Which fraction is represented by point A on the number line?0
А
-0 -1
о
IT
os
O 1
$Which fraction is represented by point A on the number - 1$

Answers

Answer 1

Answer: The answer is the third choice: -1/4.
Here’s why: if you count from 0 to 1 or -1, it’s 4 steps. That means the fraction would have a denominator of 4, if there were 5 parts, then the denominator would be 5...and so on. The numerator is 1 because 0 to the point is 1 step. But now why negative? Because everything to the left of 0 on the number line will be negative, everything right of 0 on the number line will be positive.
Hope this also helped you to understand for future problems like this.

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My soccer team has 16 players. I have to choose a starting lineup of a goalie and 10 regular players (the regular players are interchangeable). How many different starting lineups can i choose? *the answer is not 4368*

Answers

Answer:

3003

Step-by-step explanation:

We want to find out how many ways we can choose 10 players among 15 players (since the goalie is not interchangeable)

The number of different lineups you can have can be found by using combination:

$^(15)C_(10) = (15!)/((15 - 10)! 10!)\n \n= (15!)/(5! * 10!) \n\n= 3003$

There are 3003 different lineups that can be chosen.

Final answer:

To determine the number of starting lineups, we use combinations in probability. We first choose a goalie from 16 players, then 10 regular players from the remaining 15, giving us 48048 unique lineups.

Explanation:

This problem can be solved by using the concept of combinations in probability and statistics. The formula for combinations is C(n, k) = n! / [k!(n-k)!], where n is the total number of items, k is the number of items to choose, and ! denotes factorial, which is the product of all positive integers up to that number.

Firstly, we need to choose a goalie. There are 16 players, so the number of ways to choose a goalie is C(16, 1) = 16.

After choosing the goalie, we are left with 15 players. Then we need to choose 10 players to fill in the rest of the team. Thus, the number of ways to choose the 10 regular players is C(15, 10).

The total number of unique starting lineups is then the product of these two results. Hence, the solution would be C(16, 1) * C(15, 10) = 16 * 3003 = 48048 different starting lineups.

Learn more about Combinations here:

brainly.com/question/24703398

#SPJ3

X=3/5 y=1/3 z=24/5 work out the value of z+x x y

Answers

The correct answer is 3.

You have just completed an experiment measuring the length (in mm) of 12 soybean plants after 3 days of sprouting. The measurements are listed below:53 47 51 54 43 39 61 57 55 46 44 43

If you doubled every measurement in this dataset (e.g., 106, 94, 102, ...), what would the new IQR equal? (Think about the SD too!)

Answers

Answer:

The new IQR is 22.

Step-by-step explanation:

We are given the following data of length (in mm) of 12 soybean plants after 3 days of sprouting.

53, 47, 51, 54, 43, 39, 61, 57, 55, 46, 44, 43

Sorted data:

39, 43, 43, 44, 46, 47, 51, 53, 54, 55, 57, 61

Formula:

$IQR = Q_3 - Q_1\nQ_3 = \text{upper median},\nQ_1 = \text{ lower median}$

$Median:\n\text{If n is odd, then}\n\nMedian = \displaystyle(n+1)/(2)th ~term \n\n\text{If n is even, then}\n\nMedian = \displaystyle((n)/(2)th~term + ((n)/(2)+1)th~term)/(2)$

$Median ==(6^(th)+7^(th))/(2) (47+51)/(2) = 49$

$Q_1 =(3^(rd)+4^(th))/(2) = (43 + 44)/(2) = 43.5\n\nQ_3 =(9^(th)+10^(th))/(2)= (54 + 55)/(2) = 54.5$

IQR = $Q_3 -Q_1 =54.5-43.5= 11$

If every measurement is doubled, then, the IQR will also double itself.

Thus,

New IQR =

$2* \text{IQR}\n=2\TIMES 11\n=22$

Thus, the new IQR is 22.

Help with this problem (20 points)

Answers

Answer:

what problem? i dont see it

No problem here! Are you sure?

-3 = 15+4y round to nearst tenth

Answers

Answer:

y = - 4.5

Step-by-step explanation:

given the equation

- 3 = 15 + 4y ( subtract 15 from both sides )

- 3 - 15 = 15 - 15 + 4y ( simplify both sides )

- 18 = 4y ( divide both sides by 4 )

$(-18)/(4)$ = $(4)/(4)$ y , that is

- 4.5 = y

A certain genetic condition affects 8% of the population in a city of 10,000. Suppose there is a test for the condition that has an error rate of 1% (i.e., 1% false negatives and 1% false positives). Consider the values that would complete the table below.

Has condition Does not have condition totals

Test positive

Test negative

Totals

What is the probability (as a percentage) that a person has the condition if he or she tests positive? (Round your answer to one decimal place.)

Answers

Solution:

Population in the city= 10,000

As genetic condition affects 8% of the population.

8 % of 10,000

$=(8)/(100)* 10,000=800$

As, it is also given that, there is an error rate of 1% for condition (i.e., 1% false negatives and 1% false positives).

So, 1% false negatives means out of 800 tested who are found affected , means there are chances that 1% who was found affected are not affected at all.

So, 1% of 800 $=(1)/(100)* 800=8$

Also, 1% false positives means out of 10,000 tested,[10,000-800= 9200] who are found not affected , means there are chances that 1% who was found not affected can be affected also.

So, 1% of 9200 $=(1)/(100)* 9200=92$

1. Has condition Does not have condition totals = 800

2. Test positive =92

3. Test negative =8

4. Total =800 +92 +8=900

5. Probability (as a percentage) that a person has the condition if he or she tests positive= As 8% are found positive among 10,000 means 9200 are not found affected.But there are chances that out of 9200 , 1% may be affected

$=\frac{\text{1 percent of 9200}}{9200}\n\n ((1)/(100)* 9200)/(9200)=(92)/(9200)\n\n =0.01$