The frequency of two alleles in a gene pool is 0.1 (A) and .9 (a). The percentage in the population of heterozygous in individuals is 18%, and the percentage of homozygous recessives is 81%.
The frequency of two alleles in a gene pool is 0.1 (A) and .9 (a). Hence,
p = 0.1 and q = 0.9
The equation for the Hardy-Weinberg principle is:
p² + 2pq + q² = 1
p² + 2pq represents the frequency of heterozygous individuals and q² represents the frequency of homozygous recessives
Substituting the values:
p² + 2pq + q² = 11 × 0.01 + 2 × 0.1 × 0.9 + 0.81 = 1 = 0.01 + 0.18 + 0.81= 1
Therefore, the percentage of heterozygous in individuals is:
p² + 2pq = 0.18 × 100% = 18%
And the percentage of homozygous recessives is:
q² = 0.81 × 100% = 81%
Thus, the percentage in the population of heterozygous individuals is 18%, and the percentage of homozygous recessives is 81%.
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Answer:
Formula for sulfuric acid is H2SO4
Explanation:
Sulfuric acid is highly concentrated acid. It is known as king of chemicals. It is used in making of fertilizers, paints, dyes, detergents, etc.
H2SO4 is made in laboratory in different steps from burning of sulfur and oxygen. The sulfur is burned with air and oxygen is combined with it to form sulfur dioxide ( SO2).
Then SO2 is again mixed with oxygen in the presence of catalyst vanadium. It forms sulfur trioxide ( SO3). The sulfur trioxide is allowed to absorbed in water. The mixing of SO3 and H2O forms the sulfuric acid ( H2SO4).
It is highly concentrated and its dilution is decreased to some extent for selling.
Answer:
it is actually the cytoplasm
Explanation:
this boi right here is a lie
B. Nucleus
C. Cell Wall
D. Mitochondria
I know it is not C-Cell Wall.