5. What is the speed (Velocity) of a cyclist who covers 10 km (convert to metersfirst!) in 14 minutes and 30 seconds? Remember time must be in seconds first!

Answers

Answer 1
Answer:

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Actually Welcome to the Concept of the Kinematics.

Here, we know that, Velocity = Distance / Time,

So here, Distance = 10km = 10×1000 = 10000 metres.

, Time = 14 min 30 sec = 870 seconds,

so now, we get velocity as,

=> V = 10000 ÷ 870 => 11.49 m/s .

Hence, Velocity is 11.49 m/s.


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Base your answers on the graph below, which represents uniform cooling of a sample of a pure substance, starting as a gas. Solid and liquid phases can exist in equilibrium between points
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In chemical reactions, what does the law of conservation of mass mean?Group of answer choicesMatter is not created nor destroyed.The total mass of the products is greater than the total mass of the reactants.The total mass of the reactants is less that the total mass of the products.Matter is not changed.
4. An atom is neutral because it has the same number of protons as it has:electronsO neutronsO Neither... An atom isn't neutral!
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Which of the following is an example of a compound? water - H2Ooxygen-O2
hydrogen - H2
helium - He

Answers

Answer:

water

Explanation:

the other options are elements while water is 2 elements

Enter the oxidation number of one atom of each element in each reactant and product.CH4(g)+2O2(g)⟶CO2(g)+2H2O(g)
C in CH4 :
H in CH4 :
O in O2 :
C in CO2 :
O in CO2 :
H in H2O :
O in H2O :
Which atom is reduced?
Which atom is oxidized?

Answers

The oxidation numbers of the atoms of the specified elements in each of the given atoms are;

1) -4

1) -42) +1

1) -42) +13) 0

1) -42) +13) 04) +4

1) -42) +13) 04) +45) -2

1) -42) +13) 04) +45) -26) +1

1) -42) +13) 04) +45) -26) +17) -2

1) -42) +13) 04) +45) -26) +17) -2Atom oxidized = C

1) -42) +13) 04) +45) -26) +17) -2Atom oxidized = CAtom reduced = O

1) C in CH4

To get the oxidation number of C;

Oxidation state of hydrogen atom is +1 and so if the oxidation state of C is x, then we have;

x + 4(+1) = 0

x + 4 = 0

x = -4

2) H in CH4

Oxidation state on Carbon atom in this case is -4. Thus;

-4 + 4x = 0

4x = 4

x = +1

3) O in O2

This is oxygen gas that exists in it's free state and as such oxidation number is 0.

4) C in CO2

Oxidation state of O here is -2. Thus;

x + 2(-2) = 0

x - 4 = 0

x = +4

5) O in CO2

Oxidation state of C is +4 here. Thus;

4 + 2x = 0

2x = -4

x = -4/2

x = -2

6) H in H2O

Oxidation state of oxygen here is -2. Thus;

2x - 2 = 0

2x = 2

x = 2/2

x = +1

7) O in H2O

Oxidation state of hydrogen here is +1. Thus;

2(1) + x = 0

x = -2

Finally, oxidation number of carbon increased, then it is the atom that was oxidized while the atom reduced is the Oxygen atom.

Read more at; brainly.com/question/22816291

Answer:

1. -4

2. +1

3. 0

4. +4

5. -2

6. +1

7. -2

reduced = H

oxidized = O

Explanation:

Know oxidation rules.

- Hope this helped! Please let me know if you would like to learn this. I could show you the rules and help you work through them.

Looking at the different chemical structures, which one(s) might be able to holdcancer fighting drugs and could then travel through the body safely until they
released the drugs into the cancer cells?
a) Graphite and diamond because these well known substances have been used
for years to treat cancer
b) Graphite because it is found in pencils and is a good lubricant
c) Fullerene and carbon nanotubes because they have empty spaces inside the
molecules
d) Diamond because it is one of the hardest substances

Answers

Answer:

c) Fullerene and carbon nanotubes because they have empty spaces inside the  molecules

Explanation:

Fullerene and carbon nanotubes would be the most desired in order to hold the cancer fighting drugs and to carry them through the body safely.

  • These molecules have empty spaces in them.
  • The cavities makes it possible for storage.
  • As they pass through the body, they can be held perfectly well to their target site of action.

Consider four small molecules, A–D, which have the following binding affinities for a specific enzyme (these numbers are the equilibrium constants Kd for the dissociation of the enzyme/molecule complex). Which binds most tightly to the enzyme? Which binds least tightly?A) 4.5 μM

B) 13 nM

C) 8.2 pM

D) 6.9 mM

Answers

Answer:

Binding affinity measures the strength of the interaction between a molecule to its ligand; it is expressed in terms of the equilibrium dissociation constant; and the higher value of this constant, the more weaker the binding between the molecule and the ligand is. On the other hand, small constans means that the interaction is tight. So "C" binds most tightly to the enzyme and "D" binds least tightly.

What is the freezing point of a solution of 7.15 g MgCl2 in 100 g of water? K f for water is 1.86°C/m. What is the freezing point of a solution of 7.15 g MgCl2 in 100 g of water? K f for water is 1.86°C/m. -0.140°C -2.80°C -1.40°C -4.18°C

Answers

Answer:

THE NEW FREEZING POINT IS -4.196 °C

Explanation:

ΔTf = 1 Kf m

molarity of MgCl2:

Molar mass = (24 + 35.5 *2) g/mol

molar mass = 95 g/mol

7.15 g of MgCl2 in 100 g of water

7.15 g = 100 g

(7.15 * 100 / 1000) = 1000 g or 1 L or 1 dm3

= 0.715 g /dm3

Molarity in mol/dm3 = molarity in g/dm3 / molar mass

= 0.715 g /dm3 / 95 g/mol

m = 0.00752 mol/ dm3

So therefore:

ΔTf = i Kf m

1 = 3 (1 Mg and 2 Cl)

Kf = 1.86 °C/m

M = 0.752 moles

So we have:

ΔTf = 3 * 1.86 * 0.752

ΔTf = 4.196 °C

The new freezing point therefore will be 0 °C - 4.196 °C which is equals to - 4.196 °C

A student is heating a chemical in a beaker with a Bunsen burner.In a paragraph of at least 150 words, identify the safety equipment that should be used and the purpose of it for the given scenario.

Answers

When a student is warming a chemical in a container using a special burner, it is very important to focus on safety by using the right safety tools.

What is the safety equipment

First, the student needs to wear the right safety clothes like a lab coat, gloves, and goggles to protect themselves from getting splashed or hurt by chemicals. A lab coat stops chemicals from touching the skin, gloves keep the hands safe, and safety goggles protect the eyes from chemicals

and hot things.

Furthermore, using a fume hood is necessary to make sure there is enough fresh air circulating and to remove any dangerous fumes or gases that might be released while heating things up.

Read more about safety equipment here:

brainly.com/question/28389789

#SPJ3

Answer:The student should be wearing a lab coat or maybe an apron to prevent chemicals from spilling or exploding onto their clothes, I do recommend a lab coat better though because it can protect your skin better. Next, make sure while messing with chemicals you are always wearing goggles, if you are not wearing them there is a chance that after touching chemicals you could touch your eyes. And that brings me to washing your hands straight away after messing with chemicals. You could also wear gloves and just take them off when you're done but if you don't have clean hands afterward you could always put the chemicals all over your skin. But in case you do touch your eyes there is always an emergency eyewash station somewhere in the lab room. And if you are to get Chemicals on your skin, in your hair, on your clothes, or to be on fire, there shall be a shower somewhere to get rid of that. But if you read the instructions or listen closely to the teacher you shall have no problem.

Explanation:

I kinda got off topic