Answer:
The correct answer is 5.6 × 10⁻²³ M.
Explanation:
As a highly soluble salt, KBr dissolves easily in water, while Hg₂Br₂ is very less soluble in comparison to KBr.
Let the solubility of Hg₂Br₂ is S mol per liter.
Therefore,
KBr (s) (1.0 M) ⇒ K⁺ (aq) (1M) + Br⁻ (aq) (1M)
Hg₂Br₂ (s) (1-S) ⇔ Hg₂⁺ (aq) (S) + 2Br⁻ (aq) (2S)
Net [Br-] = (2S + 1) M
Ksp = S (2S + 1)²
Ksp = S (4S² + 1 + 4S)
Ksp = 4S³ + S + 4S²
As the solubility is extremely less, therefore, we can ignore S² and S³. Now,
Ksp = S = 5.6 × 10⁻²³ M
Hence, the solubility of Hg₂Br₂ is 5.6 × 10⁻²³ M.
A lab group was calculating the speed of a radio car. They measured the distance traveled to be 6 meters and the time to be 3.5 seconds. Then they divided the distance by the time to find the speed. The actual speed was 2.2 m/s. Their percent error is 22.1%.
Percent error is a measure of the difference between an observed value and a true value.
Actual Speed (True Value) = 2.2 m/s
Experimental Speed (Calculated Value) = Distance / Time = 6 m / 3.5 s = 1.714 m/s
The formula for calculating percent error is:
Percent Error = ((|Actual Value - Experimental Value|) / |Actual Value|) * 100%
Calculate the absolute difference between the actual speed and the experimental speed:
|2.2 - 1.714| = 0.486
Calculate the absolute value of the actual speed:
|2.2| = 2.2
Percent Error = (0.486 / 2.2) * 100%
= 0.221 * 100%
= 22.1%
The calculated percent error is approximately 22.1%. This means that the lab group's calculated speed of 1.714 m/s is about 22.1% lower than the true speed of 2.2 m/s.
Percent error is a way to quantify the accuracy of experimental measurements. A positive percent error indicates that the experimental value is higher than the true value, while a negative percent error indicates that the experimental value is lower. In this case, since the calculated speed is lower than the true speed, we have a positive percent error.
To know more about actual speed here
#SPJ3
Answer:456
Explanation:
Substance A: 8.2 g/cm3
Substance B: 3.5 cm and 30.0g
Substance C: 10.0g and 40mL
Substance D: 0.5 g/cm3
Substance E: 2.0cm by 3.0cm by 1.0cm and 4.0g
Most Dense_ _ _ _ _
Least Dense
The order of density of substances ranging from most dense to least dense is :substance B>substance A>substance E>substance C>substance D.
It is a ratio of substance's mass per unit of volume.Symbol most commonly used for density is р.The SI unit of densityis kilogram per cubic meter .It explains how tightly a material is packed together.
There are2 types of density :1)absolute density 2) relativedensity.Absolute density is the massof any substance per unit volume and relative density is the ratio of density of a substance to the density of a given reference material.
Reference material used forrelative density is water.The instrument used for measuring density or relative density of liquids is hydrometer. Densityis measured at constant temperature and pressure.
To learn more about density and it's types click here:
#SPJ2
Answer:
So 1st it is B then D then E then a then C
The density of the cylinder would be 3.652 gram/ cm³
.
It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
As given in the problem, you just measured a metal cylinder and obtained the following information: mass - 3.543 grams, diameter 0.53 cm, height = 4.40 cm , and we have to calculate the density of the cylinder,
mass of the cylinder = 3.543 grams
the volume of the cylinder = πr²h
= 3.14 ×.265²×4.4
=0.97 cm³
By using the above formula for density
ρ = mass of the cylinder/volume of the cylinder
= 3.543 grams/0.97 cm³
=3.652 grams/ cm³
Thus,the density of the cylinder would be 3.652 grams/ cm³.
To learn more about density from here, refer to the link;
#SPJ2
Answer:
V cylinder =
note that
density =
2.09 x 1020
O 2.31% 10110
O 1.18 x 102 103
O 1.11% 1021)
Answer: The pH of the buffer is 4.61
Explanation:
To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
We are given:
= negative logarithm of acid dissociation constant of weak acid = 4.70
= moles of conjugate base = 3.25 moles
= Moles of acid = 4.00 moles
pH = ?
Putting values in above equation, we get:
Hence, the pH of the buffer is 4.61
B) 3
C) 4
D) 7
Answer
A(1)
Explanation:
If you don't see a coefficient, which is the big number in front of the formula, then it's only one molecule.
Example of coefficient
4H3PO4