The temperature and pressure of an ideal gas are directly proportional
The pressure of the system should be in the range B) 94 psig
The given refrigerator parameters are;
The temperature of the system and the surrounding, T₁ = 75 °F = 237.0389 K
The pressure to which the system was charged with nitrogen, P₁ = 100 psig
The temperature to which the system dropped, T₂ = 50 °F = 283.15 K
The required parameter;
The pressure, P₂, of the system at 50°F
Method:
The relationship between pressure and temperature is given by Gay-Lussac's law as follows;
At constant volume, the pressure of a given mass of gas is directly proportional to its temperature in Kelvin
Mathematically, we have;
Plugging in the values of the variables gives;
Therefore;
The closest option to the above pressure is option B) 94 psig
Learn more about Gay-Lussac's law here;
Salary compression
B.
Occupational based pay
C.
Merit pay
D.
Need for Achievement
Answer:
do you have to make the right decisions to be a person who has been a member who is not the first time a great person who has a job in a day of his life or
True
False
Answer: true
Explanation:
Answer:
y=0.12 lbmol(water)/lbmol(products)
Explanation:
First we find the humidity of air. Using humidity tables and the temperature we find that is 0.01 g water/L air.
Now we set the equation assuming dry air:
With this equation we have almost all moles that exit the reactor, we are just missing the initial moles of water due to the humidity. So we proceed to calculate it with the ideal gas law:
PV=nRT
Vair=867.7L
With the volume and the fraction of water, we can calculate the mass of water:
0.01 * 867.7=8.677 g of water
Now we calculate the moles of water:
8.677 g / 18 g/mol = 0.48 moles of water
Now we can calculate the total moles of water in the exit of the reactor:
0.48 + 4 = 4.48 moles of water
And finally we just need to sum all moles at the exit of the reactor and divide:
3 moles of CO2 + 2.5 moles of O2+ 4.48 moles of H2O + 28.2 moles of N2
And we have 38.18 moles in total, then:
4.48/38.18=y=0.12 moles of water/moles of products
As the relation moles/moles is equal to lb-moles/lb-moles, we have our fina result:
y=0.12 lbmol(water)/lbmol(products)
Answer: Tl = - 13.3°C
the lowest outdoor temperature is - 13.3°C
Explanation:
Given that;
Temperature of Th = 21°C = 21 + 273 = 294 K
the rate at which heat lost is Qh = 5400 kJ/h°C
the power input to heat pump Wnet = 6 kw
The COP of a reversible heat pump depends on the temperature limits in the cycle only, and is determined by;
COPhp = Th/(Th - Tl)
COPhp = Qh/Wnet
Qh/Wnet = Th/(Th -Tl)
the amount of heat loss is expressed as
Qh = 5400/3600(294 - Tl)
the temperature of sink
( 5400/3600(294 - Tl)) / 6 = 294 / ( 294 - Tl)
now solving the equation
Tl = 259.7 - 273
Tl = - 13.3°C
so the lowest outdoor temperature is - 13.3°C
24Ω
When resistors are connected in parallel, the reciprocal of their combined resistance, when read with a DMM (Digital Multimeter - for measuring various properties of a circuit or circuit element such as resistance...) is the sum of the reciprocals of their individual resistances.
For example if two resistors of resistances R₁ and R₂ are connected together in parallel, the reciprocal of their combined resistance Rₓ is given by;
=
+
Solving for Rₓ gives;
=
------------------(i)
From the question;
Let
R₁ = resistance of first resistor = 40Ω
R₂ = resistance of second resistor = 60Ω
Now,
To get their combined or total resistance, Rₓ, substitute these values into equation (i) as follows;
=
=
= 24 Ω
Therefore, the total resistance is 24Ω
Answer:
24 ohms
Explanation:
pf
hope this helped :)
God bless you!!!!