PLEASE ANSWER I NEED ITTY
PLEASE ANSWER I NEED ITTY - 1

Answers

Answer 1
Answer:

Answer:

13. B

14. A

both declining slopes


Related Questions

Does it seem plausible that employment has a normal distribution for each gender
The golden state warriors are playing the cleveland cavaliers on thursday june 1, 2017 in game 1 of the nba championship series. suppose that golden state has a 58% chance of winning the game. nba games cannot end in a tie.
Write the slope- intercept form of the equation of the line described through (4,5) parallel to y= 1/4x-4
Miguel and his family are on vacation and notice an advertisement fee of 0.75
30 POINTS FOR JUST ONE QUESTION! :)

Breyers is a major producer of ice cream and would like to test if the average American consumes more than 17 ounces of ice cream per month. A random sample of 25 Americans was found to consume an average of 19 ounces of ice cream last month. The standard deviation for this sample was 5 ounces. Breyers would like to set LaTeX: \alpha = 0.025 α = 0.025 for the hypothesis test. It is known that LaTeX: z_{\alpha}=1.96 z α = 1.96 and LaTeX: t_{\alpha}=2.06 t α = 2.06 for the df = 24. Also, it is established that the ice cream consumption follows the normal distribution in the population. The conclusion for this hypothesis test would be

Answers

Answer:

The conclusion for this hypothesis test would be that the average American consumes less than or equal to 17 ounces of ice cream per month.

Step-by-step explanation:

We are given that Breyers is a major producer of ice cream and would like to test if the average American consumes more than 17 ounces of ice cream per month.

A random sample of 25 Americans was found to consume an average of 19 ounces of ice cream last month. The standard deviation for this sample was 5 ounces.

Let \mu = average ounces of ice cream consumed by American per month

So, Null Hypothesis, H_0 : \mu \leq 17 ounces     {means that the average American consumes less than or equal to 17 ounces of ice cream per month}

Alternate Hypothesis, H_A : \mu > 17 ounces    {means that the average American consumes more than 17 ounces of ice cream per month}

The test statistics that will be used here is One-sample t test statistics as we don't know about population standard deviation;

                                 T.S.  = (\bar X-\mu)/((s)/(√(n) ) )  ~ t_n_-_1

where, \bar X = sample average = 19 ounces

             s = sample standard deviation = 5 ounces

             n = sample of Americans = 25

So, test statistics  =  (19-17)/((5)/(√(25) ) )  ~ t_2_4

                               =  2

The value of the test statistics is 2.

Now at 0.025 significance level, the t table gives critical value of 2.06 at 24 degree of freedom for right-tailed test. Since our test statistics is less than the critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the the average American consumes less than or equal to 17 ounces of ice cream per month.

There are 13 fish in an aquarium. Seven of the fish are guppies. How manynon-guppies are in the aquarium?
A. the number of guppies
B. the total number of fish
C. the number of non-guppies
( what is the variable in the problem?)

Answers

Answer:

6 non-guppies; C. the number of non-guppies

Step-by-step explanation:

13-7=x

(x is the number of non-guppies)

13-7=6

A 50 kg pitcher throws a baseball with a mass of 0.15 kg. If the ball is thrown with a positive velocity of 35 m/s and there is no net force on the system, what is the velocity of the pitcher? −0.1 m/s −0.2 m/s −0.7 m/s −1.4 m/s

Answers

Answer:

The velocity of the pitcher is −0.1 m/s


Step-by-step explanation:

Given : Mass of pitcher = 50 kg

            Mass of Baseball= 0.15kg

            Velocity of Ball = 35m/s

To Find : velocity of the pitcher

Solution :

The total momentum of the system is conserved when no external force acts on a system .The total initial momentum of the system is equal to the total final momentum of the system.

Since ,  the ball and the pitcher are initially at rest, therefore, the total initial momentum of the system is zero.

Since we are given that  no external forces act on the system , the total final momentum of the system is also equal to zero.

Let us suppose the mass of the pitcher is m_(p)

Speed of pitcher = v_(p)

The mass of the ball is m_(b)

Speed of ball  = v_(b)

So, the final momentum of the system of pitcher and the ball is given by:

momentum =m_(p) v_(p) +m_(b) v_(b) =0

50* v_(p) +0.15*35 =0

50* v_(p) +5.25 =0

v_(p) = (-5.25)/(50)

v_(p) = -0.105

Thus , The velocity of the pitcher is -0.105m/s≈−0.1 m/s

Negative sign shows the opposite direction.

Hence The velocity of the pitcher is −0.1 m/s






the answer is -0.1 m/s if you're looking for the Edgnuity answer. I just took the test. Hope this helps!

Givin sin0= 12/13, find sec(0)A. Sec(0)= 13/12

B. Sec(0)= 5/13

C. Sec(0)= 5/12

D. Sec(0)= 13/5

Answers

Answer:

D. sec(a) = 13/5

Step-by-step explanation:

if sin(a) = 12/13, then cos (a) = 5/13, because of 5-12-13 triangles

sec(a) = 1/cos(a)

1/(5/13) = 13/5

sec(a) = 13/5

In the past, 44% of those taking a public accounting qualifying exam have passed the exam on their first try. Latterly, the availability of exam preparation books and tutoring sessions may have improved the likelihood of an individual’s passing on his first try. In a sample of 250 recent applicants, 130 passed on their first attempt. At the 0.05 level of significance, what is the calculated value of test statistic? (Specify your answer to the 2nd decimal.)

Answers

Answer:

The calculated value of test statistic is z=2.48.

This has a P-value of P=0.00657.

If we state the null hypothesis H_0: \pi\leq0.44 at a significance level of \alpha=0.05, we would reject this null hypothesis as P-value<\alpha.

Step-by-step explanation:

We have in this problem, a hypothesis test of proportions.

The test statistic for this is the z-value, and is calculated like that:

z=(p-\pi-0.5/N)/(\sigma)

Where the term 0.5/N is the correction for continuity and is negative in the cases that p>π.

p: proportion of the sample; π: proportion of the population; σ: standard deviation of the population.

The standard deviation of the population has to be calculated as:

\sigma=\sqrt{(\pi(1-\pi))/(N) } =\sqrt{(0.44(1-0.44))/(250) }=√(0.0009856)=0.0314

The proportion of the sample (p) is p=130/250=0.52.

Then, the test statistic z is

z=(p-\pi-0.5/N)/(\sigma)=(0.52-0.44-0.5/250)/(0.0314) =(0.078)/(0.0314) =2.48

The P-value of this statistic is P(z>2.48)=0.00657

If we state the null hypothesis H_0: \pi\leq0.44 at a significance level of \alpha=0.05, we would reject this null hypothesis as P-value<\alpha.

What is the next number in the sequence? 3….9….27….81….A) 162
B) 180
C)243
D) 270

Answers

The next number should be 81*3, so 243.