What is the scale factor of this dilation?

Answers

Answer 1

Answer:

Step-by-step explanation:To find the scale factor for a dilation, we find the center point of dilation and measure the distance from this center point to a point on the preimage and also the distance from the center point to a point on the image. The ratio of these distances gives us the scale factor.

Related Questions

Look at the steps used when solving 3(x - 2) = 3 for x Which step is the result of combining like terms? A) Step 1 B) Step 2 C) Step 3 D) Step 4
Find sin (A-B) if sin A = 4/5 with A between 90 and 180 and if cos B = 3/5 with B between 0 and 90
How many #5 cans of potato salad are required to serve 210 people if each can has 3 pounds 8 ounces of potato salad and each serving is 5 ounces
15. In the State of California, there are 25 full-time employees to every 4 part-time employees. If there are 250,000 full-time employees, how many part-time employees are there statewide?
The weights of a certain brand of candies are normally distributed with a mean weight of 0.8547 g and a standard deviation of 0.0511 g. A sample of these candies came from a package containing 463 candies, and the package label stated that the net weight is 395.2 g. (If every package has 463 candies, the mean weight of the candies must exceed StartFraction 395.2 Over 463 EndFraction 395.2 463equals=0.8535 g for the net contents to weigh at least 395.2 g.) a. If 1 candy is randomly selected, find the probability that it weighs more than 0.8535 g. The probability is .(Round to four decimal places as needed.)

The dew point in degrees Fahrenheit can be calculated with the formula DP - T-(100 - RH), where DP is the dew point, T is the dry-bulb temperature, and RH is the relative humidity. Which of these is the equation solved forRH?

Answers

The equation for Relative Humidity RH is Option 3.

RH = 100 - 25/9 ( T - DP )

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

The dew point in degrees Fahrenheit is calculated by the equation ,

DP = T - 9/25 ( 100 - RH )

where ,

DP = Dew Point

T = Temperature of dry-bulb

RH = Relative Humidity

Now , to solve for Relative Humidity , the equation can be simplified as

DP = T - 9/25 ( 100 - RH )

So ,

Adding 9/25 ( 100 - RH ) on both sides , we get

DP + 9/25 ( 100 - RH ) = T

Subtracting DP on both sides , we get

9/25 ( 100 - RH ) = T - DP

Multiply by 25/9 on both sides , we get

( 100 - RH ) = 25/9 ( T - DP )

Adding RH on both sides , we get

100 = RH + 25/9 ( T - DP )

Now , subtracting 25/9 ( T - DP ) on both sides , we get

100 - 25/9 ( T - DP ) = RH

Therefore , RH = 100 - 25/9 ( T - DP )

Hence , the equation for Relative Humidity RH is given by

RH = 100 - 25/9 ( T - DP )

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Answer:D

Step-by-step explanation:

A gym has yoga classes each class has 14 students if there are c classes write an equation to represent the total number of students s taking yoga

Answers

Answer:

14 times c = s

Step-by-step explanation:

Another name for the weighted point evaluation method is the ____ method.

Answers

The answer for this question is: Kepner tregoe

F(x)=5x2−3x−1 and g(x)=2x2−x+3f(x)+g(x)=
Question 18 options:

3x2−4x−4

3x2−2x−4

7x2+4x+3

7x2−4x+2

Answers

Answer:

f(x) + g(x) = 7x² - 4x + 2

General Formulas and Concepts:

Algebra I

Combining Like Terms

Step-by-step explanation:

Step 1: Define

f(x) = 5x² - 3x - 1

g(x) = 2x² - x + 3

Step 2: Find f(x) + g(x)

Substitute: f(x) + g(x) = 5x² - 3x - 1 + 2x² - x + 3
Combine like terms (x²): f(x) + g(x) = 7x² - 3x - 1 - x + 3
Combine like terms (x): f(x) + g(x) = 7x² - 4x - 1 + 3
Combine like terms (Z): f(x) + g(x) = 7x² - 4x + 2

WILL GIVE BRAINLIEST!!! 50POINTS. PLEASE EXPLAIN!What is the recursive rule for this geometric sequence? 2, 1/2, 1/8, 1/32, ... Enter your answers in the boxes.
an=___⋅an−1, a1=___

Answers

$\bf \stackrel{a_1}{2}~~,~~\stackrel{2\cdot (1)/(4)}{\cfrac{1}{2}}~~,~~\stackrel{(1)/(2)\cdot (1)/(4)}{\cfrac{1}{8}}~~,~~\stackrel{(1)/(8)\cdot (1)/(4)}{\cfrac{1}{32}}\n\n-------------------------------\n\na_n=\cfrac{1}{4}\cdot a_(n-1)\qquad \qquad a_1=2$

Answer:

an= 1/4 · an-1 a1= 2

Step-by-step explanation:

Got it correct on the test.

The blood platelet counts of a group of women have a bell-shaped distribution with a mean of and a standard deviation of . (All units are 1000 cells/L.) Using the empirical rule, find each approximate percentage below. a. What is the approximate percentage of women with platelet counts within standard of the mean, or between and ?
b. What is the approximate percentage of women with platelet counts between and ?

Answers

Answer:

(a) Approximately 95% of women with platelet counts within 2 standard deviations of the mean.

(b) Approximately 99.7% of women have platelet counts between 65.2 and 431.8.

Step-by-step explanation:

The complete question is: The blood platelet counts of a group of women have a bell-shaped distribution with a mean of 248.5 and a standard deviation of 61.1. (All units are 1000 cells/mul.) using the empirical rule, find each approximate percentage below.

a. What is the approximate percentage of women with platelet counts within 2 standard deviations of the mean, or between 126.3 and 370.7?

b. What is the approximate percentage of women with platelet counts between 65.2 and 431.8?

We are given that the blood platelet counts of a group of women have a bell-shaped distribution with a mean of 248.5 and a standard deviation of 61.1.

Let X = the blood platelet counts of a group of women

The z-score probability distribution for the normal distribution is given by;

Z = $(X-\mu)/(\sigma)$ ~ N(0,1)

where, $\mu$ = population mean = 248.5

$\sigma$ = standard deviation = 61.1

Now, the empirical rule states that;

68% of the data values lie within 1 standard deviation away from the mean.

95% of the data values lie within 2 standard deviations away from the mean.

99.7% of the data values lie within 3 standard deviations away from the mean.

(a) The approximate percentage of women with platelet counts within 2 standard deviations of the mean, or between 126.3 and 370.7 is given by;

As we know that;

P( $\mu-2\sigma$ < X < $\mu+2\sigma$ ) = 0.95

P(248.5 - 2(61.1) < X < 248.5 + 2(61.1)) = 0.95

P(126.3 < X < 370.7) = 0.95

Hence, approximately 95% of women with platelet counts within 2 standard deviations of the mean.

(b) The approximate percentage of women with platelet counts between 65.2 and 431.8 is given by;

Firstly, we will calculate the z-scores for both the counts;

z-score for 65.2 = $(X-\mu)/(\sigma)$

= $(65.2-248.5)/(61.1)$ = -3

z-score for 431.8 = $(X-\mu)/(\sigma)$

= $(431.8-248.5)/(61.1)$ = 3

This means that approximately 99.7% of women have platelet counts between 65.2 and 431.8.

Final answer:

Using the empirical rule, approximately 68% of values fall within 1 standard deviation from the mean in a bell-shaped distribution. For ranges 2 or 3 standard deviations from the mean, the respective approximate percentages are 95% and 99.7%.

Explanation:

The question refers to the Empirical rule, which in statistics, is also known as the Three-sigma rule or the 68-95-99.7 rule. This rule is a shortcut for remembering the proportion of values in a normal distribution that are within a given distance from the mean: 68% are within 1 standard deviation, 95% are within 2 standard deviations, and 99.7% are within 3 standard deviations.

Without given specific values for the mean or standard deviations, we can discuss the problem in a general sense:

For part a, the percentage of women with platelet counts within 1 standard deviation from the mean is approximately 68% under the Empirical rule.
For part b, it depends on how many standard deviations from the mean the range mentioned lies. If it refers to two standard deviations from the mean, then 95% of women would fall into this range, if it refers to three standard deviations, then approximately 99.7% would be the case.

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