Answer:
All of the above
Explanation:
To ensure the ball go to where we expected it go
The object be going at the bottom of the hill with velocity 7.75 m/s.
When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Given in the question a 400 kg object is sitting at rest at the top of a hill that is 30.0 m high and 80.0 m long measured along the hill . If there is no friction, velocity with which object be going at the bottom of the hill,
θ =sin^-1(30/80)
θ =22
F = 400 g sin(22) = 150 N
F = ma
150 = 400 a
a = 0.375 m/s²
v² - u²= 2 a s
v² - 0 = 2 x 0.375 x 80
v = 7.75 m/s
The object be going at the bottom of the hill with velocity 7.75 m/s.
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Answer:
80 cm
Explanation:
the given condition is closed-end air column. The wavelength is four times the length of the air column for the standing wave pattern for the first harmonic.
The required wavelength of the standing wave pattern is
=
Answer:
d) velocity-time graph is nonlinear
Explanation:
A straight line is seen in the velocity-time graph for uniform acceleration in rectilinear motion.
Wave A will be faster than the wave B because
The frequency of the wave is defined as the cycle completed by the wave per second.
Now it is given in the question:
Frequency of wave A = 250 hertz
The wavelength of wave A= 30 cm
Frequency of wave B = 260 hertz
The wavelength of wave B= 25 cm
Now for finding which wave is faster we will calculate the velocity of the wave.
For Wave A
For wave B
We can see that the velocity of wave A is higher than the velocity of wave B.
Thus wave A will be faster than the wave B because
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