To solve the equation 5 + 3r = 4 + 4r, we need to isolate the 'r' term on one side of the equation. Ria made a mistake by stating that the equation has infinitely many solutions, but the correct solution is r = 1.
The equation given is 5 + 3r = 4 + 4r. To solve this equation, we need to first simplify both sides by combining like terms. On the left side, 5 does not have a 'r' term, so we can leave it as it is. On the right side, 4 has a 'r' term, so we can write it as 4r. Now we have 5 + 3r = 4r + 4. To solve for 'r', we need to isolate the 'r' term on one side of the equation. We can do this by subtracting 3r from both sides of the equation. This gives us 5 = 4r + 4 - 3r. Simplifying further, we get 5 = r + 4. Now, to isolate 'r', we can subtract 4 from both sides of the equation. This gives us 1 = r. Therefore, the solution to the equation is r = 1.
#SPJ3
Responses
A There is 35 of a box of dog treats in the cupboard. Jill’s dog eats 14 of a box of treats in a week. How many weeks of treats are left in the box for Jill’s dog?
B There is , fraction 3 over 5 end fraction, , of a box of dog treats in the cupboard. Jill’s dog eats , fraction 1 over 4 end fraction, of a box of treats in a week. How many weeks of treats are left in the box for Jill’s dog?
C Christie hiked 14 mile on the trail. Jackie hiked 35 mile farther than Christie. How far, in miles, did Jackie hike on the trail?
Christie hiked , fraction 1 over 4 end fraction, , mile on the trail. Jackie hiked , fraction 3 over 5 end fraction, , mile farther than Christie. How far, in miles, did Jackie hike on the trail?
D Shawn made a poster that has a width of 14 meter and a length of 35 meter. What is the perimeter, of Shawn’s poster?
Shawn made a poster that has a width of , fraction 1 over 4 end fraction, , meter and a length of , fraction 3 over 5 end fraction, , meter. What is the perimeter, of Shawn’s poster?
E In Sophie’s doll collection, 35 of the dolls are in their original boxes. Sophie plans to donate 14 of the dolls in these boxes to charity. How much of her doll collection will Sophie donate to charity?
Answer: The story problem that could be solved using the given equation is E. In Sophie’s doll collection, 35 of the dolls are in their original boxes. Sophie plans to donate 14 of the dolls in these boxes to charity. How much of her doll collection will Sophie donate to charity?
To solve this problem, we can multiply the fractions 1/4 and 3/5 to find the fraction of the doll collection that Sophie will donate. Using the equation 1/4 × 3/5 = m, we can simplify the fractions by multiplying the numerators and denominators:
m = (1 × 3) / (4 × 5) m = 3 / 20
Therefore, Sophie will donate 3/20 of her doll collection to charity. This fraction can also be written as a decimal or a percentage:
m = 3 / 20 m = 0.15 m = 15%
I hope this helps!
b)18
c)1/81
d)-1/81
evaluate the expression 8^-2 x 4^0
16
64
-64
1/64
write 5^ x 5^-1 x 5^3 as a single exponent.
5^4
5^-6
5^5
5^2
what is 8.57 x 10^-4 in standard form
85,700
0.00857
8,750,000
0.000875
Answer:
Step-by-step explanation:
|-1.4| + (-2.7) = 1.4 - 2.7 = -1.3 is the solution
Ο 1.8, -5/9
Ο 1.8, 8.1
Ο 1.8, 5/9