MATHEMATICS COLLEGE

Michelle bought five packs of crayons for $13.75.What is the cost of a pack of crayons, in dollars, if all the packs cost the same?

Help please :/

Answers

Answer 1

Answer:

Answer:

$68.75

Step-by-step explanation:

$13.75 times 5 crayon boxes

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Find the slope Y=5x+12

Answers

Answer: The slope = 5.

Step-by-step explanation:

The equation of a line in the slope -intercept form is given by :-

$y=mx+c$

,where m= slope , c= y-intercept.

The slope of a line represents the rate of change of y with respect to x.

Given: Equation of line : Y= 5x+12

Here Slope (m)=5

Hence, the slope = 5.

Hi!

$\spadesuit$ We're given an equation in slope-intercept form:

$\clubsuit~~~\Large\boldsymbol{y=mx+b} ~~~\clubsuit$

Where:

$\diamondsuit~~~\large\boldsymbol{m- > slope}$

$\diamondsuit~~\large\boldsymbol{b- > y-intercept}$

Notes:

Please remember that the slope is the coefficient of x (the number that comes just before x; in 5x, the coefficient of x is 5), and the y-intercept is added to or subtracted from the slope.

Therefore,

$\stackrel{\heartsuit}{\boxed{\boxed{\textsc{Answers:}\begin{cases}\bold{Slope:5}\n\bold{12}\end{cases}}}}$

Cheers!!

I hope that the explanation helped you out! :D

If you need any explanation or clarification, please let me know!

Write an equation to solve for x.

Please provide steps

Answers

Answer:

x = 50

Step-by-step explanation:

= a straight line is always equal to 180 degrees

= 180 -30 degrees = 150

= 150/3

=50

Please help me with this problem

Answers

I think the answer is A. Hope this help

A is the answer
So your welcome

A certain test preparation course is designed to help students improve their scores on the MCAT exam. A mock exam is given at the beginning and end of the course to determine the effectiveness of the course. The following measurements are the net change in 6 students' scores on the exam after completing the course: 19, 15, 9, 17, 7, 16. Using these data, construct a 95% confidence interval for the average net change in a students's score after completing the course. Assume the population is approx. normal.Step 1. calculate the sample mean for the given sample data (round answer to 1 decimal place)Step 2. Calculate the sample standard deviation for the given sample data ( round answer to 1 decimal place)Step 3. Find the critical value that should be used in constructing the confidence interval. ( round answer to 3 decimal placed)Step 4. construct the 95% confidence interval (round answer to 1 decimal place)

Answers

Answer:

1) $\bar X =(\sum_(i=1)^n X_i)/(n)=13.8$

2) $s=\sqrt{(\sum_(i=1)^n (X_i -\bar X)^2)/(n-1)}=4.8$

3) $t_(\alpha/2)=2.571$

4) The 95% confidence interval would be given by (8.8;18.8)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We can calculate the sample mean and sample deviation with the following formulas:

Step 1. calculate the sample mean for the given sample data (round answer to 1 decimal place)

$\bar X =(\sum_(i=1)^n X_i)/(n)=13.8$

Step 2. Calculate the sample standard deviation for the given sample data ( round answer to 1 decimal place)

$s=\sqrt{(\sum_(i=1)^n (X_i -\bar X)^2)/(n-1)}=4.8$

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n=6 represent the sample size

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_(\alpha/2)(s)/(√(n))$ (1)

Step 3. Find the critical value that should be used in constructing the confidence interval. ( round answer to 3 decimal places)

In order to calculate the critical value $t_(\alpha/2)$ we need to find first the degrees of freedom, given by:

$df=n-1=6-1=5$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,5)".And we see that $t_(\alpha/2)=2.571$

Step 4. construct the 95% confidence interval (round answer to 1 decimal place)

Now we have everything in order to replace into formula (1):

$13.8-2.571(4.8)/(√(6))=8.8$

$13.8+2.571(4.8)/(√(6))=18.8$

So on this case the 95% confidence interval would be given by (8.8;18.8)

A lightning bolt is graphed on the coordinate plane below. A rotation of this lightning bolt 270° clockwise would place it in which quadrant?A. Quadrant I (x, y)B. Quadrant II (-x, y)C. Quadrant III (-x, -y)D. Quadrant IV (x, -y)

Answers

Explanation

From the image, it can be seen that the initial position of the lightning bolt is in the first quadrant.

After it has been rotated 270 degrees clockwise, it moves by three quadrants and stays in the second quadrant

Answer: Option B

In the final round of a TV game show, contestants have a chance to increase their current winnings of $1 million to $2 million. If they are wrong, their prize is decreased to $500,000. A contestant thinks his guess will be right 50 percent of the time. Should he play