jamie is not sure a new medication will work because it has not had a large test group. Is jamie being creative?

Answers

Answer 1
Answer:

No, he is being skeptical.

In the situation above Jamie doubts because the test was done with a small sample. He thinks the results are uncertain because it is needed a big sample to avoid mistakes and icrease the reliability of the study. So, this leads to scepticism, which means doubt about the truth of something, this is what Jamie does in the situation, this is why he is being skeptical.  

Answer 2
Answer: no, they're being skeptical.

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if a free falling rock were equipped with a speedometer, by how much would it's speed readings increase with each second IF it were on a planet where g= 20 m/s^2? would it be 60?

Answers

accelleration(a) is changing of velocity in second.
free fall a = g
speed increase = a = g = 20 (m/s) / s

A student throws a rock horizontally from the edge of a cliff that is 20 m high. The rock has an initial speed of 10 m/s. If air resistance is negligible, the distance from the base of the cliff to where the rock hits the level ground below the cliff is most nearlya.5m
b.10m
c.20m
d.40m
e.200m

Answers

Answer:

c.20

Explanation:

Which of the following is true of iambic pentameter?a. It has 14 syllables per line.
b. It is divided into a pair of fives.
c. It has a stressed syllable followed by an unstressed syllable.
d. It is present in both Italian sonnets and Shakespearean sonnets.

Answers

a).  No. "Pentameter" has 10 syllables per line.

b).  No.  This choice doesn't mean anything.

c).  No.  This is the description of a trochee, not an iamb.

d).  I don't know anything about Italian sonnets.  But I do know that
Shakespeare used iambic pentameter, and the other choices have
been eliminated, so I'll go with this one.  (the "multiple-guess" method)

a stone is dropped from the top of 50 m high tower simultaneously another stone is thrown upward with a speed of 20 m/s . calculate the time at which both the stones cross each other

Answers

'H' = height at any time
'T' = time after both actions
'G' = acceleration of gravity
'S' = speed at the beginning of time
Let's call 'up' the positive direction.
Let's assume that the tossed stone is tossed from the ground, not from the tower.

For the stone dropped from the 50m tower:

H = +50 - (1/2) G T²

For the stone tossed upward from the ground:

H = +20T - (1/2) G T²

When the stones' paths cross, their Heights are equal.

50 - (1/2) G T² = 20T - (1/2) G T²

Wow !  Look at that !  Add (1/2) G T² to each side of that equation,
and all we have left is:

50 = 20T  Isn't that incredible ? ! ?

Divide each side by 20 :

2.5 = T

The stones meet in the air 2.5 seconds after the drop/toss.

I want to see something: 
What is their height, and what is the tossed stone doing, when they meet ?

Their height is  +50 - (1/2) G T² = 19.375 meters

The speed of the tossed stone is  +20 - (1/2) G T = +7.75 m/s ... still moving up.
I wanted to see whether the tossed stone had reached the peak of the toss,
and was falling when the dropped stone overtook it.  The answer is no ... the
dropped stone was still moving up at 7.75 m/s when it met the dropped one.

An object traveling at a constant speed but with a changing direction is accelerating. a. True
b. False

Answers


Strange as it may seem, that's true. (choice 'a'.)

"Acceleration" doesn't mean "speeding up".  It means ANY change in
the speed or direction of motion.  So a car with the brakes applied
and slowing down, and a point on the rim of a bicycle wheel that's
turning at a constant rate, are both accelerating.

True, it is still moving. 

D= ((vf+vi)/2) t
Solve for vi

Answers

D= ((vf+vi)/2) t

D = (vf +vi)*t/2

2*D = (vf +vi)*t

2D/t = vf +vi

vf +vi =  2D/t

vi = 2D/t - vf
= t(Vf + Vi/2) 
Vf + Vi/2 = d/t 
Vf = (d/t) - Vi/2 

Answer: Vf = (d/t) - Vi/2 OR (2dt - Vit)/2t