Answer:
Explanation:
Depression in freezing point is given by:
= Depression in freezing point
i= vant hoff factor = 1 (for non electrolyte like glycine)
= freezing point constant = ?
m= molality
Weight of solvent = 950 g = 0.95 kg
Molar mass of glycine = 75.07 g/mol
Mass of glycine added = 282 g
Thus freezing point constant is
2)
= Depression in freezing point
i= vant hoff factor = 4 (for )
= freezing point constant =
m= molality
Weight of solvent = 950 g = 0.95 kg
Molar mass of = 162.2 g/mol
Mass of added = ?
Thus mass of iron(III) chloride that must be dissolved in the same mass of to produce the same depression in freezing point is
Answer:
Explanation:
Hello,
In this case, by using the given data for glycine, one computes the freezing point constant of the mystery liquid as shown below, considering the molality of the glycine and its van't Hoff factor equal to the unity:
Now, as we are looking for the mass of iron(III) chloride at the same conditions of the aforesaid case, at first, one solves for the molarity of such compound considering that its theoretical van't Hoff factor is 4 as follows:
Now, one obtains the requested mass via:
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The amount of heat will be 5230 j.
What is heat?
Heat is a type of energy that is transferred between both the system and its surroundings as a result of temperature variations.
Calculation of heat.
Given data:
Mass = 25.0 g = 0.025 kg
C = 4.184 J/g°C
= 80.0°C
= 30.0°C
Q= ?
By using the formula of heat.
Q = MC ()
Put the value of given data in heat equation.
Q(heat) = 0.025 × 4.184 ( 30 - 80)
Q(heat) = 5230 J.
Therefore, the amount of heat will be 5230 J.
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Answer:
5230 J
Explanation:
m = 25 g = 0,025 kg
c = 4,184 J /(g * °C) = 4184 J /(kg * °C)
= 80 °C
= 30 °C
The formula is Q = c *m * ()
Calculating:
Q = 4184 * 0,025 * (30 - 80) = 5230 J
Note that we get a negative heat (-5230 J). It just means that it is released.
Explanation:
pH is use calculate the acidic strength of a substance ,
The value of pH is calculated as , negative log of the concentration of Hydrogen ions .
Therefore ,
pH = - log [ H ⁺]
rearranging the above equation , to find the hydrogen ion concentration . log [ H ⁺] = pH
log [ H ⁺] = - pH
[ H ⁺] = antilog ( - pH )
Hence , from the question , the hydrogen ions can be calculated by using the above equation ,
( 1 )
pH = 6.95
Since ,
[ H ⁺] = antilog ( - pH )
[ H ⁺] = antilog ( - 6.95 )
[ H ⁺] = 1.12 * 10 ⁻⁷
( 2 )
pH = 7.25
Since ,
[ H ⁺] = antilog ( - pH )
[ H ⁺] = antilog ( - 7.25 )
[ H ⁺] = 5.62 * 10 ⁻⁸
( 3 )
pH = 8.1
Since ,
[ H ⁺] = antilog ( - pH )
[ H ⁺] = antilog ( - 8.1 )
[ H ⁺] = 7.94 * 10 ⁻⁹
The formula for osmotic pressure is:
where is osmotic pressure, is van't Hoff's factor, molarity, is Ideal gas constant, and T is Temperature.
= 132 atm
The van't Hoff's factor for glucose, = 1
Substituting the values in the above equation we get,
So, the molarity of the solution is .
a. Weather
b. Altitude
c. Latitude
d. Climate
Answer:
c. Latitude
Explanation:
The angular distance north or south from the earth's equator beginning at 0° at the equator and ending at 90° of either pole is the latitude.
The equator is a line of latitude that divided the earth into two hemispheres.
Only the equator is a great circle as a line of latitude. Others are small circles.
When you fill a basin with liquid water, you can see that the water takes the shape of the container in which it is contained. This is because in the liquid state, water has molecules farther apart than in the solid state.
You can notice this property when performing an experiment with liquid and solid water.
When filling a glass, liquid water takes on the shape of a glass, and solid water, such as an ice cube, remains the same shape when placed in a glass.
Therefore, when filling a basin with water we perceive a property of the physicalstate of water, in liquid form. Water is one of the few substances that can be found naturally in liquid, solid and gaseous states.
Learn more here:
Answer:
Cautiously and avoiding filling in the central area so that it does not overflow when filling, since being very beach makes filling difficult.
Explanation:
The basins are shallow, that is why filling is difficult, the filling must be slow, low intensity and at the edges not placing the water filling in the center of the basin.