A city is planning to build a parking lot for fans who drive to football games and hockey matches. For every 13 parking spaces reserved flr hockey fans,football fans will have 30 . How many spaces will football fans have If hockey fans have 1,950
Answers
The problem statement tells us parking spaces are in the proportion ...
... (football spaces)/(hockey spaces) = 30/13 = (football spaces)/1950
Multiplying by 1950 give the solution
... football spaces = 1950·30/13 = 4500
Football fans will have 4500 spacs
Hockey : Football = 13 : 30
[1950 ÷ 13 = 150]
Hockey : Football = 13x150 : 30x150 = 1950 : 4500
Answer: 4500
Related Questions
line in the Cartesian plane passes through the points (1, 3) and (5, 4). What is the slope of the line?
Please help fast!!! I need help with question attached!!
prove that if f is a continuous and positive function on [0,1], there exists δ > 0 such that f(x) > δ for any x E [0,1] g
An investigative bureau uses a laboratory method to match the lead in a bullet found at a crime scene with unexpended lead cartridges found in the possession of a suspect. The value of this evidence depends on the chance of a false positive positive that is the probability that the bureau finds a match given that the lead at the crime scene and the lead in the possession of the suspect are actually from two differant melts or sources. To estimate the false positive rate the bureau collected 1851 bullets that the agency was confident all came from differant melts. The using its established ctireria the bureau examined every possible pair of bullets and found 658 matches. Use this info to to compute the chance of a false positive.
Answers
Answer:
the probability that he length of this component is between 4.98 and 5.02 cm is 0.682 (68.2%)
Step-by-step explanation:
Since the random variable X= length of component chosen at random , is normally distributed, we can define the following standardized normal variable Z:
Z= (X- μ)/σ
where μ= mean of X , σ= standard deviation of X
for a length between 4.98 cm and 5.02 cm , then
Z₁= (X₁- μ)/σ = (4.98 cm - 5 cm)/0.02 cm = -1
Z₂= (X₂- μ)/σ = (5.02 cm - 5 cm)/0.02 cm = 1
therefore the probability that the length is between 4.98 cm and 5.02 cm is
P( 4.98 cm ≤X≤5.02 cm)=P( -1 ≤Z≤ 1) = P(Z≤1) - P(Z≤-1)
from standard normal distribution tables we find that
P( 4.98 cm ≤X≤5.02 cm) = P(Z≤1) - P(Z≤-1) = 0.841 - 0.159 = 0.682 (68.2%)
therefore the probability that he length of this component is between 4.98 and 5.02 cm is 0.682 (68.2%)
Answers
Answer:
Step-by-step explanation:
1.25 m + 3.50 = 12.35
3.50 the flat fee you just add up to the total
1.25 m you can see it depends on m the miles
12.35 is the total
Answers
Answer:
3 1/4
Step-by-step explanation:
You can do a equation:
133x=432 1/4
Which would give you 3.25 but in fraction form it is 3 1/4
Hope this helped!
Let f be a function given by f(x)=-4x-1.
Find and simplify f(x+3)
Answers
Answer:
f=-
Step-by-step explanation:
Divide each term in f(x+3)=−4x−1 by x+3 and simplify.
Mark as brainlist if you find this helpful
Answers
Answer:
x = 115° , y = 140° , z = 40°
Step-by-step explanation:
40° , x and 25° lie on a straight line and sum to 180° , that is
x + 40° + 25° = 180°
x + 65° = 180° ( subtract 65° from both sides )
x = 115°
z and 40° are vertically opposite angles and are congruent , then
z = 40°
y and z lie on a straight line and sum to 180° , that is
y + 40° = 180° ( subtract 40° from both sides )
y = 140°
Answers
Answer:
The correct answer is $800.
Step-by-step explanation:
Let the length and width of the field be equal to l meters and b meters respectively and l > b.
Area of the field is given by l × b = 400 square meters.
The river is supposed to be along the longest side so that the price of fencing the other three sides is minimum. Thus the total perimeter of the fence is b+ b+ l = 2b+l.
Total cost for fencing the other sides of the field = $ 10 × (2b + l)
The wall is supposed to be perpendicular to the river and thus the length of the wall is b meters.
Total cost for the wall is $ 20 × b
Therefore, the total price for making the field is given by
C = 10 × (2b + l) + 20 × b
⇒ C = 40b + 10l
⇒ C = + 10l
To minimize the cost we differentiate the cost with respect to l and equate it to zero.
= 0 = -
+ 10
⇒ = 1600
⇒ l = 40 ; [ negative sign neglected as length cannot be negative ]
⇒ b = 10
The second order derivative of C is positive giving the minimum value of the cost.
Thus the minimum cost required to make the field is given by $800.
Final answer:
To find the lowest possible cost to build the field, we need to determine the dimensions that will yield the minimum perimeter and then calculate the total cost of building the field. By differentiating the cost equation and solving for x, we can find the dimensions that minimize the cost.
Explanation:
To find the lowest possible cost to build the field, we need to determine the dimensions that will yield the minimum perimeter. Since the area of the field is 400 square meters and it will be divided into two equal halves by a brick wall, each half will have an area of 200 square meters. Let's say the length of the field is x meters. Then the width of each half will be 200/x meters.
The perimeter of the field is the sum of the lengths of the three sides:
Perimeter = 2x + 200/x + 200/x
Now, we can define the total cost to build the field as:
Total Cost = Cost of wall + Cost of fence
Cost of wall = 2x * $20 (since there are two halves)
Cost of fence = (2x + 200/x + 200/x) * $10 (since there is a fence on three sides)
Therefore, the total cost is: Total Cost = 2x * $20 + (2x + 200/x + 200/x) * $10.
To minimize the cost, we can differentiate the total cost with respect to x and set it equal to zero:
d(Total Cost)/dx = 0
Simplifying this equation will give us the value of x that minimizes the cost. We can solve this equation to find the minimum cost to build the field.
Learn more about field here:
#SPJ3