What is air pressure?

Answer:

a)40.77N

b)0.11seg

Explanation:

The bullet has a kinetic energy:

When the bullet stops this energy goes to zero, as the energy must be conserved the work done by the head of the superhero must be equal to the original energy of the bullet:

Considering an average constant force, the work can be calculated as:

Solving for F:

The acceleration(on the opposite direction of motion) on the bullet will be:

The velocity of the bullet considering a constant acceleration can be calculate as:

It stops moving when V=0 so:

Answer:

a) 23444.3 N

b) 0.191 ms

Explanation:

Given:

Mass of the bullet m = 7.8 g = 7.8 * 10⁻³ Kg

Initial speed u = 575 m/s

Final speed v = 0

Distance covered s = 5.50 cm = 0.055 m

(a)

According to work energy theorem

Work done W = Change in Kinetic energy

hence, force*distance = 1/2*mass*velocity²          

that is, F*S  = (1/2)mu²

 F*0.055 = 0.5 * 7.8 * 10⁻³ * (575)^2

F = 23444.3 N

(2)

From Impulse definition

 force*time = change in momentum

where momentum = mass * velocity

F*t = Change in momentum = m* u

23444.3t = 7.8*10⁻³ * 575

Time, t = 0.191 ms    

Answer:

Flame test is the procedure to find out the metal ions in the ionic compounds. By observing the color of flame we find out the presence of certain metallic ion. For example if we take the test of copper halide, the flame will become of the bluish green color due to the copper ion. You can perform the test with the common salt. Upon putting it on the flame, the color of flame will become yellow due to the presence of sodium ion. Similarly aluminium shows blue and calcium brick red etc.

Explanation:

Final answer:

The flame test, used in chemistry to identify certain substances through the color of their flame, has limited sensitivity, as some elements produce similar flame colors and multiple elements in a sample can complicate interpretation. Still, it remains a valuable tool in qualitative analysis. Other assessments, such as the NFPA 704 Hazard Identification System, can help understand the reactiveness and flammability of substances.

Explanation:

Characterizing the flame test with respect to its sensitivity involves understanding the minimal amount of a compound that the test can detect. Just like our senses have an absolute threshold for detection, so does the flame test. It can identify the presence of various elements in a compound based on the color of the flame. For example, sodium and its compounds impart a bright yellow color to a flame whereas lithium creates a bright, crimson color.

Despite its usefulness, the flame test may not be the most sensitive method for substance identification. Some elements may produce similar flame colors, making it difficult to distinguish between them. Moreover, the presence of multiple elements in a sample can also complicate the interpretation of flame test results. Therefore, while the flame test is a valuable tool in qualitative analysis, its sensitivity is somewhat limited.

According to the National Fire Protection Agency (NFPA) 704 Hazard Identification System, each substance has its own degree of hazard that ranges from 0 to 4. This information is critical in understanding the reactivity and flammability of substances, and is another aspect to consider when characterizing the sensitivity of the flame test.

Learn more about Flame Test Sensitivity here:

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