Calcium and bromine have formed a bond. Leading up to this, calcium gave up electrons. It was a(n)

Answers

Answer 1

Answer: Leading up to this, calcium gave up 2 valence electrons and thus was denoted as a cation. These 2 electrons were transferred to bromine, which received an overall negative charge because of the addition of 2 valence electrons in its valence shell, and thus formed a negatively charged ion, an anion.

Both formed an ionic bond, due to the electrostatic charge of attraction between the 2 oppositely charged ions. If many ions of Ca and Br are present and numerous ionic bonds have formed it will undergo an arrangement which is that of an ionic lattice, type of structure.

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Dumbledore thinks the students are now confident with significant figures; Snape is not so confident of this... Begrudgingly Snape decides to move forward in his lesson. His next lesson is in naming ionic compounds. He presents his students with sodium hydrogen sulfate and potassium permanganate. Which pair of ionic formulas is correct for these two compounds?(A) NaHSO3, KMnO4
(B) NaHSO2, KMnO4
(C) NaHSO4, KMnO4
(D) NaHSO4, KMnO3
(E) NaHSO3, KMnO3

Answers

Answer:

C) $NaHSO_(4), KMnO_(4)$

Explanation:

- For the sodium hydrogen sulfate:

The ending -ate of the word sulfate indicates that the compound comes from the ion sulfate that is $SO_(4)^(-)$ , so the compound formed by this ion will be $NaHSO_(4)$

- For the potassium permanganate:

The ending -ate of the word permanganate indicates that the compound comes from the ion $MnO^(-)_(4)$ , so the compound formed by this ion will be $KMnO_(4)$

A eraser has a mass of 4g and a volume of 2cm3 what is it’s density

Answers

Answer:

The answer is 2.0 g/cm³

Explanation:

The density of a substance can be found by using the formula

$density = (mass)/(volume) \n$

From the question

mass = 4 g

volume = 2 cm³

We have

$density = (4)/(2) \n$

We have the final answer as

2.0 g/cm³

Hope this helps you

Which of the following acids (listed with pKa values) and their conjugate base would form a buffer with a pH of 8.10?(A) HC7H5O2, pKa = 4.19
(B) HF, pKa = 3.46
(C) HClO, pKa = 7.54
(D) HCN, pKa = 9.31
(E) HClO2, pKa = 1.96

Answers

Answer:

The buffer of pH 8.10 will be formed by the HClO having pKa value of 7.54.

Explanation:

Buffer is defined as the substance that can withstand the changes in the solution due to addition of acid or base. Buffer acts to neutralize the small amounts of acids or base when added.

Buffer is composed of two parts:

A weak acid and its conjugate base and a weak base with its conjugate acid.

According to the Bronsted-Lowry theory,acids are the substances that release $\text {H^(2) }$ $\text H^(+)$ , whereas the substances that accept bases.

Similarly, when an acid loses a proton ( $\text H^(+)$ ) $\text {H^(2) }$ $\text {H^(+) }$ , it is converted into the conjugate base, such that the conjugate acid-base pair of HClO is $\text {H}^(+)/\text{ClO}^(-)$ .

The buffer range for a substance is either one unit more or one unit less than the pKa value of the given substance. Thus, to obtain the pH value of 8.10, the acid with pKa value of 7.54 will be selected. The pH range of $\text {H}^(+)/\text{ClO}^(-)$ will have the buffer range between 6.54 and 8.54. Thus, pH of 8.10 will be formed by

Hence, rest of the options are incorrect because the buffer range for given acids will not be close the given value of pH as 8.10.

For Further Reference:

brainly.com/question/14353715?referrer=searchResults

Answer:

Explanation:

A buffer is a solution that can resist abrupt changes in pH when acids or bases are added. It is formed by two components:

A weak acid and its conjugate base.
A weak base and its conjugateacid.

In this case, acid and base are defined according to Bronsted-Löwry theory, which states that acids are substances that release H⁺ and bases are substances that accept H⁺. Therefore, when an acid loses an H⁺ transforms into its conjugated base. For example, HF/F⁻ is a conjugate acid-base pair.

In buffers, when an acid is added, it reacts with the base to diminish its amount:

F⁻ + H⁺ ⇄ HF

Also in buffers, when a base is added, it reacts with the acid to diminish its amount:

HF + OH⁻ = F⁻ + H₂O

The optimum pH range of work of a buffer system (known as buffer range) is between 1 unit less and 1 unit more of pH than its pKa.

So, the buffer formed by HClO/ClO⁻ works optimally in the pH range 6.54-8.54. Since pH = 8.10 is in that interval, this would be the optimal choice.

how does the presence of a strong electrolyte in solution affect the colligative properties of a solution when compared to the same number of moles of a nonelectrolyte solute?

Answers

Answer:

lowered vapor pressure
higher boiling point

Explanation:

The colligative properties of a given solution can be defined as the properties of that solution that are dependent on the concentration of the molecules or ions of the solute in the solution, and not on the type or identity of that solute. Examples include:

1. vapor pressure lowering

2. boiling point elevation

3. freezing point depression

4. Osmotic pressure

In this case, vapor pressure would be lowered because with an electrolyte introduced into a solution, the number of solute particles would be larger because the solute particles dissociate into ions, thereby competing with the solvent molecules at the surface of the solution, which in turn reduces the rate at which the solvent evaporates and condenses. Vapor pressure is lower compared to a solution with the same number of moles of nonelectrolyte solute.

The higher the number of ions in the solution, the greater the colligative properties of the solution will be impacted.

Final answer:

The presence of a strong electrolyte in solution affects the colligative properties differently than a non-electrolyte solute. Strong electrolytes dissociate into ions, increasing the number of particles in solution. This affects colligative properties such as vapor pressure, boiling point elevation, freezing point depression, and osmotic pressure.

Explanation:

The presence of a strong electrolyte in solution affects the colligative properties differently than the same number of moles of a non-electrolyte solute. This is because strong electrolytes dissociate into ions when dissolved in solution, while non-electrolytes do not. The dissociation of strong electrolytes increases the total number of particles in solution, which affects colligative properties such as vapor pressure, boiling point elevation, freezing point depression, and osmotic pressure.

For example, let's compare a solution of 1 mole of sodium chloride (NaCl) to a solution of 1 mole of sucrose (C12H22O11). The sodium chloride will dissociate into Na+ and Cl- ions, which means there are now 2 particles in solution (1 Na+ and 1 Cl-) instead of just 1 molecule of sucrose. This higher particle concentration will result in a greater depression of the freezing point and elevation of the boiling point compared to the sucrose solution.

In summary, the presence of a strong electrolyte increases the number of particles in solution, leading to greater deviations in colligative properties compared to the same number of moles of a non-electrolyte solute.

Learn more about Colligative properties here:

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is the number of total atoms on the left side of a balanced equation always equal to the number of total atoms on the right side of the equation?

Answers

Yes, because conservation of mass

Yes each and every timee,

Practice the Skill 21.15b When the following ketone is treated with aqueous sodium hydroxide, the aldol product is obtained in poor yields. In these cases, special distillation techniques are used to increase the yield of aldol product. Predict the aldol addition product that is obtained, and propose a mechanism for its formation. For the mechanism, draw the curved arrows as needed. Include lone pairs and charges in your answer. Do not draw out any hydrogen explicitly in your products. Do not use abbreviations such as Me or Ph.

Answers

Answer:

Check the explanation

Explanation:

Kindly check the attached image below for the step by step explanation to the question above.

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