y=4-x
y= x+2
y=4-x
so
x + 2 = 4 - x
2x = 2
x = 1
y = 1 + 2
y = 3
Answer
x = 1, y = 3
y= x + 2
y= 4 - x
Let (y= x+2) be y
x+2 = 4- x
x + x = 4 - 2
2x = 2
Therefore x= 1
Lets now find y;
y= x+2
lets replace x with 1 ( x=1)
y= 1+2
y= 3
The answer therefore is y=3 and x= 1
To find the inverse Laplace transform of the given expression, use partial fraction decomposition to simplify it into individual fractions and then find their inverse transforms.
To find the inverse Laplace transform of the given expression, we can use partial fraction decomposition. First, we factor the denominator: s2*(s3-48). The next step is to represent the expression as a sum of simpler fractions:
1/s2 - 48/s5 = A/s + B/s2 + C/(s - 2) + D/(s + 2) + E/(s + 4) + F/(s2 - 4)
Next, we solve for A, B, C, D, E, and F by performing algebraic manipulations and equating the corresponding coefficients. Finally, we can look up the inverse Laplace transform of each individual fraction term in tables or by using known formulas.
#SPJ3
None
Two
Infinitely many