MATHEMATICS MIDDLE SCHOOL

What is the value of the expression 1/4^-3 ?A.
12

B.
64

C. 1/64


D. 1/12

Answers

Answer 1
Answer: (1)/(4^(-3))=(1)/((1)/(4^3))=4^3=\boxed{64}

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Dmitri wants to cover the top and sides of the box shown with glass tiles that are 5mm square. How many tiles does he need? ( The length is 15cm, the width is 20cm and the height is 9cm).

Answers

Answer:

372

Step-by-step explanation:

We are given that the dimensions of the box are,

Length = 15 cm, Width = 20 cm and Height = 9 cm.

We know that the box represents a cuboid.

Since, surface area of a cuboid = L×W + 2×L×H + 2×W×H

Thus, the surface area of the box = 15×20 + 2×15×9 + 2×20×9

i.e. Surface area = 300 + 270 + 360

i.e. Surface area = 930.

Thus, the surface area of the box is 930 cm² i.e. 9300 mm².

Further, the sides of the tiles are 5 mm and the tile represents a square.

So, the surface area of the tile = 5 × 5 = 25 mm².

This gives us that,

Number of tiles required to cover the box = (9300)/(25) = 372.

Hence, Dmitri requires 372 tiles to cover the box.
The Surface Area = lw + 2lh + 2wh;
The Surface Area = 15*20 + 2*15*9 + 2*20*9;
The Surface Area = 300 + 270 + 360;
The Surface Area = 570 + 360;
The Surface Area = 930cm^2;
The surface of glass tile is 5 × 5 = 25 cm^2;
Then, 930 ÷ 25 = 37.2;
He need 38 tiles to cover the top and sides of the box shown.

Write the standard form of the equation of each line. How do I find the slope and y-intercept with the graph for problem 6???

Answers

the standard form for an equation is y=mx+b. You find the slope by using the formula of rise over run. This means that for problem 6 you first look to see if its positive or negative slope. The slope is positive if the line is going uphill and if its going downhill its negative. The slope would be negative for number 6 because it is going downhill. Then for the actualy slope you would start with rise. So you look at the point (0,1) and go up 3 until you hit the line of the other point and run over 2. So your slope would be -3/2.

Final answer:

The slope and y-intercept of a linear equation can be identified directly from the graph. In this case, the y-intercept is 9 and the slope is 3, making the equation of the line y = 3x + 9.

Explanation:

In Mathematics, we often work with linear equations, which can be represented graphically as a straight line. The slope and y-intercept are two key aspects of this equation and can be obtained directly from the graph. Specifically for problem 6, your line graph has x on the horizontal axis and y on the vertical axis, and intersects the y-axis at the point (0,9). This tells us that the y-intercept (represented by b in the equation) is 9. Furthermore, the slope (represented by m in the equation) is the rise over run, or change in y over change in x. In this case, for every 1 unit increase in x, y increases by 3 units, so the slope is 3. Therefore, the standard form of the line equation would be "y = 3x + 9."

Learn more about slope and y-intercept here:

brainly.com/question/18492360

#SPJ2

Four students spent $12 on school lunch. At this rate find the amount 10 students would spend on the same school lunch.

Answers

30.004 =124=122=612+12+6 = 30

Find the value of x^3 + y^3 – 12xy + 64 when x + y = (-4)

Answers

Answer:

0

Step-by-step explanation:

Using the algebraic expansion

x³ + y³ = (x + y)³ - 3xy(x + y)

Given

x³ + y³ - 12xy + 64

= (x + y)³ - 3xy(x + y) - 12xy + 64

Substitute x + y = - 4 into the expression

= (- 4)³ - 3xy(- 4) - 12xy + 64

= - 64 + 12xy - 12xy + 64

= 0

Help me please I beg you :(

Answers

For the first p can be positive negative or zero and for the second 0.0000131 i cant do the last idk too well sorry 

Help! need these answers filled in for school asap

Answers

Answer:

Given : JKLM is a rectangle.

Prove: JL ≅ MK

Since, by the definition of rectangle all angles of rectangles are right angle.

Thus, In rectangle JKLM,

∠ JML and  ∠KLM are right angles.

⇒ ∠ JML ≅ ∠KLM

Since, JM ≅ KL   (Opposite sides of rectangles are congruent)

ML ≅ ML  ( Reflexive )

Thus, By SAS congruence postulate,

Δ JML ≅ Δ KLM

⇒ JL ≅ MK  ( because corresponding parts of congruent triangles are congruent)

Hence proved.
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