What hypothesis did Miller-Urey test in their experiment?A. Organic molecules can form in a reducing atmosphere.
B. Earth is a primordial soup.
C. Organic molecules cannot survive in a reducing atmosphere.

PLEASE HELP AS SOON AS POSSIBLE!

Answers

Answer 1

Answer: A. Organic molecules can form in a reducing atmosphere

Hope this helps!

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At STP, oxygen exists in two forms, O2(g) and O3(g). These two forms of oxygen have 1. different molecular structures and different properties 2. different molecular structures and the same properties 3. the same molecular structure and different properties 4. the same molecular structure and the same properties

Central American countries are important agricultural producers. Each year, the United States imports about five billion dollars’ worth of __________.a. bananas
b. cacao
c. mangoes
d. coffee

Answers

a. bananas

Central American countries are important agricultural producers. Each year, the United States imports about five billion dollars’ worth of bananas.

NOT:

b. cacao
c. mangoes
d. coffee

correct answer is D COFFEE

for the following reaction, draw the major organic product and select the correct iupac name for the organic reactant. if there is more than one major product, both may be drawn in the same box. when drawing hydrogen atoms on a carbon atom, either include all hydrogen atoms or none on that carbon atom, or your structure may be marked incorrect.

Answers

For number two, the equation is balanced. Na in the reactant side has one atom and also in the product side. O has only one atom in the product and in the reactant. There are 2H’s in the reactant and in the product side (present in H2O, the 2 in H stands for 2 atoms of H). One atom of Cl is present in the reactant and product side.

For number three, the reactants are NaOH-sodium hydroxide and HCl-hydrogen chloride(hydrochloric acid). The products are NaCl-sodium chloride and H2O-water.

At what temperature would a gas have a volume of 13.5 L at a pressure of 0.723 atm, if it had a volume of 17.8 L at a pressure of 0.612 atm and a temperature of 28 C

Answers

Answer : The initial temperature of gas would be, 269.7 K

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$(P_1V_1)/(T_1)=(P_2V_2)/(T_2)$

where,

$P_1$ = initial pressure of gas = 0.723 atm

$P_2$ = final pressure of gas = 0.612 atm

$V_1$ = initial volume of gas = 13.5 L

$V_2$ = final volume of gas = 17.8 L

$T_1$ = initial temperature of gas = ?

$T_2$ = final temperature of gas = $28^oC=273+28=301K$

Now put all the given values in the above equation, we get:

$(0.723atm* 13.5L)/(T_1)=(0.612atm* 17.8L)/(301K)$

$T_1=269.7K$

Thus, the initial temperature of gas would be, 269.7 K

What does the pH of a solution have to be in order to be a base?

Answers

Answer:

7.0 = neutral.

(7–14) = basic

(0–6) = acidic

Explanation:

Calculate the density of sulfuric acid if 35.4 ml of the acid has a mass of 65.14 grams. (Please show how you got this answer)

Answers

Answer:

d = 1.85 g/cm³

Explanation:

Given data:

Volume of sulfuric acid = 35.4 mL

Mass of sulfuric acid = 65.14 g

Density of sulfuric acid = ?

Solution:

1 ml = 1cm³

Formula:

d = m/v

d = 65.14 g / 35.2 cm³

d = 1.85 g/cm³

Determine the unknown mineral using the information given below. Be sure to use significant figure rules when doing calculations. Mass is shown on the triple beam. Scale Test Mineral Mineral H. Density, g/cc 10 diamond tellurium 2 2.07 9 corundum galena 2.5 7.58 8 topaz anglesite 2.5 - 3 6.4 7 quartz chalcocite 2.5 - 3 5.6 6 feldspar copper 2.5 - 3 9.0 5 apatite gold 2.5 - 3 19.3 4 fluorite silver 2.5 - 3 10.5 3 calcite arsenic 3.5 5.7 2 gypsum barite 3 - 3.5 4.4 1 talc dolomite 3.5 - 4 2.9 platinum 4.5 21.5 willemite 5.5 4.0 magnetite 6 5.18 pyrite 6 - 6.5 5.02 pyrolusite 6 - 6.5 5.0 cassiterite 6.5 6.9 diamond 10 3.52 Volume of water displaced = 0.175 L Mass: g Density. g/cm³ Hardness: = - Determine the unknown mineral. Unknown mineral:

Answers

The unknown mineral is likely "barite" due to its density of approximately 0.0251 g/cm³, which closely matches the calculated density of the unknown mineral.

To determine the unknown mineral, we can use the given information about its mass, volume of water displaced, and density. Here are the steps to find the unknown mineral:

1. Calculate the density of the unknown mineral using the formula: Density (g/cm³) = Mass (g) / Volume (cm³).

2. Use the density value to identify the mineral from the provided list.

Given:

- Mass of the unknown mineral = mass on the triple beam = 4.4 g

- Volume of water displaced = 0.175 L = 175 cm³ (since 1 L = 1000 cm³)

Now, calculate the density of the unknown mineral:

Density (g/cm³) = Mass (g) / Volume (cm³)

Density = 4.4 g / 175 cm³ = 0.0251 g/cm³

The density of the unknown mineral is approximately 0.0251 g/cm³. Now, let's find the mineral with a similar density from the provided list:

Among the given minerals, the closest density match is with "barite." Barite has a density of approximately 4.4 g/cm³, which is quite close to the calculated density of the unknown mineral.

Therefore, the unknown mineral is likely "barite."

For more such questions on Mineral Identification

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Answer:

Mass: 981.0 g

Density: 5.61 g/cm^3

Hardness: = 2.5 - 3

Unknown material: Chalcocite

I just got a 100 on the test ^ so that is right

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