Looking at the different chemical structures, which one(s) might be able to holdcancer fighting drugs and could then travel through the body safely until they
released the drugs into the cancer cells?
a) Graphite and diamond because these well known substances have been used
for years to treat cancer
b) Graphite because it is found in pencils and is a good lubricant
c) Fullerene and carbon nanotubes because they have empty spaces inside the
molecules
d) Diamond because it is one of the hardest substances

Answers

Answer 1
Answer:

Answer:

c) Fullerene and carbon nanotubes because they have empty spaces inside the  molecules

Explanation:

Fullerene and carbon nanotubes would be the most desired in order to hold the cancer fighting drugs and to carry them through the body safely.

  • These molecules have empty spaces in them.
  • The cavities makes it possible for storage.
  • As they pass through the body, they can be held perfectly well to their target site of action.

Related Questions

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What is colloidal solutions ​
After mixing the solutions in a separatory funnel, the stopper should be ______ and the liquid should be _______ and the layers allowed to separate. When you get close to the interface between the layers, ______ the funnel and turn over _______ heat up until the first layer is collected get eye level with to collect the second layer. _______
When calcium carbonate reacts with hydrogen chloride, if the reaction occurs with 78.5% yield, what mass of carbon dioxide will be collected if 19.88g of CaCO3 is added to sufficient hydrogen chloride?
Help! Can someone please explain and break down the answers to both? I’m so confused!1) The moles of H2O that f am be obtained from 15.0mL of 0.250 M HCl2) the volume of 0.150 M KMnO4 needed to replaced 1.85 mol MnCl2

What is the symbol of the element that is classified as an alkali metal and is in period 4?

Answers

Answer:

Potassium (K) [First element in period 4]

What is the molecular geometry if you have a double bond, a single bond and 1 lone pair around the central atom?

Answers

Answer:

4 pairs are needed for the bonds, leaving 1 lone pair. Each double bond uses 2 bond pairs and can be thought of as a single unit. There are 2 double bond units and 1 lone pair, which will try to get as far apart as possible - taking up a trigonal planar arrangement.

How much heat energy would be needed to raise the temperature of a 223 g sample of aluminum [(C=0.895 Jig Cy from 22.5°C to 55 0°C? Η Ο Ο Ο ΟΟ 10x10) not enough information given Prov 40 25 11 Next >

Answers

Answer : The heat energy needed would be, 6486.5125 J

Explanation :

To calculate the change in temperature, we use the equation:

q=mc\Delta T\n\nq=mc(T_2-T_1)

where,

q = heat needed = ?

m = mass of aluminum = 223 g

c = specific heat capacity of aluminum = 0.895J/g^oC

\Delta T = change in temperature

T_1 = initial temperature = 22.5^oC

T_2 = final temperature = 55.0^oC

Putting values in above equation, we get:

q=223g* 0.895J/g^oC* (55.0-22.5)^oC

q=6486.5125J

Therefore, the heat energy needed would be, 6486.5125 J

The speed of light is 3.00×108m/s. How long does it take for light to travel from Earth to the Moon and back again?

Answers

The variable we have to determine for this problem is the time. Since the given information is speed, we have to know the distance so that we can solve for the time. From literature, the distance between the Earth and the moon is 384,400,000 meters. Therefore,

Speed = Distance/Time
Time = Distance/Speed
Time = 384,400,000 m/ 3×10⁸ m/s = 1.28 seconds

How does evidence of chemicalreactions indicate that new substances
with different properties are formed?

Answers

The chemical reaction indicate the formation of new substance by change in nature of original compound and shows chemical changes in the reaction.

What is chemical reaction?

Chemical reaction is defined as  process in which two or more molecules collide with the proper orientation and enough force to produce a new product.

It is also defined as a procedure in which one or more compounds, known as reactants, are changed into one or more distinct substances, known as products.

There are mainly seven types of reaction.

  • Synthesis reaction
  • Decomposition reaction
  • Displacement reaction
  • Double displacement reaction
  • Combustion reaction
  • Redox reaction
  • Acid-Base reaction

Thus, the chemical reaction indicate the formation of new substance by change in nature of original compound and shows chemical changes in the reaction.

To learn more about chemical reaction, refer to the link below:

brainly.com/question/3461108

#SPJ5

Answer:

Changes in Properties Changes in properties result when new substances form. For instance, gas production, formation of a precipitate, and a color change are all possible evidence that a chemical reaction has taken place. ... Change in Color A color change can signal that a new substance has formed.

Explanation:

4. Oxygenating myoglobin. The myoglobin content of some human muscles is about 8 g kg 1. In sperm whale, the myoglobin content of muscle is about 80 g kg 1 . (a) How much O 2 is bound to myoglobin in human muscle and in sperm whale muscle? Assume that the myoglobin is saturated with O 2, and that the molecular weights of human and sperm whale myoglobin are the same. Berg, Jeremy M.. Biochemistry (p. 213). W. H. Freeman. Kindle Edition.

Answers

Answer:

0.01454 grams of oxygen is present per kilogram of human muscle.

0.1454 grams of oxygen is present per kilogram of sperm whale muscle.

Explanation:

Given : The myoglobin is fully saturated with oxygen gas.

Moles of myoglobin = Moles of oxygen gas

Molecular mass of myoglobin = 17,600 g/mol

(assumed same fro whale and human )

Myoglobin content in humans = 8 g/kg

Mole of molyoglobin in human muscles per kg :(8 g/kg)/(17,600 g/mol)

Mass of oxygen present in per kg of human muscle:

Moles of oxygen gas × 32g/mol :

(8 g/kg)/(17,600 g/mol)* 32 g/mol=0.01454 g/kg of human muscle

Myoglobin content in whales= 80 g/kg

Mole of molyoglobin in whale muscles per kg :(80 g/kg)/(17,600 g/mol)

Moles of myoglobin = Moles of oxygen gas

Mass of oxygen present in per kg of sperm whale muscle:

Moles of oxygen gas × 32g/mol :

(80 g/kg)/(17,600 g/mol)* 32 g/mol=0.1454 g/kg of whale muscle