Which graph represents the following piecewise defined function?

Answers

Answer 1

Answer:

The graph that represents the following piecewise defined function is of f(x) = x; x <-2 , -2; -2 < or = to x < or = to 1, x-3; x> or = to 1 is the first graph (Image attached)

What is a piecewise function?

A piecewise function is known to be a function that has been formed from pieces of a lot of functions over a lot of intervals.

An example, we can say a piecewise function f(x) where f(x) = -7 when -7 < x ≤ -4, f(x) = 4 when -4 < x ≤ -1, and f(x) = -5 when -1 <x ≤ 7.

The option that best explain the piecewise defined function is the image attached.

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Answer 2

Answer:

Answer:

A on Edge

Step-by-step explanation:

Just took the test and got a 100

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Which functions are symmetric with respect to the origin?y = arcsinx and y = arccosx
y = arccosx and y = arctanx
y = arctanx and y = arccotx
y = arcsinx and y = arctanx

Answers

The function are symmetric with respect to the origin is y = arcsinx and y = arctanx and this can be determined by using the trigonometric property.

The following steps can be used in order to determine which functions are symmetric with respect to the origin:

Step 1 - Check all the options given in order to determine which functions are symmetric with respect to the origin.

Step 2 - Substitute (x = 0) in option a), that is:

$\rm y = sin^(-1)(0)=0$

$\rm y = cos^(-1)(0)=1.57$

Step 3 - Substitute (x = 0) in option b), that is:

$\rm y = cos^(-1)(0)=1.57$

$\rm y = tan^(-1)(0)=0$

Step 4 - Substitute (x = 0) in option c), that is:

$\rm y = tan^(-1)(0)=0$

$\rm y = cot^(-1)(0)=1.57$

Step 5 - Substitute (x = 0) in option d), that is:

$\rm y = tan^(-1)(0)=0$

$\rm y = sin^(-1)(0)=0$

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Answer:

The correct option is;

y = arcsinx and y = arctanx

Step-by-step explanation:

The given options are;

1) y = arcsinx and y = arccosx

Here, we have at the origin, where x = 0, arccosx ≈ 1.57 while arcsinx = 0

Therefore arccosx does not intersect arcsinx at the origin for it to be symmetrical to arcsinx or the origin

2) y = arccosxy and y = arctanx

Here arctanx = 0 when x = 0 and arcos x = 1.57 when x = 0 therefore, they are not symmetrical

3) y = arctanx and y = arccotx

Similarly, At x = 0, arccotx = 1.57 therefore, they are not symmetrical

4) y = arcsinx and y = arctanx

Both functions arcsinx and arctanx pass through the origin and their shapes are similar but inverted as they go from negative to positive.

If it takes 3 teaspoons of salt to make 15 muffins, then how much salt is needed to make 50 muffins?

Answers

When you look at this problem you have to think, how many teaspoons do you need for 1 cupcake so you would divide 3 by 15 and get .....

Give me Colonel Sanders' Kentucky Fried Chicken.

Answers

Answer:

kk where do you live lol

Step-by-step explanation:

Answer:

i got u

Step-by-step explanation:

go to your nearest kfc and order the migos

The endpoints of AB are A(9,4) and B(5,-4). The endpoints of its image after a dilation ar A(6,3) and B(3,-3). a. explain how to find te scale factor. b. locate the center of dilation. show your work

Answers

Look at the picture for the answer.

Final answer:

The scale factor of the dilation is calculated by dividing the length of the line after dilation by the length of the initial line. The length of a line is calculated using the distance formula. The center of dilation is the point from which the shape scales, but we can't determine its location without more information.

Explanation:

To find the scale factor of a dilation in a two-dimensional plane, we divide the length of the line after dilation by the length of the initial line. The length of a line can be calculated using the distance formula which is √[(x₂ - x₁)² + (y₂ - y₁)²].

For AB, the distance will be √[(5 - 9)² + (-4 - 4)²] = √[(-4)² + (-8)²] which equals √80. For A'B', the distance will be √(3 - 6)² + (-3 - 3)² = √[(-3)² + (-6)²] which equals √45. The scale factor (k) of the dilation is the ratio of these distances, so k = √45 / √80 which simplifies to √(9/16) or 3/4.

Unfortunately, without more information, such as a fixed point in the original shape, we can't determine the exact location of the center of dilation. But, conceptually, it's the point that the shape is scaling towards or away from during the dilation.

Learn more about Dilation in Mathematics here:

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Help on a question geometry

Answers

2log 3 = log 3^2 = log 9 ;
log 5 + 2log 3 = log 5 + log 9 = log( 5 * 9 ) = log 45 ;
log ( x - 12 ) = log 45;
x - 12 = 45 ;
x = 12 + 45 ;
x = 57 ;
But, x - 12 > 0;
And, 57 - 12 > 0 ;
The solution is 57 .

$D:x-12>0\nD:x>12\n\log_3(x-12)=\log_35+2\log_33\n\log_3(x-12)=\log_35+\log_33^2\n\log_3(x-12)=\log_35+\log_39\n\log_3(x-12)=\log_3(9\cdot5)\n\log_3(x-12)=\log_345\nx-12=45\n\boxed{x=57}$

Please help

first one to answer or if correct will be marked brainliest

Answers

Answer:

1/6 for number 1

4/6 but 1/6 for number 2

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