MATHEMATICS COLLEGE

28Here are two rectangles.
Р
e
B
D
S
R
QR = 20 cm
BC = PQ
The perimeter of ABCD is 52 cm
The area of PQRS is 90 cm?
Find the length of AB.
28 Here are two rectangles. Р e B D S - 1

Answers

Answer 1
Answer:

9514 1404 393

Answer:

  21.5 cm

Step-by-step explanation:

Consider rectangle PQRS. Its area is ...

  A = LW

  90 cm² = PQ×QR = PQ×(20 cm)

  (90 cm²)/(20 cm) = PQ = 4.5 cm . . . . . . BC has this value, too

__

Consider the perimeter of ABCD. It is given by ...

  P = 2(L +W)

  52 cm = 2(AB +BC) . . . . substitute known value for P

  26 cm = AB +4.5 cm . . . . use known value for BC, divide by 2

  21.5 cm = AB

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Marco paid $42.40 for 6.4 Gallons of gas. What is the price of 1 gallon of gas? Group of answer choices

Answers

Answer:

6.63

Step-by-step explanation:

An angelfish was 1 1/2 inches long when it was bought. Now it is 2 1/3 inches long.a. How much has the angelfish grown?

b. An inch is 1/12 of a foot. How much has the angelfish grown in feet?

40 points!

Answers

A)

Earlier, The length of the angelfish  = 1 (1)/(2) inches

Now, the length of angelfish = 2 (1)/(3) inches

We have to determine the grown length of angelfish

=  2 (1)/(3) -  1 (1)/(2)

= (7)/(3)- (3)/(2)

LCM of '2' and '3' is '6',

= (14-9)/(6)

= (5)/(6) inch

Therefore, the angelfish has grown by (5)/(6) inch.

B)

We have to determine the increased length of angelfish in feet.

Since 1 inch = (1)/(12) foot

So, (5)/(6) inch = (5)/(6) * (1)/(12) = (5)/(72)

= 0.069 foot.
The answer for A is 5/6 inches.
2 1/3 - 1 1/2 = 2 2/6 - 1 3/6

= 2 + 6 / 6 - 1 3/6 = 8/6 - 1 3/6 = 5/6

The answer for B is 0.0694 feet.
Greetings!

For the function g(x)=5x2+4x−5, find g(−5)

Answers

Answer:

100

Step-by-step explanation:

g(x)=5x^2+4x−5

Let x = -5

g(x)=5 ( -5)^2+4(-5)−5

     = 5*25 - 20 -5

     =125 - 25

    = 100

A culture started with 5000 bacteria after three hours it grew 6500 bacteria predict how many bacteria will be present after 13 hours round your answer to the nearest whole number

Answers

Answer:

15595 bacteria will be present after 13 hours.

Step-by-step explanation:

Continuous population growth:

The continuous population growth model, for the population after t hours, is given by:

P(t) = P(0)e^(rt)

In which P(0) is the initial population and r is the growth rate.

Started with 5000 bacteria

This means that P(0) = 5000

So

P(t) = 5000e^(rt)

After three hours it grew 6500 bacteria:

This means that P(3) = 6500. We use this to find r.

P(t) = 5000e^(rt)

6500 = 5000e^(3r)

e^(3r) = (65)/(50)

\ln{e^(3r)} = \ln{(65)/(50)}

3r = \ln{(65)/(50)}

r = \frac{\ln{(65)/(50)}}{3}

r = 0.0875

So

P(t) = 5000e^(0.0875t)

How many bacteria will be present after 13 hours?

This is P(13). So

P(13) = 5000e^(0.0875*13) = 15594.8

Rounding to the nearest whole number

15595 bacteria will be present after 13 hours.

I will really appreciate the help because i’m stuck and need this as soon as possible This problem uses the notion that to find the closest distance from a point to a line we need the perpendicular line joining them. The idea is that the plane is heading in some direction, if we treat the takeoff point as the origin (0,0), we can make an equation of a line to the destination. Then we need to take the slope of that line, find its negative reciprocal to build a perpendicular slope, and then use that new perpendicular slope and the point where the mountain is to make a NEW line. Then we find the intersection of these two lines, a system of equations, (preferably by an algebraic process like substitution or elimination) to find the time at which the plane will be closest to the mountain on its path toward its destination.

the problem:

You're flying from Joint Base Lewis-McChord (JBLM) to an undisclosed location 245 km south and 237 km east. Mt. Rainier is located approximately 56 km east and 40 km south of JBLM. If you are flying at a constant speed of 800km / hr how long after you depart JBLM will you be the closest to Mt. Rainier?

______minutes

Answers