A certain skin lotion is a fine mixture of water and various oils. This lotion is cloudy and cannot be separated into oil and water by filtration or centrifuge. What type of mixture is it?

Answers

Answer 1
Answer: A certain skin lotion is a fine mixture of water and various oils. This lotion is cloudy and cannot be separated into oil and water by any filtration or centrifuge, it is a colloid mixture. The colloid consists of large molecules & ultra microscopic particles of a substance that has been dispersed by another substance. 

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I need help with this molecular formula problem really quick!!
A gas Syringe contains 42.3 milliliters of a gas at 98.15°C. Determine the volume that the gas will occupy if the temperature is decreased to -18.50°C.

DA gas has a volume of 4.00 L at 0 degrees Celsius. What final temperature, in degrees Celsius, is needed to change the volume of the gas to each of the following, if n and p do not change?A. 1.50 L
B. 1200 mL
C. 10.0 L
D. 50.0 mL

Answers

The final temperature is  -170.625 degree Celsius ,-191.1 degree C, 409.5 degree C,-272.66 degrees Celsius .

What is Charle's Law ?

According to Charle's Law , For an Ideal Gas , the volume is directly proportional to temperature when no. of moles and Pressure remains constant.

It is given in the question that

A gas has a volume of 4.00 L

T = 0 degree Celsius = 273 K

T' = ? for each scenario

the volume of the gas = 1.5 l , 1200ml , 10 l , 50ml

if n and p do not change

\rm (V_1)/(T_1) = (V_2)/(T_2)

For V₂ = 1.5 l

4 / 273 = 1.5 / T₂

T₂ = 1.5*273/4

T₂ = 102.375 K = -170.625 degree Celsius

For  V₂ = 1.2 l

4/273 = 1.2/T₂

T₂ = 81.9 K = -191.1 degree C

For  V₂ = 10 l

4/273 = 10/T₂

T₂ = 682.5 K= 409.5 degree C

For  V₂ = 50/1000= 0.005L

4/273 = 0.005/T₂

T₂ = 0.34125 K= -272.66 degree C

Therefore the final temperature in degrees Celsius has been determined.

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D 50.O ML IS THE ANSWER

Upon combustion, a 1.3109 g sample of a compound containing only carbon, hydrogen, and oxygen produces 3.2007 gCO_(2) and 1.3102 gH_(2)O. Find the empirical formula of the compound.The answer I got was CH_(16)O, but I'm not sure if I did it right or not. Can someone confirm this for me?

Answers

Answer:

The empirical formula of the compound is C_4H_8O_1

Explanation:

Moles of carbon dioxide = (3.2007 g)/(44 g/mol)=0.07274 mol

Moles of carbon in sample = 1* 0.07274 mol=0.07274 mol

Moles of water = (1.3101 g)/(18 g/mol)=0.07279 mol

Moles of hydrogen in sample = 2* 0.07279 mol=0.14558 mol

Mass of sample = Mass of carbon + Mass of hydrogen + Mass of oxygen

Mass of oxygen =

1.3109 g - (12 g/mol × 0.07274 mol) - (1 g/mol× 0.14558 mol)

Mass of oxygen = 0.29244 g

Moles of oxygen in sample = (0.29244 g)/(16 g/mol)=0.01828 mol

For empirical formula divide the moles of element which are is less amount with all the moles of every element.

Carbon =(0.07274 mol)/(0.01828 mol)=3.9\approx 4

Hydrogen =(0.14558 mol)/(0.01828 mol)=7.9\approx 8

oxygen=(0.01828 mol)/(0.01828 mol)=1

The empirical formula of the compound is C_4H_8O_1

Answer:

The answer to your question is:   C₃H₃O  This is my answer.

Explanation:

Data

Sample = 1.3109 g

CxHyOz

CO₂ = 3.2007 g

H₂O = 1.3102 g

Empirical formula = ?

MW CO2 = 44 g

MW H2O = 18 g

For Carbon

                                     44 g -------------------- 12 g

                                     3.2007 g ------------    x

                                      x = (3.2007 x 12) / 44

                                      x = 0.8729 g of Carbon

                                     12 g of C --------------  1 mol

                                     0.8729 g --------------  x

                                     x = (0.8729 x 1) / 12

                                     x = 0.0727 mol of Carbon

For Hydrogen

                                 18 g ---------------------- 1 g

                              1.3102 g -------------------  x

                                   x = (1.3102 x 1) / 18

                                  x = 0.0727 g of Hydrogen                                      

                                  1 g ------------------------ 1 mol

                                  0.0727g ----------------  x

                                  x = (0.0727 x 1)/1

                                  x = 0.0727 mol of Hydrogen

For oxygen

                    g of Oxygen = g of sample - g of Carbon - g of hydrogen

                    g of Oxygen = 1.3109 - 0.8709 - 0.0727

                    g of Oxygen = 0.3673

                                  16 g of Oxygen ------------- 1 mol of O

                                  0.3673 g ---------------------   x

                                   x = (0.3673 x 1)/ 16

                                   x = 0.0230 mol of Oxygen

Divide by the lowest number of moles

Carbon              0.0727 / 0.023  = 3.1  ≈ 3

Hydrogen         0.0727 / 0.023 = 3.1  ≈ 3

Oxygen             0.0230 / 0.023 = 1

                                        C₃H₃O

What is a star's emission spectrum?It is the same as the HR diagram and gives the same information.
It is the fingerprint of all of the colors of light emitted by a star.
It is a graph of all the pollution given off by a star.
It is a graph of the star’s solar flares.

Answers

The right answer for the question that is being asked and shown above is that: "It is the same as the HR diagram and gives the same information." a star's emission spectrum is tat It is the same as the HR diagram and gives the same information.

A white solid is flammable and dissolves in hexane. Would you expect this compound to be organic or inorganic?

Answers

A white solid is flammable and dissolves in hexane. It should be organic molecule.

What is organic molecule.?

Any chemical substance that has carbon-hydrogen, as well as carbon-carbon bonds is considered an organic molecule.

What is flammable?

The term "flammable substances" refers to those gases, liquids, as well as solids that, when exposed to an ignition source, would catch fire and keep burning in the air. Many flammable and explosive substances have a volatile character, which means they rapidly evaporate and continuously emit vapors.

A chemical characteristic, like corrosion resistance, was flammability. A material's physical characteristics, including its hardness, density, melting point, and thermal conductivity, can be measured or observed without using force or chemical alterations. A material's phase changes when it melts, not just its identity.

There are some properties of organic molecules.

  • An abundance of carbon.
  • Saturation in organic solvents.
  • Covalent bonds form
  • A low boiling as well as melting point.

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The answer is organic. The most important hint is it can dissolves in hexane which is organic. And the other hint is flammable. Then you can say this compound is likely to be organic.

What is scientific consensus?O a new scientific idea that was confirmed by the original researcher
an idea that has been changed due to new information
O a general agreement among scientists about a scientific idea
the understanding that knowledge in a particular area can be uncertain

Answers

The scientific consensus is a general agreement among scientists about a scientific idea. The correct option is C.

What is a scientific idea?

A scientific idea is the explanation or facts of science. It reveals the truth about the world. How the world works and the secrets of nature. It tells and gathers true information about the world.

The different aspects of life and the world are understood and studied by scientists. Different scientists work for different forms of life. The scientist's ideas change over the different evidence.

The generalized ideas of various scientists give and agree upon the different theories of the levels of science. The publication process and specialized field.

Thus, the correct option is C. a general agreement among scientists about a scientific idea.

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Answer:

it's C

Explanation:

got it right on EDG 2021

a man bought two watches for Rs 2500 each.He sold one of them at 10% . profit and the other at 4% loss.what was his gain or loss percent on the whol​

Answers

Answer:

Selling price of watch A and watch B= Rs. 425

Let cost price of watch A=x

Profit =10%

100

110

x=425

x=386.36

Let cost price of watch B=y

Loss =10%

100

90

y=425

y=472.22

Net cost price =x+y=858.5858

Net selling price =850

Loss%=

858.58

858.5858−850

×100=1%

Explanation:

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