MATHEMATICS COLLEGE

F3 + 11g - 4h when f=3 g=2 h=7

Answers

Answer 1
Answer:

Answer:

3

Step-by-step explanation:

3 x 3 = 9

11 x 2 = 22

4 x 7 = 28

9 + 22 = 31

31 - 28 = 3

hope this helps :)

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Jessica is asked to solve this problem on her math quiz −29+14=? She remembered that she needed to watch for the signs on the numbers, but she is still confused on how the rules work for addition of integers. In complete sentences, explain to Jessica what rule she would use to solve this problem and how she can tell what the sign on her final answer should be in order to get the question correct on her quiz.

Answers

Answer:

Step-by-step explanation:

-29 +14 =-15

The biggest number "29" has minus "-" in front, so in the final the sigh will be minus. The final sigh on the answer dibents on the biggest number.

If you have this exercise :

-14 +29 =15

The biggest number has "+" in front of it

Final answer:

To solve the problem −29+14, you subtract the smaller number from the larger number and give the answer the sign of the larger number, resulting in −15. The rules of addition for integers require attention to the sign and magnitude of the numbers involved.

Explanation:

Jessica, to solve the problem −29+14, we need to apply the rule for addition when dealing with integers that have different signs. Since −29 is negative and 14 is positive, you subtract the smaller number from the larger number and the answer will have the sign of the larger number. In this case, 29 is larger than 14, so we do 29 − 14, which equals 15. Because the larger number (29) was negative, the result will also be negative, so the final answer is −15.

Remember the rules of addition for different signs: when adding two numbers with opposite signs, the answer will have the sign of the larger absolute value. We subtract the smaller absolute value from the larger one to determine the numerical part of the answer. If you're ever unsure about the sign, just remember that the answer will take the sign of the number with the larger absolute value. This is also true when performing subtraction, except you change the sign of the number being subtracted first, then proceed with addition based on the rules for integers.

Write an augmented matrix for the system. Then state the dimensions. x+8y−7z=12 5x+9y+5z=15 6z−3y−8x=1

Answers

Answer: Write an augmented matrix for the system. Then state the dimensions. x+8y−7z=12 5x+9y+5z=15 6z−3y−8x=1

Step-by-step explanation: x+8y-7z=12 5x+9y+5z=15 6z-3y-8x=1. - 18028782.

Final answer:

The system of equations provided can be converted into an augmented matrix as follows: [[1, 8, -7, 12], [5, 9, 5, 15], [-8, -3, 6, 1]]. The dimensions of this matrix are 3x4.

Explanation:

The provided system of equations is:

1. x + 8y - 7z = 12

2. 5x + 9y + 5z = 15

3. -8x - 3y + 6z = 1

We can represent this system as an augmented matrix by aligning the coefficients of the variables and the constants. The augmented matrix is:

[[1, 8, -7, 12], [5, 9, 5, 15], [-8, -3, 6, 1]]

The dimensions of this matrix represents the number of rows and columns it has. In this case, this matrix is a 3x4 matrix because it has 3 rows and 4 columns.

Learn more about Augmented Matrix here:

brainly.com/question/40671143

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Let v be the volume of a sphere, s be the surface area of the sphere, and r be the radius of the sphere. which equation represents the relationship between these three measures

Answers

let
v------->  the volume of a sphere
s-------> the surface area of the sphere
r------> the radius of the sphere

we know that
v=(4/3)*pi*r³-----> v=(r/3)*4*pi*r²------> equation 1
and
S=4*pi*r²-----> equation 2

substitute equation 2 in equation 1
so
v=(r/3)*4*pi*r²-------> v=(r/3)*s

the answer is
the equation that represents the relationship between these three measures
 v=(r/3)*s

A field is 53 1/3 yards wide. What is the width of the field in feet?

Answers

Answer: The  width of the field = 160 feet

Step-by-step explanation:

We are given that , A field is 53(1)/(3) yards wide.

That means , The width of the field = 53(1)/(3) yards

Since , the fraction is in mixed for , so first we convert this into improper fraction.

53(1)/(3)=(3(53)+1)/(3)=(160)/(3)

Therefore , the width of the field = (160)/(3) yards

Since 1 yard = 3 feet.

⇒ the width of the field = (160)/(3)*3 feet

Therefore , the width of the field = 160 feet

What the answer to this math problom

Answers

Step-by-step explanation:

S=b*h/2=8*10/2=40m2

40*4=160m²

Answer:

60 m2

Step-by-step

i did that before hope this helps :)

A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the cost to make the can if the metal for the sides will cost $1.25 per 2 cm and the metal for the bottom will cost $2.00 per 2 cm ?

Answers

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= \pi r^2h

According to the problem,

\pi r^2 h=25

\Rightarrow h=(25)/(\pi r^2)

The surface area of the base of the can is = \pi r^2

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× \pi r^2)

The lateral surface area of the can is = 2\pi rh

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× 2\pi rh)

                                                 =\$2.5 \pi r h

Total cost of metal is C= 2.00 \pi r^2+2.5 \pi r h

Putting h=(25)/(\pi r^2)

\therefore C=2\pi r^2+2.5 \pi r * (25)/(\pi r^2)

\Rightarrow C=2\pi r^2+ (62.5)/( r)

Differentiating with respect to r

C'=4\pi r- (62.5)/( r^2)

Again differentiating with respect to r

C''=4\pi + (125)/( r^3)

To find the minimize cost, we set C'=0

4\pi r- (62.5)/( r^2)=0

\Rightarrow 4\pi r=(62.5)/( r^2)

\Rightarrow r^3=(62.5)/( 4\pi)

⇒r=1.71

Now,

\left C''\right|_(x=1.71)=4\pi +(125)/(1.71^3)>0

When r=1.71 cm, the metal cost will be minimum.

Therefore,

h=(25)/(\pi* 1.71^2)

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.
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