B) increasing the temperature of the reactant.
C) adding a catalyst to the reaction.
D)adding more reactant
Answer:
C)
Explanation:
C) adding a catalyst to the reaction.
Answer:
Lemon
HCI
Blood
Saliva
Bleach
NaOH
Explanation:
Blood 7.35-7.45
Bleach 12.6
Saliva 6.2-7.6
Lemon 2-3
HCI 3.01
NaOH 13
The vapor pressure of the solution would be as follows:
torr
Given that,
Vapor pressure of Carbon Disulfide torr
Naphthalene's mass
Naphthalene's molar mass
Now,
We know that
Number of moles
Mass ×
×
So,
Number of moles of Carbon Disulfide ×
moles of Carbon Disulfide
Number of moles of Naphthalene:
Number of moles
Now,
Total number of moles :
moles
Mole fraction of each compound in solution :
Carbon Disulfide:
2.567 / 2.65
Naphthalene
0.083 / 2.65
According to Raoult's:
P ×
Carbon Sulfide = Solvent
Mole fraction of solvent
Vapour pressure of the pure solvent
×
torr
Thus, " torr" is the correct answer.
Learn more about "Pressure" here:
Answer:
344.5764 torr
Explanation:
Molar mass of naphthalene = 128.2g/mol
Mass of naphthalene = 10.60 g
Carbon disulfide:
Molar mass= 76.14g/mol ;
volume = 155mL ;
density = 1.261 g/mL
Vapour pressure = 355.6 torr
Number of moles = mass / molar mass
CS2:
Mass = density × volume
Number of moles = (density × volume) / molar mass
Number of moles = (1.261 * 155) / 76.14 = (195.455 / 76.14) = 2.567 moles of CS2
Number of moles of C8H10:
Number of moles = 10.60 / 128.2 = 0.083 C8H10
Total number of moles :
2.567 + 0.083 = 2.65 moles
Mole fraction of each compound in solution :
CS2 :
2.567 / 2.65 = 0.969
C8H10:
0.083 / 2.65 = 0.031
According to Raoult's:
Psolution = Xsolvent × Posolvent
CS2 = solvent
Xsolvent = Mole fraction of solvent
Posolvent = Vapour pressure of pure solvent
Psolution = 0.969 × 355.6 torr = 344.5764 torr
Answer:
4.5m/s
Explanation:
speed = distance/time
speed = 18/4
speed = 4.5m/s
Answer:
400 Joules
Explanation:
From the question,
The total kinetic energy of the water balling when hits the ground is given as
K.E = 1/2mv².................. Equation 1
Where K.E = Kinetic Energy of water ballon, m = mass of water balloon, v = velocity of water ballon
Given: m = 2 kilograms, v = 20 meters/second.
Substitute these values into equation 1
K.E = (2×20²)/2
K.E = 2×400/2
K.E = 400 Joules