The acceleration of a moving vehicles is 10 metre per second square what does it means

Answers

Answer 1

Answer:

Answer:

Acceleration is the rate of change of velocity. What is commonly said as ‘ten meter per second squared’ can bee broken down into ‘ten meter per second per second.’ This gives us the true meaning of the term acceleration.

Just like ‘ten meter per second’ means increasing the displacement by ten meters every second, ‘ten meter per second per second’ means increasing the velocity by ten meters per second every second.

So, basically if you consider the case of a free fall motion, where ‘t’ stands for time and ‘v’ stand for velocity at that instant:

At,

t=0, v=0 m/s

t=1, v=0+10 m/s;

t=2, v=0+10+10 m/s;

t=3, v=0+10+10+10 m/s;

This can also be thought as a Arithmetic Progression where common difference ‘D’ is the acceleration(a), since it adds a 10 m/s to velocity every second and the first term ‘A’ stands for the initial velocity (u). Using this approach we can derive to the first equation of motion:

v = u + at

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Explanation:

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Answer 2

Answer:

It means that the vehicle's speed increases at the rate of 10m/s every second.

At any time, it's speed is 10 m/s faster than it was 1 second earlier.

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A minimum price, set by the government, that must be paid for a good or service is called a _____. A. price wall
B. price floor
C. price field
D. price ceiling

Answers

Answer:

B. Price floor

Explanation:

it is a price imposed by the government for a product , goods or commodity if the government feels that price is too low. In order to be effective Price floor must be more than the equilibrium price .

B: a price floor is the correct answer

The driver of a 1500 kg car, travelling on a highway, hits the brakes. A force of 12000 N stops the car in a distance of 64 m. how fast was the car going when the driver hit the brakes?

Answers

Answer:

$v = 32 m/s$

Explanation:

As per work energy theorem we know that work done by all the forces must be equal to change in kinetic energy of the car

So here when brakes are applied then work is done by the brakes which is equal to change in kinetic energy of the car

so we know that work done by the brakes is given as

$W = -12000 * 64$

$W = -768000 J$

now we will have

$W = 0 - (1)/(2)mv^2$

$-768000 = - (1)/(2)(1500) v^2$

$v = 32 m/s$

A light plane is headed due south with a speed relative to still air of 185 km/h. After 1 h, the pilot notices that they have covered only 135 km and their direction is not south but 75˚ south of east. What is the wind velocity?

Answers

Use the cosine rule to solve for the distance the wind pushed them to the east and because this all happened in an hour, you can say they travelled this distance per hour.

+-130 km due east which means the wind speed was +-130km/h.

So for example i used a^2=b^2+c^2-2bc(cos75) b will be the distance they travelled and c= 135cos75=35km now all you do is substitute in and you will get your distance that the wind pushed them to the east and because it was an hour of travel the distance as said before will be per hour.

Final answer:

The wind velocity can be calculated by vector subtraction of the plane's velocity relative to the ground (the observed travel path) and the plane's velocity relative to still air. This involves converting the velocities to their component forms along the east-west and north-south axes, performing the subtraction, and then converting back to a magnitude and direction.

Explanation:

This problem can be solved through the use of vector addition and subtraction. Let's denote the velocity of the plane as Vp, the velocity of the wind as Vw, and the resultant velocity (or the actual observed travel path) as Vr. These velocities are vectors, which mean they have both magnitude and direction.

Given that the plane had an airspeed of 185 km/h due south, which can be represented as Vp=185 km/h south. However, the actual path covered was Vr=135 km/h, 75° south of east. We can find Vw through the equation Vr = Vp + Vw, rearranged as Vw = Vr - Vp.

Following this calculation, we then need to convert these vector magnitudes and directions into components along the north-south and east-west axes. We then subtract corresponding components to find the wind velocity in terms of its north-south and east-west components, before finally converting these back into a magnitude and direction using Pythagoras' theorem and trigonometric functions.

Learn more about Physics of Wind Velocity here:

brainly.com/question/24253179

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Could you give me 4 examples of acceleration??

Answers

Certainly.

1). A driver presses the gas and the car speeds up.

2). A driver presses the brake and the car slows down.

3). A driver turns the steering wheel slightly. The car's speed doesn't change
as it goes around the curve.

4). A stone is tossed into the air. Gravity accelerates it from the moment it
leaves the thrower's hand until it hits the ground.

5). A new TV satellite is successfully launched and placed in a perfect circular
orbit around the Earth. The satellite's motion is accelerated forever, 24/7/365 .

"Acceleration" means any change in the speed or direction of motion. Any
object that's not moving at constant speed in a straight line is accelerated.

What unit of length is used to express the size of stars?

Answers

The size (radius, diameter) of stars is typically described
in terms of miles or kilometers.

The mass and volume of stars are described in kilograms and
cubic meters respectively, with scientific notation for the huge numbers.

Because the distances to stars are so large, it is useful to introduce some large ... The Light Year Distance Unit ... of 3 x 1010 cm/s in a vacuum, we can determine the length of a light year in centimeters

If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C? A. 0.002010812m3
B. 0.004021624m3
C. 0.002021624m3
D. 0.000010812m3

Answers

As per the question the volume of mercury is given as 0.002 m^3 at 20 degree Celsius.

We are asked to calculate the volume of the mercury at 50 degree Celsius.

This problem is based on thermal expansion of matter.

Let us consider the initial and final volume of the mercury is denoted as -

$v_(1) \ and\ v_(2)$

Let the initial and final temperature of the mercury is denoted as -

$T_(1)\ and \ T_(2)$

As per question

$v_(1) =0.002 m^3$ $v_(2) =?$

$T_(1) =20^0 C$ $T_(2) =50^0 C$

The change in temperature is

$T_(2) -T_(1)$

$= 50^0 C -20^0 C$

$= 30^0 C$

Mercury is a fluid.So we have to apply volume expansion of liquid .

The coefficient of of volume expansion of mercury $[ \gamma ]$ at 20 degree Celsius is 0.00018 per centigrade.

As per volume expansion of liquid,

$V_(T) = v_(1) [1 +\gamma [T_(2) -T_(1) ]]$

Here $V_(T)$ is the volume at T degree Celsius.

Hence volume at 50 degree Celsius is calculated as-

$v_(2) =v_(1) [1+\gamma[50-30]]$

$= 0.002[1+0.00018*30]$

$=0.0020108m^3$ [ans]

As per the options given in the question ,option A is close to the calculated value. So option A is right.

The answer to this question lies in understanding the Combined Gas Law in chemistry, which combines Boyle's, Charles', and Gay-Lussac's gas laws. This law shows the relationship between pressure, volume, and temperature of gases and is represented by the equation P1V1/T1 = P2V2/T2. Changes in pressure (P) and volume (V) are directly proportional to one another, but these are inversely proportional to changes in temperature (T). This question must assume that pressure is constant, so the Ps cancel out and the equation becomes V1/T1 = V2/T2. Additionally, temperature should be converted to Kelvins (K) by adding 273 to the temperature in Celsius (so 20 C = 293 K, and 50 C = 323 K). If V1 = 0.002 and T1 = 293 and T2 = 323, then we solve the equation as V2 = T2*V1/T1 or V2 = (323*0.002)/293, so the answer is approximately equal to 0.0022... or answer (C).

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