The equation 36x^2 + 25 = 0 possesses no real solutions; however, it yields two complex roots: x = (5/6)i and x = -(5/6)i.
The equation provided, 36x^2 + 25 = 0, is a quadratic equation in one variable, x. To solve it, we'll first isolate the x^2 term:
36x^2 = -25
Next, we'll divide both sides by 36:
x^2 = -25/36
Taking the square root of both sides, we get:
x = ±√(-25/36)
Since the square root of a negative number is imaginary, there are no real solutions to this equation. This means that the equation 36x^2 + 25 = 0 has no real roots, but it does have complex roots in the form of x = ±(5/6)i, where i is the imaginary unit.
The equation 36x^2 + 25 = 0 has no real solutions, but it does have two complex solutions: x = (5/6)i and x = -(5/6)i.
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If the next number is 125% of the previous number, that means that the previous number is increasing by 25% each time.
The multiplier for increasing by 25% is:
(100 + 25) ÷ 100 = 1.25
So on day one, there are 64 responses. That means on day two, there will be:
---> 64 x 1.25 = 80 responses
On day 3, there will be:
---> 80 x 1.25 = 100 responses
Finally, on day 4, there will be:
---> 100 x 1.25 = 125 responses
A quicker way of getting this would be to do:
64 x 1.25³ since you are multiplying by 1.25 3 times
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Answer:
125 responses
Answer:
125
Step-by-step explanation:
meh . . .
B. y = x – 6
C. y = x + 6
D. y = x
Given:
Distance between two buildings = feet apart.
Distance between highway and one building = feet.
Distance between highway and second building = feet.
To find:
The standard form of the polynomial representing the width of the highway between the two building.
Solution:
We know that,
Width of the highway = Distance between two buildings - Distance of both buildings from highway.
Using the above formula, we get the polynomial for width (W) of the highway.
Combining like terms, we get
Therefore, the width point highway is .
The correct standard form of the polynomial equation that represents the width of the highway between the two buildings is: .
Given:
Distance between the building:
Building 1 distance from highway:
Building 2 distance from highway:
To find the Width of the highway between two building:
Add the distances of the buildings from the highway.
Let's call the width of the highway "w"
Distance between the two buildings:
=
Width of the highway:
The polynomial equation is .
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The width of the rectangular lot is 33 meters and the length of the rectangular lot is 37 meters.
Let, the width of the rectangular lot is W meters.
According to the problem, the length of the rectangular lot is 4 meters more than the width, so the length would be (W + 4) meters.
Now, we can use the formula for the perimeter of a rectangle:
Perimeter = 2 * Length + 2 * Width
Given that the perimeter is 140 meters, we can set up the equation:
140 = 2 * (W + 4) + 2 * W
Now, solve for W:
140 = 2W + 8 + 2W
Combine like terms:
140 = 4W + 8
Subtract 8 from both sides:
132 = 4W
Finally, divide by 4:
W = 33
So, the width of the rectangular lot is 33 meters.
Now, we can find the length:
Length = Width + 4
Length = 33 + 4
Length = 37
Therefore, the length of the rectangular lot is 37 meters.
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the length is 37 and the width is 33 if you add 33+33+37+37 you get 140
c. 3
b. –3
d. 87
A: Explanatory: Latitude
Response: Daylight hours
B. Explanatory: Latitude
Response: Average temperature
C. Explanatory: Daylight hours
Response: Latitude
D. Explanatory: Time of year
Response: Daylight hours