Is cobalt chloride solution a conductor or an insulator

Answers

Answer 1
Answer: well, cobalt is a metal and metals are good conductors of heat and electricity.
Answer 2
Answer: Cobalt is a conductor!

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2Mg + O2 --> 2MgO Magnesium is the oxidizing agent and is reduced oxidizing agent and is oxidized reducing agent and is reduced reducing agent and is oxidized

What happens if you don't get nutrients in your body

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You body starts to shut down! Hope this helped!
You begin to suffer from malnutrition

Iridium is a component of cosmic dust that rains down upon the earth at a constant rate. Why did Luis Alvarez suggest measuring iridium levels in the K-T boundary?

Answers

Answer:

In order to determine the rate at which the sediment layers were deposited

Explanation:

Iridium is an important element that belongs to the Platinum group and they are dominantly present in the asteroids and comets. They are the key evidence that suggests the occurrence of an asteroidal impact or a mass extinction event that has taken place in the geological past.

The presence of Iridium mixed with the clay sediments in the boundary between the Cretaceous and Tertiary (K-T boundary) suggested the mass extinction event that wiped out numerous life forms from the earth.

The famous scientist Dr. Luis Walter Alvarez suggested measuring the concentration of Iridium in this K-T boundary in order to determine the rate at which these sediment layers were deposited. They were able to determine that these Iridium elements were present due to the asteroid impact on earth, that wiped out the dinosaurs from the earth. They also considered that this element can be produced from the eruptions of volcanoes.

Answer:

The presence of Iridium mixed with the clay sediments in the boundary between the Cretaceous and Tertiary (K-T boundary) suggested the mass extinction event that wiped out numerous life forms from the earth.

The famous scientist Dr. Luis Walter Alvarez suggested measuring the concentration of Iridium in this K-T boundary in order to determine the rate at which these sediment layers were deposited. They were able to determine that these Iridium elements were present due to the asteroid impact on earth, that wiped out the dinosaurs from the earth. They also considered that this element can be produced from the eruptions of volcanoes.

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Explanation:Iridium is a component of cosmic dust that rains down upon the earth at a constant rate. Why did Luis Alvarez suggest measuring iridium levels in the K-T boundary?

If 10.3 g of Mg3N2 is treated with water, what volume of gas would be collected at STP

Answers

Use the ideal gas law: PV=nRtTo find volume, move to V=(nRt)/PN=# of moles (to find, 10.3 g/100.929g)=.102 molesR=ideal gas constant(this value is 0.082056(Liters*atmospheres)/(Kelvin*mol)T= temp which at stp is 273 KelvinP= 1 atmosphereV=((.102 moles)(0.082056 Latm/Kmol)(273 K))/1 atm
Mg3N2 +6H2O → 3Mg(OH)2 +2 NH3
relative weight of Mg3N2 = (3x24)+(2x14) = 100 g/mole
mole of Mg3N2 = 10,3 g/100 g/mole = 0,103 mole
mole of NH3(g) = 2/1 x 0,103 mole = 0,206 mole
volume NH3(g) which collected at STP = mole NH3(g) x 22,4 litre/mole = 0,206 mole x 22,4 litre/mole = 4,6144 litre.

How many significant digits are in the mass measurement 0.025 g? (a) 1 (B) 2 (c) 3 (d) 4 (e) none of the above

Answers

The answer is B. Only the 2 and the 5 are significant numbers.

Final answer:

The measurement 0.025 g has two significant digits. Leading zeroes are not counted as significant.

Explanation:

The correct answer to the question is (b) 2. The number 0.025 g has two significant digits.

In Physics, a significant digit is any non-zero digit or any embedded or trailing zeroes in a number. Leading zeros, which are zeros at the beginning of a decimal number, are not considered significant digits. In the number 0.025 g, the leading zeros are not counted as significant because they only indicate the decimal place of the significant digits (in this case, the digits 2 and 5). Therefore, the number of significant digits is 2.

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A patient is given 0.050 mg of technetium-99 m (where m means metastable—an unstable but long-lived state), a radioactive isotope with a half-life of about 6.0 hours.How long until the radioactive isotope decays to 1.3×10−2 mg ?

Answers

The correct answer is 9.6h.

As you know, a radioactive isotope's nuclear half-life tells you exactly how much time must pass in order for an initial sample of this isotope to be halved.

Using the formula , A = Ao.1/2^n

where , A- final mass after decay

Ao - initial mass

n - the number of half-lives that pass in the given period of time

Now, putting all the values, we get

1.3 × 10^-2 mg = 0.050 mg × 1/ 2^n

Take the natural log of both sides of the equation to get,

(1.3 . 10^(-2) / 0.050 ) = ㏑((1/2)^(n))

(1.3 . 10^(-2) / 0.050 ) = n. ln(1/2)\n

n = 1.6

Since n represents the number of half-lives that pass in a given period of time, you can say that

n = t /  t _(1/2)

t= 1.6 × 6 h

t = 9.6h
Hence, it will take 9.6 h  until the radioactive isotope decays.

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Final answer:

Using the formula for radioactive decay and the provided half-life of technetium-99m, it can be calculated that it takes approximately 28.5 hours for 0.050 mg of technetium-99m to decay to a quantity of 1.3 x 10^-2 mg.

Explanation:

The decay of a radioactive isotope is an exponential process based on the half-life, which is, in turn, constant for any given isotope. The general formula for the remaining quantity of a radioactive isotope after a given time is given by: N = N0 (0.5) ^(t/t1/2), where (N0) is the initial amount, (N) is the remaining amount, (t) is time, and (t1/2) is the half-life of the isotope. In this case, we are given the initial quantity (N0 = 0.050 mg), the remaining quantity (N = 1.3 x 10^-2 mg), and the half-life (t1/2 = 6.0 hours).

We can solve for time (t) in the equation: N = N0 (0.5) ^(t/t1/2). Plugging in the values, we get 1.3 x 10^-2 = 0.050 x (0.5)^(t/6), and solving for t, we find that it takes approximately 28.5 hours for the technetium-99m to decay to 1.3 x 10^-2 mg.

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Which question would most likely be studied by a physicist?A. Were there ever any living organisms on Mars?
B. How can the forces on a space probe be controlled so it will land
on Mars?
O C. What type of substances make up the soil on Mars?
O D. Should the government spend taxpayers' money to send space
probes to Mars?

Answers

Answer:A

Explanation: Were there any living organisms is the answer because physics is the study of matter,its motion and behaviour of space and time and some other topics like energy and force.

Answer:

B

Explanation:

Forces and vectors on a probe are a physics thing