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You wish to prepare 100 mL of a 0.100 M solution by dilution of a 1.00 M solution. Which of the following pieces of glassware will you use? A. 100 mL graduated cylinder
B. 100 mL volumetric flask
C. 10 mL volumetric pipet
D. 25 mL volumetric pipet
E. 10 mL graduated pipet
F. 25 mL graduated pipet

Answers

Answer 1
Answer:

Answer:

C

Explanation:

The volumetric pipet is designed for a specific volume of solution. In this case, a 10 mL of volumetric pipet is required to take exactly 10 mL of the solution 1.00 M and add into a volumetric flask of 100 mL. Then water or solvent(s) can be added to reach the ring of the volumetric flask. This volumetric flask is also a laboratory equipment for precis dilutions beside the volumetric pipet

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A sample of iron having a mass of 93.3g is heated to 65.58OC is placed in 75.0g ofwater raising the temperature from 16.95 OC to 22.24 OC. Find the specific heatcapacity for this iron sample. The answer you find has had some lab errors due tohuman mistakes. Find your percent error for your work using %Error = [(Expected - Actual) / (Expected Yield)] x100

Answers

The heat gained or lost by a substance undergoing a change in temperature is:
Q = mCpΔT
The heat lost by the iron is equal to that gained by water. The Cp for water is 4.186 Joules/gram

75 x 4.186 x (22.24 - 16.95) = -93.3 x Cp x (22.24 - 65.58)
Cp = 0.411 J/g

The heat capacity of iron is 0.45 J/g

%Error = [(0.45 - 0.41) / 0.41] x 100
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How many mL of 0.100 M NaOH are needed to neutralize 50.00 mL of a 0.150 M solution of CH3CO2H, a monoprotic acid? How many mL of 0.100 M NaOH are needed to neutralize 50.00 mL of a 0.150 M solution of CH3CO2H, a monoprotic acid? a. 37.50 mL
b. 50.00 mL
c. 75.00 mL
d. 100.00 mL
e. 25.00 mL

Answers

Answer:

We need 75 mL of 0.1 M NaOH ( Option C)

Explanation:

Step 1: Data given

Molarity of NaOH solution = 0.100 M

volume of 0.150 M CH3COOH = 50.00 mL = 0.05 L

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles of CH3COOH

Moles CH3COOH = Molarity * volume

Moles CH3COOH = 0.150 M * 0.05 L

Moles CH3COOH =  0.0075 moles

Step 4: Calculate moles of NaOH

For 1 mol of CH3COOH we need 1 mol of NaOH

For 0.0075 mol CH3COOH we need 0.0075 mole of NaOH

Step 5: Calculate volume of NaOH

volume = moles / molarity

volume = 0.0075 moles / 0.100 M

Volume = 0.075 L = 75 mL

We need 75 mL of 0.1 M NaOH

4-methyl-3-hexanol was prepared by reacting an alkene with either hydroboration-oxidation or oxymercuration-reduction. Draw the structure of the alkene that was used to prepare the alcohol in highest yield.

Answers

Answer:

Structure in attachment.

Explanation:

The oxymercuration-demercuration of an asymmetric alkene usually produces the  Markovnikov orientation of an addition. The electrophile ⁺Hg(OAc), formed by the electrophile attack of the mercury ion, remains attached to least substituted group at the end of the double bond. This electrophile has a considerable amount of positive charge on its two  carbon atoms, but there is more positive charge on the more substituted carbon atom,  where it is more stable. The water attack occurs on this more electrophilic carbon, and the Markovnikov orientation occurs.

In hydroboration, borane adds to the double bond in one step. Boron is added to the less  hindered and less substituted carbon, and hydrogen is added to the more substituted carbon. The electrophilic boron atom adds to the less substituted end of the double bond, positioning the positive charge (and the hydrogen atom) at the more substituted end. The result is a product with the anti-Markovnikov orientation.

Use the weather map to answer the question.Weather map with blue line with triangles pointing down and to the right. Red line with semi-circles pointing up and to the right. Red line is to the right of the blue line.
© Dorling Kindersley / Universal Images Group / Image Quest 2016

What does the red line indicate?

A. A cold front is moving to the north and east.
B. A cold front is moving to the south and west.
C. A warm front is moving to the north and east.
D. A warm front is moving to the south and west.

Answers

I think the answers to this is d

Answer: It's D. A warm front is moving to the south and west.

Explanation: I got it right on the test

Write Lewis structural formulas for the following molecules: NH3 SO2
CH3OH HNO2
N2 CH2O

Answers

Answer :  The Lewis-dot structure of the following molecules are shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

(1) The given molecule is, NH_3

As we know that hydrogen has '1' valence electron, nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in NH_3 = 5 + 3(1)  = 8

According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.

(2) The given molecule is, SO_2

As we know that sulfur and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in SO_2 = 6 + 2(6)  = 18

According to Lewis-dot structure, there are 8 number of bonding electrons and 10 number of non-bonding electrons.

(3) The given molecule is, CH_3OH

As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in CH_3OH = 4 + 4(1) + 6  = 14

According to Lewis-dot structure, there are 10 number of bonding electrons and 4 number of non-bonding electrons.

(4) The given molecule is, HNO_2

As we know that hydrogen has '1' valence electron, nitrogen has '5' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in HNO_2 = 1 + 5 + 2(6) = 18

According to Lewis-dot structure, there are 8 number of bonding electrons and 10 number of non-bonding electrons.

(5) The given molecule is, N_2

As we know that nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in N_2 = 2(5) = 10

According to Lewis-dot structure, there are 6 number of bonding electrons and 4 number of non-bonding electrons.

(6) The given molecule is, CH_2O

As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in CH_2O = 4 + 2(1) + 6  = 12

According to Lewis-dot structure, there are 8 number of bonding electrons and 4 number of non-bonding electrons.

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Answers

evaporation is when liquid turns into gas
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