MATHEMATICS HIGH SCHOOL

What is an equation in slope intercept form for the line perpendicular to y = - 2x + 5that contains (-8, 1)?
1
A.O
y - 8 = 2 (x + 1)
B. O y=-2x - 1
C.O. 1
=
0:0 x = žy + 14

Answers

Answer 1
Answer:

Answer:

\displaystyle y =(1)/(2)x+5

Step-by-step explanation:

Equation of the line

The slope-intercept form of a line is given by:

y=mx+b

Being:

m = the slope of the line

b = the y-intercept

We can also use the point-slope form of the line:

y - k=m(x-h)

Being:

(h,k) = A point that belongs to the line

Two lines of slopes m1 and m2 are perpendicular if:

m_1.m_2=-1

We are given the line:

y=-2x+5

Whose slope is m1=-2

Thus, the perpendicular line has a slope of:

\displaystyle m_2=-(1)/(m_1)

\displaystyle m_2=-(1)/(-2)

\displaystyle m_2=(1)/(2)

The required line contains the point (-8,1), thus the equation is:

\displaystyle y - 1=(1)/(2)(x+8)

Removing the parentheses:

\displaystyle y - 1=(1)/(2)x+(1)/(2)\cdot 8

Adding 1:

\displaystyle y =(1)/(2)x+(1)/(2)\cdot 8+1

Operating:

\displaystyle y =(1)/(2)x+4+1

\mathbf{\displaystyle y =(1)/(2)x+5}

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6 can you help me I don't have very much time it's already missing

How do I solve this -4y+x=-27

Answers

First you have to know what a "solution" is.

The 'solution' is a set of 2 numbers which, if you put them into the equation
in place of 'x' and 'y', make the equation a true statement. 

There are an infinite number of possible pairs of numbers that can do that. 
Here are a few:

x = 0, y = 6.75 
x = 1, y = 7
x = 2, y = 7.25
x = 3, y = 7.5
x = 4, y = 7.75
x = 10, y = 9.25
x= 100, y = 31.75
x= -50, y = -5.75

When you graph this equation, the graph is a straight line without any ends.
Every point on the line is a solution to the equation, and you know how many
points there are on a line without ends . . . . .



According x variable;

-4y+x=-27\n \n \boxed{x=4y+27}

According y variable:

-4y+x=-27\n \n -4y=-27-x\n \n \boxed{y=(-27-x)/(-4)}

two nascar cars are racing around a 2 mile track. one car can complete a lap in 48 seconds, and the other car can complete one lap in 40 seconds. if they start side by side, after how much time will they be side by side again

Answers

First we need to find the speed of each car using the formula

s=(d)/(t), where s is the speed, d is the distance and t is time.

s=(2)/(48)=0.0417 miles/s

s=(2)/(40) = 0.05miles/s

Since they are moving in the same direction we subtract the speeds to obtain relative velocity, V_r

V_r = 0.05-0.0417= 0.0083 miles/s, then

t=(2)/(0.0083)= 240s.  This is the time it takes for the fastest car to complete an extra lap relative to the slower car.

If the nth term of a sequence is 7n-1 what is the 6th term?

Answers

To find the 6th term in the sequence whose nth term is represented by the formula 7n-1, substitute 6 in place of n into the formula. This gives 7*6 - 1, which equals 41.

The question is: If the nth term of a sequence is 7n-1, what is the 6th term?

In order to find this, we can substitute 6 into the formula for the nth term, in place of n.

Following the formula, we get 7n-1, replace n with 6, hence, the formula looks like 7*6 - 1.

Therefore, we get 42 - 1 = 41. Hence, the 6th term of the sequence is 41.

For more such questions on sequence, click on:

brainly.com/question/36944481

#SPJ2
The only thing you should do is to put 6 for n so you will have:
7(6) -1 = 42 - 1 = 41 :)))
I hope this is helpful
have a nice day

Which of the following are solutions to the equation below?check all that apply. x^2+6x+9=6
A. x=3+√6
B. x=3-√6
C. x=3
D. x=0
E. x=-3+√6
F. x= -3-√6

Answers

make it equal to zero
minus 6 from both sides
x^2+6x+3=0
quadratic formula
x=\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}


x=\frac{-6+/- \sqrt{6^(2)-4(1)(3)} }{2(1)}
x=(-6+/- √(36-12) )/(2)
x=(-6+/- √(24) )/(2)
x=(-6+/- 2√(6) )/(2)
x=-3+/- √(6)


E and F are answer

-6x + 7y = 9
2x - 2y = 4

Answers

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How far from zero would you move on the x-axis to reach the point (10,8)

Answers

Answer:

You would move 10 units to the right from zero on the x-axis

Answer:

10 spaces to the right to get to 10 and up 8 to get to 8
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