How many iron atoms are in 0.32 mol of Fe2031? 3.9x 1023 jron atoms O 3.9 iron atoms O 6.02 x 1023 iron atoms 1.9 x 1023 iron atoms O 11x 10-24 iron atoms

Answers

Answer 1

Answer:

Answer: $3.9* 10^(23)$ iron atoms

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023* 10^(23)$ of particles.

$1 molecule of [tex]Fe_2O_3$ contains= 2 atoms of iron

$1 mole of [tex]Fe_2O_3$ contains= $2* 6.023* 10^(23)=12.05* 10^(23)$ atoms of iron

thus 0.32 moles of $Fe_2O_3$ contains= $(12.05* 10^(23))/(1)* 0.32=3.9* 10^(23)$ atoms of iron

Thus the sample would have $3.9* 10^(23)$ iron atoms.

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Conversion of minus 1 coulomb meter in debye

____________ acids are proton donors. ____________ bases are proton acceptors. The ____________ the pKₐ the stronger the acid. ____________ acids are electron pair acceptors.

Answers

Answer:

1. Bronsted—Lowry acid

2. Bronsted—Lowry Base

3. Lower the pka

4. Lewis acids

Explanation:

2. Which test for iron(II) ions is conclusive

Answers

The conclusive test for iron(II) ions is the test by the use of potassium hexacyanoferrate III solution.

In qualitative analysis certain reagents are used to test for the presence of certain cations or anions. Those reagents react in a certain way with those reagents. Usually, a positive test may involve a color change, formation of a precipitate or evolution of a gas.

In the case of iron(II) ions, potassium hexacyanoferrate III solution is used in the conclusive qualitative test for the ion. A positive test involves the appearance of a deep blue precipitate.

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Answer:

please brainlist answer

Explanation:

The addition of K 3 Fe(CN) 6 to a solution causes the formation of a deep blue precipitate which indicates that iron(II) ions are present.

If a sample contains 84.0 % of the R enantiomer and 16.0 % of the S enantiomer, what is the enantiomeric excess of the mixture

Answers

Answer:

enantiomeric excess = 68%

Explanation:

Enantiomeric excess is a value used to determine the purity of chiral molecules. It is possible to determine enantiomeric excess (ee) using:

ee = R - S / R + S * 100

Where R is the mass (In this case percentage) of the R enantiomer and S of the S enantiomer.

Replacing with values of the problem:

ee = 84% - 16% / 84% + 16% * 100

ee = 68%

Final answer:

The enantiomeric excess of the mixture, defined as the difference between the concentrations of the R and S enantiomers, is 68.0%.

Explanation:

The enantiomeric excess (ee) is defined as the absolute difference between the mole percentage of the major enantiomer and the minor enantiomer in a mixture. In a sample that contains 84.0 % of the R enantiomer and 16.0 % of the S enantiomer, the enantiomeric excess is calculated as follows:

Calculation: The enantiomeric excess is 84.0% (R) - 16.0% (S) = 68.0%

Therefore, the enantiomeric excess of the mixture is 68.0%.

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Given the following equation: 8 Fe + S8 ---> 8 FeSHow many moles of iron are needed to react with 16.0 moles of sulfur?
A FULL STEP EXPLANATION WILL BE APPRECIATED

Answers

The number of moles of iron needed to react with 16.0 moles of sulfur is 128.0 moles.

Calculation of number of moles of iron

Given equation, 8Fe + S8 = 8 FeS

Moles of sulfur = 16.0

To react 1 mole of sulfur, we need 8 moles of Fe

So, for 16.0 moles of sulfur we need

$16.0* 8 = 128.0 moles$

Thus, to react with 16.0 moles of Sulfur, 128.0 moles of Fe is needed.

Learn more about sulfur, here:

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Answer:

To react with 16.0 moles of sulfur we need 128.0 moles of iron (Fe).

Explanation:

Step 1: Data given

Number of moles Sulfur = 16.0 moles

Step 2: The balanced equation

8 Fe + S8 → 8 FeS

Step 3: Calculate mole Fe

For 8 moles Fe we need 1 mol S8 to produce 8 moles FeS

For 16.0 moles of Sulfur we need 8*16.0 = 128.0 moles

To react with 16.0 moles of sulfur we need 128.0 moles of iron (Fe).

What is planck's theory?

Answers

One photon of light carries exactly one quantum of energy. Planck is considered the father of the Quantum Theory. According to Planck: E=h ν , where h is Planck's constant (6.62606957(29) x 10 -34 J s), ν is the frequency, and E is energy of an electromagnetic wave.

A theory in physics based on the principle that matter and energy have the properties of both particles and waves.

Which three are advantages of asexual reproduction?A:Offspring are more likely to survive environmental changes.

B:Some offspring are more likely to survive a disease.

C:Less energy is required to reproduce.

D:The population can increase from only one parent.

E:The population can increase quickly.

Answers

C, D, and E

A and B cannot be true because asexual reproduction means the parent organism is essentially creating clones of itself, providing no variation in DNA and making all offspring vulnerable to the same environmental changes and diseases as the parent.

Answer:

sorry if I get this wrong I think it is C

Explanation:

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