1. What is the angular distance north or south from the earth's equator beginning at0° at the equator and ending at 90° at either pole?
a. Weather
b. Altitude
c. Latitude
d. Climate

Answers

Answer 1
Answer:

Answer:

c. Latitude

Explanation:

The angular distance north or south from the earth's equator beginning at 0° at the equator and ending at 90° of either pole is the latitude.

The equator is a line of latitude that divided the earth into two hemispheres.

Only the equator is a great circle as a line of latitude. Others are small circles.

  • Weather is the atmospheric condition of a place over a short period of time
  • Climate is the average weather condition at a place over a long period of time.
  • Altitude of a place is its elevation above a reference plane.

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Which of the two aqueous solutions will be a better conductor of electricity in the following examples? Explain why in each case.a)1.0M NaCl vs. 0.010 M Nacl
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c) 1.0 mole of NaCl added to water vs. 1.0 mole of pbCl2 added to water (hint: remember the solubility rules).

Answers

a) The solution with a concentration of 1.0 M NaCl will be a better conductor of electricity since it has a higher number of electrolytes
b) The 0.10 M Al2(SO4)3 will be a better conductor since more ions are formed per mole of the salt dissociated
c) 1.0 mol of NaCl in water because NaCl is very soluble in water

Which of the following statements is true about exothermic reactions?

Answers

Answer:

An Exothermic Reaction , gives off more heat, and a little energy to its surroundings.

this can helps us figure out that the answer is , C, More heat is given off into its products.

Explanation:

Determine the end (final) value of n in a hydrogen atom transition, if the electron starts in and the atom emits a photon of light with a wavelength of 486 nm. Group of answer choices

Answers

Complete Question

Determine the end (final) value of n in a hydrogen atom transition, if the electron starts in n=4 and the atom emits a photon of light with a wavelength of 486 nm. Group of answer choices

Answer:

n=2

Explanation:

From the question we are told that:

Wavelength \lambda=486nm=>486*10^(-9)

Generally the equation for Atom Transition is mathematically given by

(1)/(\lambda)=R_(\infty )((1)/(n_1^2)-(1)/(n_2^2))

Where

Rydberg constant R_(\infty)=1.097*10^7

Therefore

(1)/(486*10^(-9))=1.097*10^7*((1)/(n_1^2)-(1)/(4^2))

((1)/(n_1^2)-(1)/(4^2))=(1)/(486*10^(-9)*1.097*10^7)

n_1^2=3.98

n=1.99

n=2

Final answer:

The final value of n in the hydrogen atom transition is 4.

Explanation:

The end value of n in a hydrogen atom transition can be determined using the equation En = Eo * Z^2 / n^2, where En is the energy of the excited state and Eo is the ionization energy. Since the electron starts in the ground state (n = 1) and emits a photon of light with a wavelength of 486 nm, we can use Equation 6.49 to solve for n. By substituting m = 1 and λ = 486 nm into Equation 6.49, we find that n is approximately 4. Therefore, the final value of n in the hydrogen atom transition is 4.

Learn more about Hydrogen atom transition here:

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How is energy transfer connected to your life

Answers

Answer:

Baking, microwave, heating system for your house, water boiler, fridge.

22. What is the molar mass of oxygen (O2)?A- 15.9994 g/mol
B- 1.204 x 1024 g/mol
C- 6.02 x 1023 g/mol
D- 31.9988 g/mol

Answers

Answer:

D- 31.9988 g/mol

Explanation:

The molar mass of a substance is the mass in grams of one mole of the substance. For a compound, the molar mass is the gram - formula mass or gram - molecular weight. It is determined by the addition of its component atomic masses;

  To find molar mass of O₂;

      Atomic mass of O = 15.9994g/mol

 Molar mass of O₂ = 2(15.9994) = 31.9988g/mol

Be sure to answer all parts. Consider both 5-methyl-1,3-cyclopentadiene (A) and 7-methyl-1,3,5-cycloheptatriene (B). Which labeled H atom is most acidic? Hb is most acidic because its conjugate base is aromatic. Hc is most acidic because its conjugate base is antiaromatic. Ha is most acidic because its conjugate base is antiaromatic. Hd is most acidic because its conjugate base is aromatic. Which labeled H atom is least acidic? Ha is least acidic because its conjugate base is aromatic. Hb is least acidic because its conjugate base is antiaromatic. Hd is least acidic because its conjugate base is aromatic. Hc is least acidic because its conjugate base is antiaromatic.

Answers

Due to the conjugate base of the hydrogen atom is aromatic, Hb is regarded as the most acidic. Because the conjugate base of the hydrogen atom Hc is anti-aromatic, it is the least acidic.

The correct options are:

(A) - (a)

(B) - (d)

What are the most and the least acidic hydrogen atom?

The hydrogen connected at the heptatriene's tertiary position (at the 7-methyl) would be particularly acidic, as its removal would leave a positive charge that could be transported around the ring via resonance.

The hydrogen connected to the pentadiene (5-methyl) at the tertiary position would not be acidic, as removing it would result in an anti-aromatic structure.

Thus, the least acidic H atom is Hc and the most acidic H atom is Hb.

Learn more about hydrogen atom, here:

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I don’t have a picture but I can describe it to you.

The hydrogen that is attached at the tertiary position on the heptatriene (at the 7-methyl) would be very acidic, as removal would leave a positive charge that could be moved throughout the ring through resonance. This would mean that the three double bonds would be participating in resonance, and the deprotonated structure would be aromatic, thus making this favorable.

The hydrogen that is attached at the tertiary position on the pentadiene (5-methyl) would NOT be acidic, as removal would cause an antiaromatic structure.

Any other hydrogens would NOT be acidic. Those vinylic to their respective double bonds would seriously destabilize the double bond if removed, and hydrogens attached to the methyl group jutting off the ring have no incentive to leave the carbon.

Hope this helps!