CHEMISTRY COLLEGE

What is the purpose of a catalyst?O A. To change the potential energy of the reactants
O B. To lower the activation energy of a reaction
O C. To increase the kinetic energy of the reactants
O D. To shift the equilibrium position of a reaction

Answers

Answer 1

Answer: B. To lower the activation energy of a reaction

Answer 2

Answer:

Answer:

To lower the activation energy of a reaction

Explanation:

i just took the test and got it right ...... i hope this helps :)

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I have a cup of hot coffee at 140 oC but I want to cool it to 110 oC. My cup holds about 0.3 kg of coffee. Fortunately, I have a bunch of aluminum cubes in the freezer that I can drop into my hot coffee to cool it down. If each aluminum cube has a mass of 1 g (not 1 kg!) and my freezer keeps its contents at a temperature of –10 oC, how many cubes do I have to drop into my coffee? The specific heat of water is around 4000 joules/kg/oC and aluminum is about 900 joules/kg/oC. (Pick the answer closest to the true value and ignore any thermal losses to surroundings.)A. 200B. 330C. 400D. 110E. 88
At 445 °C, Kc = 50.2. If one starts with 0.100 M H2 (g), 0.100 M I2 (g) and 0.0500 M HI (g) what is the equilibrium concentration of HI?
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Notice that "SO4" appears in two different places in this chemical equation. SO42− is a polyatomic ion called "sulfate." What number should be placed in front of CaSO4 to give the same total number of sulfate ions on each side of the equation? ?CaSO4+AlCl3→CaCl2+Al2(SO4)3
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A geochemist in the field takes a 13.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X. He notes the temperature of the pool, 16.° C, and caps the sample carefully. Back in the lab, the geochemist filters the sample and then evaporates all the water under vacuum. Crystals of X are left behind. The researcher washes, dries and weighs the crystals. They weigh 0.143 gRequired:
Using only the information above, can you calculate the solubility of X in water at 15°C ? If you said yes, calculate it.

Answers

Answer:

The answer is YES

The value is $S = 110 \ g/L$

Explanation:

From the question we are told that

The volume of the sample taken is v = 13.0 mL

The temperature is $T = 16^oC$

The mass of the sample is $m = 0.143 g$

Generally the solubility of the substance X is mathematically represented as

$S = (m)/(V)$

=> $S = (0.143 )/(13.0)$

=> $S = 0.011 \ g/mL$

=> $S = 110 \ g/L$

2. Calculate the mass of solvent in grams in a solution containing 3.0 grams of Tylenolif the mass percent is 3.5%.

Answers

Answer:

83g

Explanation:

1, Formula

Mass percent = (mass of solute/mass of solution) × 100

2. Determine mass of solution

Substitute the data and clear the mass of solution:

3.5 = (3.0g / mass of solution) × 100

0.035 = 3.0g / mass of solution

mass of solution = 3.0 g / 0.035

mass of solution = 85.714g

3. Determine the mass of solvent:

mass of solvent = mass of solution - mass of solute

mass of solvent = 85.714g - 3.0g = 82.714g

Round to two significant figures: 83 g

How many moles of atoms are in 9.00 g of 13c?

Answers

0.629 moles will be present in moles of atoms are in 9.00 g of 13 carbon atom.

What is a mole?

One mole of any substance is the amount of the substance which contain 6.023 × 10²³ atoms or molecule if the substance is atomic or molecular in nature and known as gram atomic mass.

Number of atoms in carbon is 9.00 grams and isotope are 13C,

Number of moles = weight of substance / mass of substance

Substituting the value in formula,

Number of moles = 9.00 grams / 13

Number of moles = 0.629 moles

Therefore, 0.629 moles will be present in moles of atoms are in 9.00 g of 13 carbon atom.

Learn more about moles, here:

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The atomic weight of 13C should be pretty close to 13.0. (If you have the exact mass, use it in the problem.) So, 9.00 g / 13.0 g/mol = 0.692 moles Therefore, the answer should be 0.692 moles are in 9.00 g of 13C.

Assuming 100% dissociation, which of the following compounds is listed incorrectly with its van't Hoff factor i? Al2(SO4)3, i = 4 NH4NO3, i = 2 Mg(NO3)2, i = 3 Na2SO4, i = 3 Sucrose, i = 1

Answers

Answer:

- Aluminium sulfate Al2(SO4)3 dissociates in two aluminium ions and three sulfate ions, therefore, van't Hoff factor is 5 (incorrect).

Explanation:

Hello,

In this case, since the van't Hoff factor is related with the species that result from the ionization of a chemical compound, we can see that that

- Aluminium sulfate Al2(SO4)3 dissociates in two aluminium ions and three sulfate ions, therefore, van't Hoff factor is 5 (incorrect).

- Ammonium nitrate NH4NO3 dissociates in one ammonium ions and one nitrate ion, therefore, van't Hoff factor is 2 (correct).

- Sodium sulfate Na2SO4 dissociates in two sodium ions and one sulfate, therefore, van't Hoff factor is 3 (correct).

- Sucrose is not ionized, therefore, van't Hoff factor is 1 (correct).

Best regards.

How many moles of sulfuric acid are there in 1.50L of a 6.0 M solution

Answers

Answer:

n= 9moles

Explanation:

n=?, C=6M, V= 1.5L

Applying

n= CV

n= 6×1.5= 9moles

The vapor pressure of carbon disulfide is 355.6 torr at 25°C. What is the vapor pressure of a solution prepared by dissolving 10.60 g naphthalene (C10H8, Molar Mass = 128.2 g/mol) in 155 mL CS2 liquid (Molar Mass = 76.14 g/mol, density = 1.261 g/mL)? Assume the solution obeys Raoult's law, and treat naphthalene as a nonvolatile solute.