your answer is 15,625 N
i just took the test
b) 150kPA
c) 170kPA
d) 250kPA
give reasons
A fixed mass of gas has a volume of 25 , the pressure of the gas is 100 kPa, the volume of the gas is slowly decreased by 15 at a constant temperature, and the change in pressure of the gas is 150 kPa, which is option b.
PV = nRT (P= pressure of the gas, V =volume, n = number of moles of gas, R = gas constant, and T =temperature of the gas in kelvin)
Suppose the gas is an ideal gas and that the temperature is constant,
P1V1 = P2V2
Here P1 = 100 kPa, V1 = 25 , V2 = 10 ,
100 kPa x 25 = P2 x 10
P2 = (100 kPa x 25 ) / 10
P2 = 250 kPa
the change in pressure of the gas is,
ΔP = P2 - P1 = 250 kPa - 100 kPa = 150 kPa
The reason is that when the volume of a fixed mass of gas is decreased, the pressure of the gas increases proportionally, so here assuming that the temperature is constant it is calculated.
Hence, the volume of the gas is slowly decreased by 15 at a constant temperature, and the change in pressure of the gas is 150 kPa, which is option b.
Learn more about the calculation of the change in pressure here.
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Answer:
v' = 14.76 m/s
Explanation:
given,
frequency of the one truck = 206 Hz
apparent frequency ,f' = 189 Hz
speed of sound, v = 343 m/s
speed of observer (v_o)and source (v_s) = v'
now, using Doppler's effect
314.69 + 0.9174 v' = 343 - v'
1.9174 v' = 28.30
v' = 14.76 m/s
hence, the speed of the truck is equal to 14.76 m/s
b.yes, the obtained speed is almost equal to the world-record.
c.no, the obtained speed is greater than the world-record.
d.no, the obtained speed is almost equal to the world-record.
The answer is
A. Yes, the obtained speed is less than the world record
The explanation:
when the obtained speed is 6 m /s
and the world record speed = distance / time = 100 m / 10 s = 10 m/s
So, Yes, the obtained speed is less than the world record
Not only is it less, its also a reasonable average speed for a somewhat athletic person. Therefore, the leap is entirely possible.
-Samuel Brady gained his lasting notoriety for his leap over the Cuyahoga River around 1780 in what is now Kent, Ohio. After following a band of Indians into the Ohio country, a failed ambush attempt resulted in the band chasing Brady near the Cuyahoga River. To avoid capture, Brady leaped across a 22-foot (6.7 m) wide gorge of the river (which was widened considerably in the 1830s for construction of the Pennsylvania and Ohio Canal) and fled to a nearby lake where he hid in the water under a fallen tree using a reed for air.
Part (a): The minimum speed of Brady should be to cross the cliff.
Part (b): The speed of Brady’s leap is possible to achieve, as it is less than the speed of world record.
Further Explanation:
(a)
Brady jumps from a cliff to go on other side. He crosses horizontal distance from a height of . To jump from cliff, he follows the Newton’s law of motion.
Given:
The horizontal distance is .
The vertical distance is .
Concept:
The horizontal distance in meter is .
The vertical distance in meter is .
To obtain the time of flight, applying one of the equation of motion given as:
Substitute for and rearrange the above equation for :
Substitute for and for in above equation.
The time of flight and time taken to cover horizontal distance are equal.
Horizontal velocity of Brady given as:
Thus, the minimum speed of Brady should be to cross the cliff.
(b)
The minimum speed with which Brady is running is .
The speed of world record given as:
Thus, the speed of Brady’s leap is possible to achieve, as it is less than the speed of world record.
Learn more:
1. Projectile motion of a body: brainly.com/question/11023695
2. Body in pure rolling motion: brainly.com/question/9575487
3. Newton’s law of motion: brainly.com/question/6125929
Answer Details:
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords:
1780, Brady's Leap, Captain, Sam, U.S. Continental Army, horizontally, cliff, Ohio's Cuyahoga, gorge, leap, 22 ft, 20 ft, minimum, speed, river, 100 m, dash, 10 s, jump, time of flight, vertical and distance.
The mass of the aluminum added is calculated through the principle of conservation of energy, specifically thermal energy. By considering the heat lost by the aluminum and gained by the water, we can rearrange the equation for heat transfer and find that the mass of the aluminum is approximately 37.9 grams.
In this physics question, we're looking at a thermodynamic process involving a chunk of aluminum and water. Given the known values of their respective specific heats, the mass of water, and their final equilibrium temperature, we're aiming to find the mass of the aluminum.
We begin by understanding that in a closed system, the heat gained by one body is equal to the heat lost by another. In this case, the aluminum is losing heat, and the water is gaining it. The equation for heat transfer (Q = mcΔT), where m is mass, c is specific heat, and ΔT is change in temperature.
The heat gained by the water = mass of water * specific heat of water * change of temperature in water = 200g * 4.18J/g°C * (18.9°C - 15.5°C) = 2836.4J.
This is equal to the heat lost by the aluminum. Solving the analogous heat equation for the mass of the aluminum gives us the answer:
m = Q / (c * ΔT) = 2836.4J / (0.897J/g°C * (91.4°C - 18.9°C)) = 37.9g
So the mass of the aluminum is approximately 37.9 grams.
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