can you afford?
Cho
Answer:
You can afford 16 feet of plastic tubing.
Step-by-step explanation:
Divide 8.16 by 4.08 = 2
Multiply 8 by 2 = 16
Hope this helps! Have a good day!
Answer:
Sixteen feet of plastic tubing
Step-by-step explanation:
4.08x2=8.16 and 8x2=16 so its just double the amount.
Answer:
380$
Step-by-step explanation:
Multiply 400*5%=20
Then subtract 400-20=380
Answer:
$380
Step-by-step explanation:
-5x + 4y = -13
A. (0, -1)
B. (8,0)
C. (1, -7/8)
D. (2, -3/4)
Answer:
D. (2, -3/4)
Step-by-step explanation:
Using the substitution method:
-5x+4(1/8x-1)=-13
-5x+0.5x-4=-13
-4.5x/4.5=-9/4.5
-x=-2
x=2
You are supposed to replace 2 in the first equation now but as there is no other option with x value of 2 D is the answer.
If continued:
-5(2)+4y=-13
-10+4y=-13
4y=-3
y=-3/4
Use rules of inference to prove that the following conclusion follows from these hypotheses:
C : ∃x (p(x) ∧ r(x))
Clearly label the inference rules used at every step of your proof.
2. Consider the following hypotheses:
H1 : ∀x (¬C(x) → ¬A(x)) H2 : ∀x (A(x) → ∀y B(y)) H3 : ∃x A(x)
Use rules of inference to prove that the following conclusion follows from these hypotheses:
C : ∃x (B(x) ∧ C(x))
Clearly label the inference rules used at every step of your proof.
3. Consider the following predicate quantified formula:
∃x ∀y (P (x, y) ↔ ¬P (y, y))
Prove the unsatisfiability of this formula using rules of inference.
Answer:
See deductions below
Step-by-step explanation:
1)
a) p(y)∧q(y) for some y (Existencial instantiation to H1)
b) q(y) for some y (Simplification of a))
c) q(y) → r(y) for all y (Universal instatiation to H2)
d) r(y) for some y (Modus Ponens using b and c)
e) p(y) for some y (Simplification of a)
f) p(y)∧r(y) for some y (Conjunction of d) and e))
g) ∃x (p(x) ∧ r(x)) (Existencial generalization of f)
2)
a) ¬C(x) → ¬A(x) for all x (Universal instatiation of H1)
b) A(x) for some x (Existencial instatiation of H3)
c) ¬(¬C(x)) for some x (Modus Tollens using a and b)
d) C(x) for some x (Double negation of c)
e) A(x) → ∀y B(y) for all x (Universal instantiation of H2)
f) ∀y B(y) (Modus ponens using b and e)
g) B(y) for all y (Universal instantiation of f)
h) B(x)∧C(x) for some x (Conjunction of g and d, selecting y=x on g)
i) ∃x (B(x) ∧ C(x)) (Existencial generalization of h)
3) We will prove that this formula leads to a contradiction.
a) ∀y (P (x, y) ↔ ¬P (y, y)) for some x (Existencial instatiation of hypothesis)
b) P (x, y) ↔ ¬P (y, y) for some x, and for all y (Universal instantiation of a)
c) P (x, x) ↔ ¬P (x, x) (Take y=x in b)
But c) is a contradiction (for example, using truth tables). Hence the formula is not satisfiable.
C. A neutral beryllium atom
D. A positively charged beryllium ion
This image represents A positively charged beryllium ion.
We have given that,
He 4 Protons e 5 Neutrons = 2 Electrons
A. A negatively charged beryllium ion
B. A neutral boron atom
C. A neutral beryllium atom
D. A positively charged beryllium ion.
We have to determine, Based on information from the periodic table what does this image represent?
A table of the chemical elements arranged in order of atomic number, usually in rows, so that elements with similar atomic structure (and hence similar chemical properties) appear in vertical columns.
This image represents A positively charged beryllium ion.
To learn more about the periodic table visit:
#SPJ2
Answer:
D. A positively charged beryllium ion
Answer:
x+3. is the first num
x +4 is the second num
the sum is 2x +7
Answer:
2x + 7
Difference is 1
Step-by-step explanation:
Consecutive numbers are numbers that increase with a steady difference.
For example; 1, 2, 3 all increase with a difference of 1 (2 = 1 + 1; 3 = 2 + 1) and so on.
If the smaller of two consecutive numbers is x + 3, that means the other number which should be bigger is x + 4
Therefore the sum of both numbers is (x + 3) + (x + 4) = 2x + 7.
Their difference is (x + 4) - (x + 3) = 1
And subtracting their sum from x + 8 gives (x + 8) - (2x + 7) = x + 8 - 2x - 7 = -x + 1.