The mean distance from Saturn to the sun is 9 times greater than the mean distance from Earth to the sun. How long is a Saturn year?

Answers

Answer 1

Answer: It probably also has a nineth of the speed, so it's 81 earth years. If they had the same speed, it would be 9 earth years. Probably the first one is more accurate :-??

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Which of the following best describes the fate of energy in ecosystems?
A 12 volt car battery produces more current than a 1.5 volt battery for a TV remote because...A. the tv remote has more kinetic energy.B. the tv remote has a greater difference in electric potential energy.C. the car bettery has a greater difference in electric potential energy.D. the car bettery has more kinetic energy.

What is the speed of sound, when travelling through steel?

Answers

20000 ft/s or 6100 m/s

How much work is required to move3.0 coulombs of electric charge a distance of
0.010 meter through a potential difference of
9.0 volts?
(1) 2.7 × 10^3 J (3) 3.0 J
(2) 27 J (4) 3.0 × 10^−2 J

Answers

So we want to know how much work is needed to move a charge Q=3C for a distance r=0.01m trough a potencial difference U=9V. Work of electric potential is defined as W=Q*U and we can now simply put in the numbers. We get: W=3C*9V=27J. So the correct answer is (2) 27J.

Why are the vector quantities magnitude and direction

Answers

Because color, cost, temperature, weight, and age
don't tell you enough about the motion.

Because, by definition, a vector has to have magnitude and direction. Otherwise, it's not a vector. If it only has magnitude, then it's a scalar, not a vector. Does that help at all?

An object is dropped from a height H above the ground. This free-falling object requires 1.02 s to travel the last 39 m before hitting the ground. From what height H above the ground did the object fall?

Answers

Answer:

H = 95.3 m

Explanation:

Let the height from which object fall down is H

so the total time to fall is given as

$H = (1)/(2)gt^2$

now it cover 39 m in last 1.02 s of its path

$H - 39 = (1)/(2)g(t - 1.02)^2$

so now we have

$(1)/(2)gt^2 - 39 = (1)/(2)g(t - 1.02)^2$

by solving above equation

$t = 4.41 s$

Now the total height is given as

$H = (1)/(2)gt^2$

$H = (1)/(2)g(4.41)^2$

H = 95.3 m

A 2-kg object is moving 6 m/s in a horizontal direction.How much net force is required for this object to continue its state of motion?
Α. Ο Ν
B.
2N
C.
3 N
12 N

Answers

Answer: A) O N

Explanation:

An object in motion will maintain its state of motion. The presence of an unbalanced force changes the velocity of the object.

Which letter represents the direction of the centripetal force?

Answers

I think there should be a picture。
But the direction of the centripetal force is towards the center。
Hope that helps。

Other Questions

You are asked to measure the density of a cube that has a side of 10 centimeters, and weighs 1 kg nominally. The tools you have are a ruler with the smallest reading at 1 mm, and a scale with a precision down to 0.1 g. Both tools are calibrated. Please estimate the final error on the density of the object that you measure.

An unknown substance has a mass of 0.125 kg and an initial temperature of 90.5°C. The substance is then dropped into a calorimeter made of aluminum containing 0.285 kg of water initially at 29.5°C. The mass of the aluminum container is 0.150 kg, and the temperature of the calorimeter increases to a final equilibrium temperature of 32.0°C. Assuming no thermal energy is transferred to the environment, calculate the specific heat of the unknown substance.

The asthenosphere is a part of the upper mantle just below the lithosphere that is involved in plate tectonic movement and isostatic adjustments. Which is NOT true about the role of the asthenosphere in plate tectonics?

A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.7 1010 m (inside the orbit of Mercury), at which point its speed is 9.5 104 m/s. Its farthest distance from the Sun is far beyond the orbit of Pluto. What is its speed when it is 6 1012 m from the Sun? (This is the approximate distance of Pluto from the Sun.)