Hence an aerosol is a colloidal solid or liquid suspended in a gas Smoke or fog, for example.
Aerosol is a system of equally dispersed, finely divided liquid or solid particles passing through a gas, often air. Dust and other aerosol particles, which serve as the nuclei for condensation and freezing, are crucial to the precipitation process.
Secondary aerosols develop when gas is converted into a particle, whereas primary aerosols are made up of particles that are added directly to the gas. Key aerosol categories include sulfates, organic carbon, black carbon, nitrates, mineral dust, and sea salt. These substances typically clump together to create complicated mixtures.
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Answer:
An aerosol is a colloidal A. liquid suspended in a C. gas.
Explanation:
Answer:
0.1 M
Explanation:
The overall balanced reaction equation for the process is;
IO3^- (aq)+ 6H^+(aq) + 6S2O3^2-(aq) → I-(aq) + 3S4O6^2-(aq) + 3H2O(l)
Generally, we must note that;
1 mol of IO3^- require 6 moles of S2O3^2-
Thus;
n (iodate) = n(thiosulfate)/6
C(iodate) x V(iodate) = C(thiosulfate) x V(thiosulfate)/6
Concentration of iodate C(iodate)= 0.0100 M
Volume of iodate= V(iodate)= 26.34 ml
Concentration of thiosulphate= C(thiosulfate)= the unknown
Volume of thiosulphate=V(thiosulfate)= 15.51 ml
Hence;
C(iodate) x V(iodate) × 6/V(thiosulfate) = C(thiosulfate)
0.0100 M × 26.34 ml × 6/15.51 ml = 0.1 M
To determine the moles of KIO_3 titrated, use the balanced equation 2 KIO_3 + 5 Na_2S_2O_3 + 6 HCl → 3 I_2 + 6 NaCl + 6 NaClO + 3 H_2O. Therefore, 0.001551 mol of KIO_3 were titrated.
To determine the moles of KIO3 titrated, we need to use the balanced equation for the reaction:
2 KIO3 + 5 Na2S2O3 + 6 HCl → 3 I2 + 6 NaCl + 6 NaClO + 3 H2O
From the equation, we can see that 2 moles of KIO3 react with 5 moles of Na2S2O3. Therefore, the moles of KIO3 titrated can be calculated using the following proportion:
(0.0100 M KIO3 / 1 L) * (15.51 mL / 1000 mL) * (2 mol KIO3 / 5 mol Na2S2O3) = 0.001551 mol KIO3
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a Chromatin
b Centromere
C Centriole
Check it
Sister chromatids are held together at the centromere on a duplicated chromosome. The centromere serves as the point of attachment. Chromatin and centrioles do not serve this function. The correct option is b) Centromere.
Two identical sister chromatids are held together at the centromere on a duplicated chromosome. The centromere serves as the point of attachment for sister chromatids. During cell division, the spindle fibers attach themselves to the centromere to pull apart the sister chromatids into two separate cells. This process helps ensure that each new cell receives an identical and complete set of chromosomes. Neither chromatin nor centriole holds sister chromatids together. Chromatin refers to the material chromosomes are made up of, which includes DNA and protein, while centrioles are involved in cell division. In summary, the precise answer to your question is option b) Centromere.
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(b)CHCL3
(c)C12H10O16
(d)CH3CH2CH2CH2CH3
The mass of carbon in is 12.007 amu, is 12.007, is 144.084 amu, and is 60.035 amu.
The mass has been given as the sum of the atomic mass unit in the compound. The mass of 1 atom of carbon is 12.007 amu.
The mass of carbon in the following compounds is given as:
The number of Carbon units = 1
The mass of carbon in compound = 12.007 amu
The number of Carbon units = 1
The mass of carbon in the compound = 12.007 amu
The number of carbon units =12
The mass of carbon in the compound:
The number of carbon units = 5
The mass of carbon in the compound:
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Answer:
The atomic mass of carbon (C) is 12.0107 amu, so if you want to calculate the total mass in each molecule, you just need to multiply the number of carbon atoms in the substance by 12.017. In (a) there is one atom of C, (b) have also one atom of C, (c) have 12 atoms of C, and (d) have five atoms of C. Thus, the total mass (amu) of carbon is:
(a) 12.017 amu
(b) 12.017 amu
(c) 144.204 amu
(d) 60.085 amu
why?
Answer:
Answer is cerebellum. And this is the right answer
Answer:
6.58
Explanation:
Answer:
the awnser is kilograms(Kg)