Answer:
a. True
Explanation:
Distillation process is a process that is used to separate the components or the substances from the liquid mixtures by using selectively boiling and condensation.
While fractional precipitation is a process which separates the ions from solution based on the different solubilities.
Therefore, the answer is true.
Answer:
The ionic bond in NaCl are stronger than the stronger than the dispersion forces in HCl.
The hydrogen bonds in H2O are stronger than the dispersion forces in H2Se
Hydrogen bonds in NH3 are stronger than the dipole-dipole attractions in PH3.
Hydrogen bonds in HF are stronger than the dispersion forces in F2
Explanation:
Ionic bonds occur in molecules with high differences in their electronegative value where there are actual transfer of electrons. HCl has a bond which is involved in the sharing of electrons.
Hydrogen bonds are present in H2O which is stronger than the dispersion forces.
PH3 is a larger molecule with greater dispersion forces than ammonia, NH3 has very polar N-H bonds leading to strong hydrogen bonding. This dominant intermolecular force results in a greater attraction between NH3 molecules than there is between PH3 molecules.
F2 is a non-polar molecule, therefore they have London dispersion forces between molecules while HF has a hydrogen bond because F is highly electronegative.
Ionic bonds are stronger than dispersion forces in HCl, while hydrogen bonds are stronger than dispersion forces in H2Se, PH3, and F2.
In the given sentences, the blanks represent the types of intermolecular forces. The options given are ionic bonds, hydrogen bonds, dispersion forces, and dipole-dipole attractions. Ionic bonds are stronger than the dispersion forces in HCl. Hydrogen bonds are stronger than the dispersion forces in H2Se. Hydrogen bonds are stronger than the dipole-dipole attractions in PH3. Hydrogen bonds are stronger than the dispersion forces in F2.
#SPJ3
Br-1
(NO3)-1
(SO3)2
Answer:
D. For the atoms lower in the periodic table, the valence electrons are in higher energy levels and farther from the nucleus.
Explanation:
Atomic radius increases down the group because down the group, there an increase in the number of principle energy levels occupied. Now, these higher principal energy levels are made up of orbitals that are larger than the orbitals from the lower energy levels in size.
Therefore, the effect of this is that the greater number of principal energy levels will outweigh the increase in nuclear charge since nuclear charge also increases down the group and this in turn makes the atomic radius to increase as we go down the group.
Answer: C. For the atoms lower in the periodic table, the balance electrons are in higher energy levels and farther from the nucleus.
Explanation: As the valance electrons orbit farther from the nucleus the energy level increases from the top to the bottom of the periodic table. So the atoms lower in the periodic table, the balance electrons are in higher energy levels and farther from the nucleus, which result in an increase in the atomic radius.
Answer:
It lights on fire
Explanation:
The friction sparks the match causing it to go on fire.
Answer:
K₂SO₄(aq) + 2AgNO₃ (aq) → 2KNO₃(aq) + Ag₂SO₄ (s) ↓
2Ag⁺ (aq) + SO₄⁻²(aq) ⇄ Ag₂SO₄ (s) ↓
Explanation:
Our reactants are: K₂SO₄ and AgNO₃
By the solubility rules, we know that sulfates are insoluble when they react to Ag⁺, Pb²⁺, Ca²⁺, Ba²⁺, Sr²⁺, Hg⁺
We also determine, that salts from nitrate are all soluble.
The reaction is:
K₂SO₄(aq) + 2AgNO₃ (aq) → 2KNO₃(aq) + Ag₂SO₄ (s) ↓
2Ag⁺ (aq) + SO₄⁻²(aq) ⇄ Ag₂SO₄ (s) ↓