The probability that all cards are the same suit is 33/16660 if the standard deck of cards has 52 members consisting of 4 suits each with 13 members (2, 3, …, 10, j, q, k, a).
It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.
It is given that:
A standard deck of cards has 52 members consisting of 4 suits each with 13 members (2, 3, …, 10, j, q, k, a)
Five cards are dealt from the randomly mixed deck.
P(5 cards are from same deck) = 4(13/52)(12/51)(11/50)(10/49)(9/48)
P(5 cards are from same deck) = 33/16660
Thus, the probability that all cards are the same suit is 33/16660 if the standard deck of cards has 52 members consisting of 4 suits each with 13 members (2, 3, …, 10, j, q, k, a).
Learn more about the probability here:
#SPJ2
Answer:
a) green: 0.3
yellow: 0.1
b) 12
Step-by-step explanation:
Unfortunately, I cant write on the table. But, I CAN help you with this question.
Since all probabilities have to add up to one, we can for an equation like this
(where y is yellow)
0.35+0.25+3y+y=1
This simplified is
0.6+4y=1
4y=0.4
So, we now know that green is 0.3, and yellow is 0.1.
For b, we set 0.35x to 14. Dividing gives us:
14/0.35=1400/35=40.
Multiply 0.3 by 40, and you get 12.
Hope this helped!
Equation D: y = 2x + 2
Which of the following best describes the solution to the given set of equations?
No solution - Is this the answer?
One solution
Two solutions
Infinite solutions
The successful completion of the exam review packet
The number of days students ate breakfast that semester
The location of students in the classroom
The number of times students completed extra credit
Answer:
The successful completion of the exam review packet
Step-by-step explanation:
This is the only answer that talks about the school work because every other answer doesn’t even correlate with the question. Except the extra credit one but that one still excludes from the original test. Therefore, it is
The successful completion of the exam review packet
Also I got it right on the test