In quadrilateral ABCD, AD ∥ BC. Quadrilateral A B C D is shown. Sides A D and B C are parallel. The length of A D is 3 x + 7 and the length of B C is 5 x minus 9. What must the length of segment AD be for the quadrilateral to be a parallelogram? 8 units 16 units 31 units 62 unitsIn quadrilateral ABCD, AD ∥ BC. 9.
Answers
Answer:
31 units
Step-by-step explanation:
When the figure is a parallelogram, opposite sides have the same measure:
AD = BC
3x +7 = 5x -9 . . . . . . substitute given expressions
16 = 2x . . . . . . . . . . . add 9-3x
8 = x . . . . . . . . . . . . . divide by 2
Use this value of x in the expression for AD to find its required length:
AD = 3(8) +7 = 24 +7
AD = 31 . . . . units
The length of segment AD must be 31 units for ABCD to be a parallelogram.
Answer:
31
Step-by-step explanation:
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Tom ate 1/4 of a pizza. he divided the leftover pizza into pieces each equal to 1/12 of the original pizza. after he gave some friends 1 piece each, 1/6th
Answers
After adding one mile, the digits are {a, b, c, d, c, b}, so the relevant equation is
10c +b = 10d +c +1
After adding another mile, the digits are {a, b, c, c, b, e}, so the relevant equation is
100c +10b +e = 100d +10c +b +1
After another mile, the digits are {a, b, c, c, b, a}, so the relevant equation is
a = e +1
In summary, we have 3 equations in 5 unknowns.
b + 9c -10d = 1
9b +90c -100d +e = 1
a - e = 1
along with the constraints {a, b, c, d, e} ∈ {0, ..., 9}
_____
These have the solution {a, b, c, d, e} = {1, 9, 8, 8, 0}, so the odometer readings were
198888
198889
198890
198891
Answers
so
Answers
Answer:
d. Decrease
Step-by-step explanation:
A Type II error is when we fail to reject a false null hypothesis. Higher values of α make it easier to reject the null hypothesis, so choosing higher values for α can reduce the probability of a Type II error.
The consequence here is that if the null hypothesis is true, increasing α makes it more likely that we commit a Type I error (rejecting a true null hypothesis).
So using lower values of α can increase the probability of a Type II error.
Final answer:
Raising the level of significance in a hypothesis test from .01 to .05 would decrease the probability of making a Type II error. This is because as we become more accepting of risk in making a Type I error, we simultaneously reduce the risk of making a Type II error.
Explanation:
The level of significance in a hypothesis test is the probability that we are willing to accept for incorrectly rejecting the null hypothesis or making a Type I error. If the level of significance is raised, there is a higher chance we incorrectly reject the null hypothesis, increasing the chances of a Type I error. However, this also has an effect on the probability of committing a Type II error, which is to incorrectly accept the null hypothesis.
Specifically, when the level of significance of a hypothesis test is raised from .01 to .05, the probability of a Type II error (option b) will decrease. The reason for this is that increasing the level of significance or alpha means we are more likely to reject the null hypothesis. As we are more accepting of risk in terms of making a Type I error, we are less likely to make a Type II error, as the two error types often move in opposite directions. Thus, the answer to your question is d. The probability of a Type II error will decrease if the significance level is raised from .01 to .05.
Learn more about Hypothesis Testing here:
#SPJ3
Answers
ANSWE,LET two numbers be A and B then
A+B=52
A-B=14....linear equation in 2 variable
adding 2 eqns
2A=66... dividing both side by 2
A=33
and put A=33 in eqn A+B=52
B=52-33
B=19.
SO. LARGER NUMBER=33
Smaller number=19
Answers
Answer:
4.5
Step-by-step explanation: you divide 24 by what you do to get 6 which is 4 then you use 4 to divide 18 which is 4.5 or 4 and a half. Have A Great Day!
Using this rate, create an equation to represent the number of chocolate candies,
c
, in millions, the company can produce in
h
hours.
Answers
Answer:
f(x)=60c * 24h
Step-by-step explanation:
Hope this helped!