The specific heat capacity of liquid water is 4.18 J/g-K. How many joules of heat are needed to raise the temperature of 5.00 g of water from 25.1°C to 65.3°C?

Answers

Answer 1
Answer:

Answer:

840.18

Explanation:

Use the equation: Q = mcΔT

m = mass (5 g)

c = specific heat (4.18)

ΔT = change in temperature (65.3-25.1 = 40.2)

5*4.18*40.2 = 840.12


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Which of the following statements best explains why the atomic radius increases from top to bottom of the periodic table? A. The electronegativity decreases from top to bottom of the periodic table, so the atoms near the bottom have an increased capacity for electrons. B. For the atoms lower in the periodic table, there is more difference in charge between the electrons and the protons, which allows electrons to orbit farther from nucleus. C. The ionization energy decreases from top to bottom of the periodic table, so the atoms near the bottom have an increased capacity for electrons. D. For the atoms lower in the periodic table, the valence electrons are in higher energy levels and farther from the nucleus.

Answers

Answer:

D. For the atoms lower in the periodic table, the valence electrons are in higher energy levels and farther from the nucleus.

Explanation:

Atomic radius increases down the group because down the group, there an increase in the number of principle energy levels occupied. Now, these higher principal energy levels are made up of orbitals that are larger than the orbitals from the lower energy levels in size.

Therefore, the effect of this is that the greater number of principal energy levels will outweigh the increase in nuclear charge since nuclear charge also increases down the group and this in turn makes the atomic radius to increase as we go down the group.

Answer: C. For the atoms lower in the periodic table, the balance electrons are in higher energy levels and farther from the nucleus.

Explanation: As the valance electrons orbit farther from the nucleus the energy level increases from the top to the bottom of the periodic table. So the atoms lower in the periodic table, the balance electrons are in higher energy levels and farther from the nucleus, which result in an increase in the atomic radius.

Consider the titration of 25.0 mL of 0.340 M HCl with 0.160 M NaOH. What volume of NaOH is required to reach the equivalence point?

Answers

Answer:

53.1 mL NaOH

Explanation:

Draw a well-labelled diagram showing how your body digests food​

Answers

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Explanation:

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How many sulfide ions are in 15 dg of sodium sulfide?O 1.16 x 1022
O 3.04 x 1028
O 5.76 x 1029
O 6.02 x 1023
O 3.13

Answers

There are 5.78 × 10^20 sulfide ions in sodium sulfide

The formula of the compound is Na2S. The molar mass of the compound is calculated as follows; 2(23) +32 = 46 + 32 = 78 g/mol

Number of moles of Na2S = 0.15 g/ 78 g/mol = 0.0019 moles

Since there is 1 mole of Na^+ and 2 moles of S^2- in Na2S, the number of S^2- ions in  0.19 moles of Na2S is 0.00096 moles of S^2-.

If 1 mole of S^2- contains 6.02  × 10^23

0.095 moles of S^2- contains 0.00096 moles × 6.02  × 10^23/ 1 mole

= 5.78 × 10^20 sulfide ions

Learn more: brainly.com/question/1309057

Consider the balanced equation for the following reaction:7O2(g) + 2C2H6(g) → 4CO2(g) + 6H2O(l)
Determine the amount of CO2(g) formed in the reaction if 8.00 grams of O2(g) reacts with an excess of C2H6(g) and the percent yield of CO2(g) is 90.0%.

Answers

Answer: The amount of carbon dioxide formed in the reaction is 5.663 grams

Explanation:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of oxygen gas = 8 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen gas}=(8g)/(32g/mol)=0.25mol

For the given chemical equation:

7O_2(g)+2C_2H_6(g)\rightarrow 4CO_2(g)+6H_2O(l)

By Stoichiometry of the reaction:

7 moles of oxygen gas produces 4 moles of carbon dioxide

So, 0.25 moles of oxygen gas will produce = (4)/(7)* 0.25=0.143mol of carbon dioxide

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 0.143 moles

Putting values in equation 1, we get:

0.143mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\n\n\text{Mass of carbon dioxide}=(0.143mol* 44g/mol)=6.292g

To calculate the experimental yield of carbon dioxide, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}* 100

Percentage yield of carbon dioxide = 90 %

Theoretical yield of carbon dioxide = 6.292 g

Putting values in above equation, we get:

90=\frac{\text{Experimental yield of carbon dioxide}}{6.292g}* 100\n\n\text{Experimental yield of carbon dioxide}=(90* 6.292)/(100)=5.663g

Hence, the amount of carbon dioxide formed in the reaction is 5.663 grams

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Answers

Answer:

C

Explanation: