a rate of 40 square centimeters per second.

2) Mr. Riley dove off a cliff that was 30 feet above the surface of the water and descended a total of 100 feet. Which of the equations below can be used to determine his elevation at the bottom of his dive?a) 30 + 100
b) 30-100
C) 30 + (-100)
d) Both b and c

Answers

Answer:

Step-by-step explanation:

Mr.Riley was 30 feet above the water, which means he is at +30 above sea level. If he descends 100 feet, that means he goes 100 feet lower then that. 30 - 100 is equal to -70. He is 70 feet under water after he dived. You do not need to know the answer, but it helps to visualize the problem you have, therefore, finding the answer

Alice is saving to buy a house and currently has $2,000 in her savings account. She's planning to contribute $150 to the account each month. Identify the function that describes the relationship between the number of months that pass (n) and the balance of her savings account, f(n).