A sample of 76 g of NaCl is dissolved to make 1 L of solution. What is the molarity of the solution? Show your work.

Answers

Answer 1
Answer: The answer is 1.3 mol of NaCl.

We know that there is 76 g of NaCl in 1L of the solution.
But we need to calculate the molarity.
First, we will need the molar mass of NaCl, which is the sum of relative atomic masses of Na (22.99 g/mol) and Cl (35.45 g/mol):
Mr(NaCl) = A(Na) + A(Cl) = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol.

This says that there are 58.44 g of NaCl in 1 mole. So, in how many moles will be 76 g of NaCl)? Use the proportion:
58.44 g : 1 mol = 76 g : x

After crossing the products:
x * 58.44 g = 1 mol * 76 g
x = 76 / 58.44 mol = 1.3 mol
Answer 2
Answer:

Answer:

1.3005 M

Explanation:

Given that:

Mass of NaCl = 76 g

Molar mass of NaCl = 58.44 g/mol

The formula for the calculation of moles is shown below:

moles = (Mass\ taken)/(Molar\ mass)

Thus,

Moles= (76\ g)/(58.44\ g/mol)

Moles= 1.3005\ mol

Given that volume = 1 L

Considering:

Molarity=(Moles\ of\ solute)/(Volume\ of\ the\ solution)

Molarity=(1.3005)/(1)

Molarity = 1.3005 M


Related Questions

Which pair of atoms can form an ionic bond?* Na, K (Sodium, Potassium)* K, F (Potassium, Fluorine)* F, Cl (Fluorine, Chlorine)* Na, Ne (Sodium, Neon)
Which compound is a base? lemon juice sour milk vinegar soap
Which of the following molecules has correctly labeled bond dipoles?
Rule 2: hydrogen ---ate becomes ____________ acid
State the use of multimeters

2. A sample of iron has the dimensions of 2.0 cm x 3.0 cm x2.0 cm. It has a mass of 94.0 grams. What is the density of
iron? (8 points)

Answers

Answer:

first change cm to m and g to kg so you will find the volume first which is 0.02 by 0.03 by 0.02 your answer is 0.000012 m . using the formula density=mass/volume take 0.094/ 0.00012 then divide

How far can a cough travel?

Answers

Traveling upwards of 200 mph or 320 km/h, and accelerating in a matter of seconds, germs from a cough or sneeze can travel a great distance very quickly.

How would I go about solving this problem? Sodium bicarbonate reacts with sulfuric acid to form sodium sulfate, carbon dioxide, and water. Calculate the mass od sodium bicarbonate necessary to produce 1.75 g of carbon dioxide gas.

Answers

The first thing you need to do with problem of this kind is to write the chemical equation. This would help you in calculations later. First, convert how many moles are there in 1.75g of carbon dioxide. Then, from the chemical equation you will know how many moles of sodium bicarbonate formed with 1 mole of carbon dioxide. Then convert the moles of sodium bicarbonate to grams using the molecular weight of the compound. You now have your answer. 

The total number of sodium atoms in 46.0 grams of solution is?

Answers

First step, is to find the Molar Mass.
If you go to the periodic table, the Molar Mass of the Sodium Na is 23g/mol

Second Step, you convert from grams to moles.
number of Mole = mass of sodium / molar mass = (46)/(23)  = 2 mol

Third Step, you find the number of atoms.
As We know, Avogadro said that the number of atoms in 1 mole is about 6.022 * 10^(23).
You use the Rule of three and you find the number of atoms!
1 mole = 6.022 * 10^(23) atoms
2 mole = x atomes
x = 2 * ( 6.022 * 10^(23) )
x= 12.044 * 10^(23) atomes

So, there is 12.044 * 10^(23) atoms of Sodium Na in 46g of Solution.

Hope this Helps! :D
molar mass Na = 23g/mol
46g = 456/2 = 2mol
1mol = 6.022*10^23 atoms
2mol = 2*6.022*10623
= 1.204*10^24 atoms

In general, the solubility of ________ in water decreases as temperature increases.

Answers

Solubility of a gas in a liquid is directly proportional to the partial pressure of the gas present above the liquid and is inversely proportional to the temperature.

So, the solubility of gas in water decreases as the temperature increases.

Answer:

solubility increases

Explanation:

A student requires 2.00 L of 0.100 M NH4NO3 from a 1.75 M NH4NO3 stock solution. What is the correct way to get the solution?

Answers

To solve this we use the equation,

 

M1V1 = M2V2

 

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

 

1.75 M x V1 = 0.100 M x 2.0 L

V1 = -.11 L


Answer : The volume of NH_4NO_3 stock solution is, 0.114 L

Solution :

According to the dilution law,

M_1V_1=M_2V_2

where,

M_1 = molarity of NH_4NO_3 solution = 0.100 M

V_1 = volume of NH_4NO_3 solution = 2.00 L

M_2 = molarity of NH_4NO_3 stock solution = 1.75 M

V_2 = volume of NH_4NO_3 stock solution = ?

Now put all the given values in the above law, we get the volume of NH_4NO_3 stock solution.

(0.100M)* (2.00L)=(1.75M)* V_2

V_2=0.114L

Therefore, the volume of NH_4NO_3 stock solution is, 0.114 L