Whta is the sum of the the largest tow prime numbers that are less than 10

1) Find the length of the diagonals of the greater rhombus

NJ=9 units

XY=6 units

Find the the ratio

NJ/XY=9/6-------> 3/2

2) Find the length of the diagonals of the smaller rhombus

HS=6 units

ZC=4 units

Find the the ratio

HS/ZC=6/4-------> 3/2

so

NJ/XY=HS/ZC--------> the rhombus are similar

the scale factor is equal to ------> 3/2=1.5

measure greater rhombus =scale factor*measure smaller rhombus

measure greater rhombus =1.5*measure smaller rhombus

measure smaller rhombus=(measure greater rhombus/1.5)

therefore

the answer is

Yes , they are a scaled copies and the scale factor is equal to 1.5

Hi!

y = kx

k = y/x

In this case:

k = 4/8 = 3/6 = 2/4 = 1/2

The answer is A. 1/2

Hope this helps!

Hello!

The answers are:

3. Addition property of equality

4. - Simplification

7.

Why?

To solve the problem, we need to start with the result of the second step:

So,

For the step 3:

Then, for the 3rd step, we have to apply the addition property of equality.

The addition property of equality states that if we add a term to one side of the equality, we need to add it to the other side of the equality, in order to not alterate the equality.

Then, applying the property, we have:

Adding 7 to both sides, we have:

For the step 4:

Now, for the 4th step, we have to simplify the expression:

Then, simplifying, we have:

For the step 7:

Simplificating, we divide each side of the equality by 6:

Have a nice day!

Answer:

No, it is not.

Step-by-step explanation:

Answer: Ues

Step-by-step explanation:

1. Make sure you are paying attention to the tenths place

Answer:

x = π/2 + πk

Step-by-step explanation:

cot² x csc² x + 2 csc² x − cot² x = 2

Multiply both sides by sin² x:

cot² x + 2 − cos² x = 2 sin² x

Add cos² x to both sides:

cot² x + 2 = 2 sin² x + cos² x

Pythagorean identity:

cot² x + 2 = sin² x + 1

Subtract 1 from both sides:

cot² x + 1 = sin² x

Pythagorean identity:

csc² x = sin² x

Multiply both sides by sin² x:

1 = sin⁴ x

Take the fourth root:

sin x = ±1

Solve for x:

x = π/2 + 2πk, 3π/2 + 2πk

Which simplifies to:

x = π/2 + πk