Answer:
B, C, and E
Step-by-step explanation:
B; C = score + 25 percent of score
C; C = 125% of score (which equals 1 plus 25%)
E; t plus 25% of t score
This question is incomplete, the complete question is;
find the critical points and classify them as local maxima, local minima, saddle points, or none of these.
f(x,y) = (x + y)(xy + 1)
Answer:
(x,y) = (-1, 1), (1, -1) area critical points
f(xx) =2y, fyy =2x,f(xy) =2x + 2y, D = f(xx)fyy - f(xy²)
at (-1, 1)
f(xx) = 2 ,fyy =-2,f(xy) = 0, D = -4 < 0 saddle point
at (1, -1)
f(xx) = -2, fyy =2,f(xy) =0, D = -4 < 0 saddle point
Step-by-step explanation:
Given that;
f(x,y) = (x + y)(xy + 1)
f(x,y) =x²y + xy² + x + y
for critical points fx =0 ,fy =0
fx = 2xy + y² + 1 = 0, fy = x² + 2xy + 1 = 0
2xy + y² + 1 = 0, x²+ 2xy + 1 = 0
2xy + y² + 1 - x² - 2xy - 1 = 0
x² = y²
=> x = y, x = -y
2xy + y² + 1 = 0, x = y
2yy + y² + 1 = 0
3y² = -1 , no solution
2xy + y² + 1 = 0, x = -y
-2yy + y² + 1 = 0
=> -y2 + 1 = 0
=> y = -1, y = 1
y = -1 => x = 1, y = 1 => x = -1
(x,y) = (-1, 1), (1, -1) area critical points
f(xx) =2y, fyy =2x,f(xy) =2x + 2y, D = f(xx)fyy - f(xy²)
at (-1, 1)
f(xx) = 2 ,fyy =-2,f(xy) = 0, D = -4 < 0 saddle point
at (1, -1)
f(xx) = -2, fyy =2,f(xy) =0, D = -4 < 0 saddle point
Answer:
Domain is number of candy or 300
Range is profit from selling candy or $50
Step-by-step explanation:
Domain is the numbers you are allowed to use in your function. In this case, it would be the amount of candy you sold.
The range is the output from inputting the number(s) in the domain. In this case, the range is the amount of money you profit.
Profit=(amount gained)-(amount lost)
amount gained is from selling candy
amount lost is what you invested to get the candy
amount gained=(cost per candy)X(number of candy)
amount gained=(1.50)(300)
amount gained=$450
amount lost=$50
therefore
Profit=450-40=$400
a function for profit can be as follows:
P(x)=1.5x-c
where amount you sold each candy for, c is cost for those x candies, and P(x) is the profit for x candies
9514 1404 393
Answer:
B, D, E
Step-by-step explanation:
Any of the following will put rectangle 1 on top of rectangle 2:
(B) Find the demand equation.
(C) Find the equilibrium price and quantity
Answer:
(A) Find the supply equation.
Qs = 245.67 + 333.33Ps
(B) Find the demand equation.
Qd = 1079 - 1000Pd
(C) Find the equilibrium price and quantity
Price P = $0.625
Quantity Q = 454 bushels
Step-by-step explanation:
The demand equation is of the form;
Q = a - bP
The supply equation is of the form;
Q = c + eP
We need to determine the values of a,b,c,d;
At $ 0.49 per bushel, the daily supply for wheat is 409 bushels, and the daily demand is 589 bushels
589 = a - b(0.49) ........1
409 = c + e(0.49) .........2
When the price is raised to $ 0.85 per bushel, the daily supply increases to 529 bushels, and the daily demand decreases to 229 bushels;
229 = a - b(0.85) ........3
529 = c + e(0.85). .......4
Subtract equation 3 from 1
589-229 = b(0.85) - b(0.49)
360 = b(0.36)
b = 360÷0.36
b = 1000
Using equation 1
589 = a - 1000(0.49)
a = 589+490 = 1079
Subtract equation 2 from 4
529-409= e(0.85) - e(0.49)
120 = 0.36e
e = 120/0.36
e = 333.33
Using equation 2
409 = c + 333.33(0.49)
c = 409 - 333.33(0.49)
c = 245.67
Therefore the demand equation is;
Qd = 1079 - 1000Pd
The supply equation is ;
Qs = 245.67 + 333.33Ps
The equilibrium price is at Qs = Qd and Ps = Pd
1079-1000P = 245.67 +333.33P
P = (1079-245.67)/(1000+333.33)
P = $0.625
Qd = 1079 - 1000(0.625)
Qs = Qd = 454