The weights of a certain brand of candies are normally distributed with a mean weight of 0.8547 g and a standard deviation of 0.0511 g. A sample of these candies came from a package containing 463 ​candies, and the package label stated that the net weight is 395.2 g.​ (If every package has 463 ​candies, the mean weight of the candies must exceed StartFraction 395.2 Over 463 EndFraction 395.2 463equals=0.8535 g for the net contents to weigh at least 395.2 ​g.) a. If 1 candy is randomly​ selected, find the probability that it weighs more than 0.8535 g. The probability is .​(Round to four decimal places as​ needed.)

Answers

Answer 1
Answer:

Answer:

There is a 69.15% probability that it weighs more than 0.8535 g.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = (X - \mu)/(\sigma)

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that

The weights of a certain brand of candies are normally distributed with a mean weight of 0.8547 g, so \mu = 0.8547.

We have a sample of 463 candies, so we have to find the standard deviation of this sample to use in the place of \sigma in the Z score formula. We can do this by the following formula:

s = (\sigma)/(√(463)) = 0.0024

Find the probability that it weighs more than 0.8535

This is 1 subtracted by the pvalue of Z when X = 0.8535

So

Z = (X - \mu)/(s)

Z = (0.8535 - 0.8547)/(0.0024)

Z = -0.5

Z = -0.5 has a pvalue of 0.3085.

This means that there is a 1-0.3085 = 0.6915 = 69.15% probability that it weighs more than 0.8535 g.


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23 greater than b is at least -276

What is the y-coordinate of the point that divides the directedline segment from J to K into a ratio of 2:3?

K(8,11)

J(-3,1)


*7

*-6

*5

*-5

Answers

Answer:

(D)5

Step-by-step explanation:

Given the point J(-3,1) and K(8,11).

The line segment that divides the segment from J to K in any given ratio can be determined using the formula.

P(x,y)=\left((mx_2+nx_1)/(m+n) ,(my_2+ny_1)/(m+n)\right)

In the given case:

(x_1,y_1)=(-3,1), (x_2,y_2)=(8,11), m:n=2:3

Since we are to determine the y-coordinate of the point that divides JK into a ratio of 2:3, we have:

(my_2+ny_1)/(m+n)=(2*11+3*1)/(3+2)\n\n=(22+3)/(5)\n\n=(25)/(5)\n\n=5

The y-coordinate of the point that divides the directed  line segment from J to K into a ratio of 2:3 is 5.

The correct option is D.

Answer:

The answer is actually C(5) not D

Step-by-step explanation:

HALP AND YOU GET CANDY THE PICTURE BELOW IS YOUR KEY TO CANDY (BRAINLIST)

Answers

Answer:

3 1/8

Step-by-step explanation:

Wheres my candy!!

Answer:

3 1/8

Step-by-step explanation:

10 - 6 7/8 = 3 + 1/8

Solve the inequality. 12x<-144

Answers

Answer:

Step-by-step explanation:

x=-12

Answer:

x= -12

Step-by-step explanation:

Frans Summer job pays $200 per week. The circle graph shows how she spends the $200.50%
savings
10%
movies
15%
other
10%
books
15%
clothing
How many dollars of Fran's weekly pay is spent on books and clothing?
O
A. $25
OC. $50
O D. $100
OB. $30

Answers

Answer:

  C.  $50

Step-by-step explanation:

She spends 10% of her pay on books and 15% on clothing, for a total of 25% on books and clothing.

  0.25 × $200 = $50

Fran spends $50 of her pay on books and clothing.

If f(x) = - x2 + 6x - 1 and g(x) = 3x2 - 4x - 1, find (f - g)(x).O A. (f- g)(x) = 2x2 + 2x - 2
O B. (f- g)(x) = -4x2 + 10x
O c. (f- g)(x) = 4x2 - 10x
O D. (f- g)(x) = -4x2 - 2x

Answers

The (f-g)(x) is- 4x²+ 10x

What are functions?

A function in mathematics from a set X to a set Y allocates exactly one element of Y to each element ofX. The sets X and Y are collectively referred to as the function's domain and codomain, respectively. Initially, functions represented the idealized relationship between two changing quantities.

Given

f(x) = - x² + 6x -1

g(x)=3x² - 4x - 1

(f-g)(x) = - x² + 6x -1 -(3x² - 4x - 1)

(f-g)(x) = - x² + 6x -1 - 3x² + 4x + 1

(f-g)(x) = - 4x² + 10x

(f-g)(x) = - 4x²+ 10x

To know more about codomain refer to :

brainly.com/question/14626586

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If f(x) = x2 + 2x + 1 and g(x) = 3(x + 1)2, which is anequivalent form of f(x) + g(x)?
O x2 + 4x + 2
O 4x2 + 2x + 4
O 4x2 + 8x + 4
o 10x2 + 20x + 1

Answers

The equivalent form of f(x) + g(x), if  f(x) = x² + 2x + 1 and g(x) = 3(x + 1)² is

4x² + 8x + 4, so option C is correct.

What is a function?

In the case of a function from one set to the other, each element of X receives exactly one element of Y. The function's domain and co-domain are respectively referred to as the sets X and Y as a whole.

Given:

f(x) = x² + 2x + 1 and g(x) = 3(x + 1)²

Calculate the equivalent form as shown below,

f(x) + g(x) = x² + 2x + 1 + 3(x + 1)²

Simplify the above equation,

f(x) + g(x) = x² + 2x + 1 + 3(x² + 2x + 1)

f(x) + g(x) = x² + 2x + 1 + 3x² + 6x + 3

f(x) + g(x) = 4x² + 8x + 4

To know more about function:

brainly.com/question/5975436

#SPJ2

the answer should be C