A cessna 150 airplane has a takeoff speed of 28 m/s. determine the minimum length of the runway which would be required for the plane to take off if it averages an acceleration of 1.9 m/s/s.

Answers

Answer 1
Answer:

Given: Takeoff Speed (u) = 28 m/s

Final velocity (v) = 0.0 m/s

Acceleration (a) = 1.9 m/s²

To calculate: The minimum length of runway (s) =?

Solution: Apply 3rd kinematic equation of motion

                                 v² = u² - 2as

Or,                              s =  ( u² -  v²) / 2 a

Or,                              s =  ( 28² - 0²) / 2 × 1.9 m

Or,                              s =  206.3 m

Hence, the required minimum length of the runway will be 206.3 m

Answer 2
Answer:

Final answer:

To determine the minimum length of the runway a Cessna 150 airplane would need to take off, you can use a kinematic equation. Plugging in a final velocity of 28 m/s, initial velocity of 0 m/s (since the plane starts from rest), and acceleration of 1.9 m/s/s gives an answer of approximately 207.11 meters.

Explanation:

The subject of your question is related to physics, specifically, kinematics, which studies the motion of objects. In your case, a Cessna 150 airplane needs to accelerate from rest to a speed of 28 m/s for takeoff, with an average acceleration of 1.9 m/s/s, and you're trying to find out the minimum length of the runway required. For this, we can use a kinematic equation.

The equation we can use is the following: v^2 = u^2 + 2as, where v is the final velocity (28 m/s), u is the initial velocity (0 m/s since the plane starts from rest), a is the acceleration (1.9 m/s/s), and s is the distance we want to find out.

When you plug in the known values into the equation, you will get: (28)^2 = (0)^2 + 2 * 1.9 * s. After rearranging the equation, you will have s = [(28)^2 - (0)^2] / 2*1.9 = 207.11 m. Therefore, the minimum length of the runway required for the Cessna 150 airplane to take off is approximately 207.11 meters, assuming constant acceleration and no other factors interfering.

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Answers

Answer:

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